GED Math : Geometry and Graphs

Study concepts, example questions & explanations for GED Math

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Example Questions

Example Question #2 : Central Angles And Arcs

Sector

Note: Figure NOT drawn to scale.

Refer to the above diagram.

The area of the shaded sector is \(\displaystyle 24 \pi\). The area of the white sector is \(\displaystyle 40 \pi\).

What is the length of arc \(\displaystyle \widehat{MN}\) ?

Possible Answers:

\(\displaystyle 4 \pi\)

\(\displaystyle 10 \pi\)

\(\displaystyle 8 \pi\)

\(\displaystyle 6 \pi\)

Correct answer:

\(\displaystyle 6 \pi\)

Explanation:

The area of the circle is the sum of the areas of the sectors, which is

\(\displaystyle A = 24 \pi + 40 \pi = 64 \pi\).

The degree measure of the arc of the shaded sector is

\(\displaystyle \frac{24 \pi}{64 \pi} \times 360 ^{\circ } = 135 ^{\circ }\).

 

The radius can be found by solving for \(\displaystyle r\) and substituting \(\displaystyle A = 64 \pi\) in the area formula:

\(\displaystyle A = \pi r^{2}\)

\(\displaystyle 64 \pi = \pi r^{2}\)

\(\displaystyle r^{2} = 64\)

\(\displaystyle r = 8\)

 

The length of arc \(\displaystyle \widehat{MN}\) is 

\(\displaystyle \frac{135}{360} \cdot 2 \pi r = \frac{135}{360} \cdot 2 \cdot 8 \pi = 6\pi\).

Example Question #3 : Central Angles And Arcs

Circle

What percent of the above circle has not been shaded in?

Possible Answers:

\(\displaystyle 77\frac{7}{9 } \%\)

\(\displaystyle 80 \%\)

\(\displaystyle 75 \%\)

\(\displaystyle 87\frac{1}{2} \%\)

Correct answer:

\(\displaystyle 77\frac{7}{9 } \%\)

Explanation:

There are a total of 360 degrees to a complete circle. The shaded sector has degree measure \(\displaystyle 80^{\circ }\), so the unshaded sector has degree measure

\(\displaystyle 360 ^{\circ }- 80^{\circ }= 2 80^{\circ }\)

Also, a sector of \(\displaystyle N^{\circ }\) is \(\displaystyle \frac{N}{360} \times 100 \%\) of the circle, so, setting \(\displaystyle N = 280\), we find that the unshaded sector is 

\(\displaystyle \frac{280}{360} \times 100 \%\)

\(\displaystyle = \frac{28,000}{360} \%\)

of the circle. This reduces to

\(\displaystyle \frac{28,000\div 40 }{360 \div 40 } \%\)

\(\displaystyle =\frac{700 }{9 } \%\)

\(\displaystyle =77\frac{7}{9 } \%\),

the correct percentage.

Example Question #1 : Central Angles And Arcs

Circle

What percent of the above circle has been shaded?

Possible Answers:

\(\displaystyle 69\frac{4}{9} \%\)

\(\displaystyle 58\frac{1}{3} \%\)

\(\displaystyle 66\frac{2}{3} \%\)

\(\displaystyle 61\frac{1}{9} \%\)

Correct answer:

\(\displaystyle 61\frac{1}{9} \%\)

Explanation:

There are a total of \(\displaystyle 360^{\circ }\) in a circle. The unshaded portion of the circle represents a \(\displaystyle 140^{\circ }\) sector, so the shaded portion represents a sector of measure

\(\displaystyle 360^{\circ } - 140^{\circ } = 220 ^{\circ }\).

This sector represents 

\(\displaystyle \frac{ 220 ^{\circ }}{360^{\circ } } \times 100 \%\)

\(\displaystyle = \frac{ 22000}{360 } \%\)

\(\displaystyle = \frac{ 22000 \div 40 }{360 \div 40 } \%\)

\(\displaystyle = \frac{ 550 }{9 } \%\)

\(\displaystyle = 61\frac{1}{9} \%\)

of the circle.

Example Question #2 : Central Angles And Arcs

What percentage of a circle is covered by a sector with a central angle of \(\displaystyle 240^{\circ}\)?

Possible Answers:

\(\displaystyle 66.67 \%\)

\(\displaystyle 50 \%\)

\(\displaystyle 87.5\%\)

Not enough information to determine.

Correct answer:

\(\displaystyle 66.67 \%\)

Explanation:

What percentage of a circle is covered by a sector with a central angle of \(\displaystyle 240^{\circ}\)?

To find the percentage of a circle from the central angle, we need to use the following formula:

\(\displaystyle \%=\frac{\theta}{360^{\circ}}*100\)

Where theta is our central angle.

Plug in our given degree measurement and simplify.

 

\(\displaystyle \%=\frac{240^{\circ}}{360^{\circ}}*100=66.67 \%\)

So, our answer is  66.67%

Example Question #2 : Central Angles And Arcs

Find the length of the minor arc \(\displaystyle AB\) if the circle has a circumference of \(\displaystyle 81\pi\).

1

Possible Answers:

\(\displaystyle 72\pi\)

\(\displaystyle 18\pi\)

\(\displaystyle 9\pi\)

\(\displaystyle 3\pi\)

Correct answer:

\(\displaystyle 9\pi\)

Explanation:

Recall that the length of an arc is a proportion of the circumference, just like how the measure of a central angle is a proportion of the total number of degrees in a circle.

Thus, we can write the following equation to solve for arc length.

\(\displaystyle \text{Arc length}=\frac{\text{central angle}}{360}(\text{circumference})\)

Plug in the given central angle and circumference to find the length of the minor arc \(\displaystyle AB\).

\(\displaystyle \text{Arc length}=\frac{40}{360}(81\pi)=9\pi\)

Example Question #3 : Central Angles And Arcs

A circle has area \(\displaystyle 81 \pi\). Give the length of a \(\displaystyle 90 ^{\circ }\) arc of the circle. 

Possible Answers:

\(\displaystyle \frac{9}{4} \pi\)

\(\displaystyle \frac{81}{4} \pi\)

\(\displaystyle \frac{9}{2} \pi\)

\(\displaystyle \frac{81}{16} \pi\)

Correct answer:

\(\displaystyle \frac{9}{2} \pi\)

Explanation:

The radius \(\displaystyle r\) of a circle, given its area \(\displaystyle A\), can be found using the formula 

\(\displaystyle A = \pi r^{2}\)

Set \(\displaystyle A= 81 \pi\):

\(\displaystyle \pi r^{2} = 81 \pi\)

Find \(\displaystyle r\) by dividing both sides by \(\displaystyle \pi\) and then taking the square root of both sides:

\(\displaystyle \pi r^{2} \div \pi = 81 \pi \div \pi\)

\(\displaystyle r^{2} = 81\)

\(\displaystyle r = \sqrt{81} = 9\)

The circumference of this circle is found using the formula

\(\displaystyle C = 2 \pi r\):

\(\displaystyle C = 2 \pi (9)\)

\(\displaystyle C= 18 \pi\)

\(\displaystyle 90 ^{\circ }\) arc of the circle is one fourth of the circle, so the length of the arc is 

\(\displaystyle L = \frac{1}{4}C\)

\(\displaystyle = \frac{1}{4} \cdot 18 \pi\)

\(\displaystyle = \frac{9}{2} \pi\)

Example Question #3 : Central Angles And Arcs

If a sector covers \(\displaystyle \frac{4}{5}\) of the area of a given circle, what is the measure of that sector's central angle?

Possible Answers:

\(\displaystyle 288^{\circ}\)

\(\displaystyle 144^{\circ}\)

Not enough information given.

\(\displaystyle 728^{\circ}\)

Correct answer:

\(\displaystyle 288^{\circ}\)

Explanation:

If a sector covers \(\displaystyle \frac{4}{5}\) of the area of a given circle, what is the measure of that sector's central angle?

 

While this problem may seem to not have enough information to solve, we actually have everything we need.

To find the measure of a central angle, we don't need to know the actual area of the sector or the circle. Instead, we just need to know what fraction of the circle we are dealing with. In this case, we are told that the sector represents four fifths of the circle. 

All circles have 360 degrees, so if our sector is four fifths of that, we can find the answer via the following.

\(\displaystyle \measuredangle =\frac{4}{5}(360^{\circ})=288^{\circ}\)

So our answer is:

\(\displaystyle 288^{\circ}\)

Example Question #2 : Central Angles And Arcs

Sector

Figure is not drawn to scale.

What percent of the  circle has not been shaded?

Possible Answers:

\(\displaystyle 75 \%\)

\(\displaystyle 72 \%\)

\(\displaystyle 66\frac{2}{3} \%\)

\(\displaystyle 60 \%\)

Correct answer:

\(\displaystyle 60 \%\)

Explanation:

The total number of degrees in a circle is \(\displaystyle 360^{\circ }\), so the shaded sector represents \(\displaystyle \frac{144^{\circ }}{360^{\circ }}\) of the circle. In terms of percent, this is 

\(\displaystyle \frac{144^{\circ }}{360^{\circ }} \times 100 \% = \frac{14,400^{\circ }}{360^{\circ }} \%= 40\%\).

The shaded sector is 40% if the circle, so the unshaded sector is \(\displaystyle 100 \% - 40\% = 60\%\) of the circle.

Example Question #1 : Perimeter And Sides Of Triangles

If \(\displaystyle \Delta MNO \cong \Delta PQR\), then which segment is congruent to \(\displaystyle \overline{NO}\) ?

Possible Answers:

\(\displaystyle \overline{RP}\)

\(\displaystyle \overline{RQ}\)

\(\displaystyle \overline{MO}\)

\(\displaystyle \overline{NQ}\)

Correct answer:

\(\displaystyle \overline{RQ}\)

Explanation:

A congruency statement about two triangles implies nothing about the relationship between two sides of the same triangle, so we can eliminate \(\displaystyle \overline{MO}\). Also, the length of a segment with endpoints on two different  triangles depends on their positioning, not their congruence, so we can eliminate \(\displaystyle \overline{NQ}\).

Since \(\displaystyle N\) and \(\displaystyle O\) are in the same positions in the name of the first triangle as \(\displaystyle Q\) and \(\displaystyle R\)\(\displaystyle \overline{NO}\) and \(\displaystyle \overline{QR}\) are corresponding sides of congruent triangles, and 

\(\displaystyle \overline{NO} \cong \overline{QR}\)

Since the letters of the name of a segment are interchangeable, this statement can be rewritten as

\(\displaystyle \overline{NO} \cong \overline{RQ}\),

making \(\displaystyle \overline{RQ}\) the correct choice.

Example Question #1 : Perimeter And Sides Of Triangles

A triangle has sides of length 36 inches, 3 feet, and one yard. Choose the statement that most accurately describes this triangle.

Possible Answers:

This triangle is isosceles but not equilateral.

This triangle is equilateral.

This triangle is scalene.

More information is needed to answer this question.

Correct answer:

This triangle is equilateral.

Explanation:

One yard is equal to three feet, or thirty-six inches. The three given sidelengths are equal to one another, making this an equilateral triangle.

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