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GED Math : Geometry and Graphs

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4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Geometry And Graphs

Determine the diameter if the radius is $\frac{2}{3}x-4$ $\displaystyle \frac{2}{3}x-4$ .

Possible Answers:

$\frac{4}{3}x-8$ $\displaystyle \frac{4}{3}x-8$

$\frac{1}{3}x-2$ $\displaystyle \frac{1}{3}x-2$

$\frac{4}{3}x-2$ $\displaystyle \frac{4}{3}x-2$

$\frac{1}{3}x-8$ $\displaystyle \frac{1}{3}x-8$

$\textup{The answer is not given.}$

Correct answer:

$\frac{4}{3}x-8$ $\displaystyle \frac{4}{3}x-8$

Explanation:

The diameter is double the radius.

$2(\frac{2}{3}x-4) = \frac{4}{3}x-8$ $\displaystyle 2(\frac{2}{3}x-4) = \frac{4}{3}x-8$

The answer is: $\frac{4}{3}x-8$ $\displaystyle \frac{4}{3}x-8$

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Example Question #12 : Geometry And Graphs

Determine the diameter of a circle if the radius is $2\frac{1}{3}$ $\displaystyle 2\frac{1}{3}$ .

Possible Answers:

$\frac{25}{3}$ $\displaystyle \frac{25}{3}$

$4\frac{1}{6}$ $\displaystyle 4\frac{1}{6}$

$\frac{13}{3}$ $\displaystyle \frac{13}{3}$

$\frac{7}{2}$ $\displaystyle \frac{7}{2}$

$\frac{14}{3}$ $\displaystyle \frac{14}{3}$

Correct answer:

$\frac{14}{3}$ $\displaystyle \frac{14}{3}$

Explanation:

The diameter is twice the radius.

D= 2r $\displaystyle D= 2r$

Convert the mixed fraction to an improper fraction.

$D= 2(\frac{7}{3}) = \frac{14}{3}$ $\displaystyle D= 2(\frac{7}{3}) = \frac{14}{3}$

The answer is: $\frac{14}{3}$ $\displaystyle \frac{14}{3}$

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Example Question #12 : Geometry And Graphs

Determine the diameter if the radius is $\frac{1}{8}$ $\displaystyle \frac{1}{8}$ .

Possible Answers:

$\frac{1}{16}$ $\displaystyle \frac{1}{16}$

$\frac{1}{32}$ $\displaystyle \frac{1}{32}$

$\frac{1}{64}$ $\displaystyle \frac{1}{64}$

$\frac{17}{8}$ $\displaystyle \frac{17}{8}$

$\frac{1}{4}$ $\displaystyle \frac{1}{4}$

Correct answer:

$\frac{1}{4}$ $\displaystyle \frac{1}{4}$

Explanation:

The diameter is twice the radius.

Multiply the radius by two.

$\frac{1}{8} (2) = \frac{2}{8} = \frac{1}{4}$ $\displaystyle \frac{1}{8} (2) = \frac{2}{8} = \frac{1}{4}$

The answer is: $\frac{1}{4}$ $\displaystyle \frac{1}{4}$

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Example Question #13 : Geometry And Graphs

What is the radius if the diameter of a circle is $\frac{\sqrt3}{3}$ $\displaystyle \frac{\sqrt3}{3}$ ?

Possible Answers:

$\frac{\sqrt{3}}{6}$ $\displaystyle \frac{\sqrt{3}}{6}$

$\frac{2\sqrt3}{3}$ $\displaystyle \frac{2\sqrt3}{3}$

$\frac{\sqrt6}{3}$ $\displaystyle \frac{\sqrt6}{3}$

$\frac{\sqrt6}{6}$ $\displaystyle \frac{\sqrt6}{6}$

$\frac{3\sqrt{3}}{2}$ $\displaystyle \frac{3\sqrt{3}}{2}$

Correct answer:

$\frac{\sqrt{3}}{6}$ $\displaystyle \frac{\sqrt{3}}{6}$

Explanation:

The radius is half the diameter of a circle.

$r=\frac{d}{2}$ $\displaystyle r=\frac{d}{2}$

This is also similar to multiply diameter by one-half.

$\frac{\sqrt3}{3} \times \frac{1}{2} = \frac{\sqrt{3}}{6}$ $\displaystyle \frac{\sqrt3}{3} \times \frac{1}{2} = \frac{\sqrt{3}}{6}$

The answer is: $\frac{\sqrt{3}}{6}$ $\displaystyle \frac{\sqrt{3}}{6}$

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Example Question #13 : Geometry And Graphs

What is the radius with a diameter of $\frac{\sqrt3}{2}$ $\displaystyle \frac{\sqrt3}{2}$ ?

Possible Answers:

$\sqrt3$ $\displaystyle \sqrt3$

$\frac{\sqrt3}{6}$ $\displaystyle \frac{\sqrt3}{6}$

$\frac{\sqrt3}{4}$ $\displaystyle \frac{\sqrt3}{4}$

$\sqrt6$ $\displaystyle \sqrt6$

$\frac{\sqrt6}{4}$ $\displaystyle \frac{\sqrt6}{4}$

Correct answer:

$\frac{\sqrt3}{4}$ $\displaystyle \frac{\sqrt3}{4}$

Explanation:

The radius is half the diameter.

Multiply the diameter by one-half.

$\frac{\sqrt3}{2} \cdot \frac{1}{2} = \frac{\sqrt3}{4}$ $\displaystyle \frac{\sqrt3}{2} \cdot \frac{1}{2} = \frac{\sqrt3}{4}$

The answer is: $\frac{\sqrt3}{4}$ $\displaystyle \frac{\sqrt3}{4}$

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Example Question #14 : Radius And Diameter

Find the radius of a circle with an area of $8\pi$ $\displaystyle 8\pi$ .

Possible Answers:

$\displaystyle 4$

$8\sqrt2$ $\displaystyle 8\sqrt2$

$2\sqrt2$ $\displaystyle 2\sqrt2$

$\sqrt2$ $\displaystyle \sqrt2$

$4\sqrt2$ $\displaystyle 4\sqrt2$

Correct answer:

$2\sqrt2$ $\displaystyle 2\sqrt2$

Explanation:

Write the formula for the area of a circle.

$A = \pi r^2$ $\displaystyle A = \pi r^2$

Substitute the area.

$8\pi = \pi r^2$ $\displaystyle 8\pi = \pi r^2$

Divide by pi on both sides.

$\frac{8\pi }{\pi}=\frac{ \pi r^2}{\pi}$ $\displaystyle \frac{8\pi }{\pi}=\frac{ \pi r^2}{\pi}$

$\displaystyle r^2 = 8$

Square root both sides.

$\sqrt{r^2 }= \sqrt{8}$ $\displaystyle \sqrt{r^2 }= \sqrt{8}$

$r= \sqrt8 = 2\sqrt2$ $\displaystyle r= \sqrt8 = 2\sqrt2$

The answer is: $2\sqrt2$ $\displaystyle 2\sqrt2$

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Example Question #14 : Geometry And Graphs

Find the value of the diameter if the radius is $5\pi-2$ $\displaystyle 5\pi-2$ .

Possible Answers:

$5\pi -4$ $\displaystyle 5\pi -4$

$10\pi -4$ $\displaystyle 10\pi -4$

$10\pi -2$ $\displaystyle 10\pi -2$

$5\pi +4$ $\displaystyle 5\pi +4$

$10\pi +4$ $\displaystyle 10\pi +4$

Correct answer:

$10\pi -4$ $\displaystyle 10\pi -4$

Explanation:

The diameter is double the radius.

Multiply the quantity by two.

$2(5\pi-2) = 10\pi -4$ $\displaystyle 2(5\pi-2) = 10\pi -4$

The answer is: $10\pi -4$ $\displaystyle 10\pi -4$

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Example Question #15 : Geometry And Graphs

Determine the radius if the diameter is $\frac{\sqrt{2}}{3}$ $\displaystyle \frac{\sqrt{2}}{3}$ .

Possible Answers:

$\frac{1}{3}$ $\displaystyle \frac{1}{3}$

$\frac{\sqrt2}{2}$ $\displaystyle \frac{\sqrt2}{2}$

$\frac{\sqrt2}{6}$ $\displaystyle \frac{\sqrt2}{6}$

$\frac{2}{3}$ $\displaystyle \frac{2}{3}$

$2\sqrt2$ $\displaystyle 2\sqrt2$

Correct answer:

$\frac{\sqrt2}{6}$ $\displaystyle \frac{\sqrt2}{6}$

Explanation:

The radius is half the diameter.

Multiply the diameter by half.

$\frac{\sqrt{2}}{3} \cdot\frac{1}{2}$ $\displaystyle \frac{\sqrt{2}}{3} \cdot\frac{1}{2}$

The answer is: $\frac{\sqrt2}{6}$ $\displaystyle \frac{\sqrt2}{6}$

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Example Question #981 : Ged Math

Determine the radius of the circle if the diameter is $\frac{3\sqrt5}{7}$ $\displaystyle \frac{3\sqrt5}{7}$ .

Possible Answers:

$\frac{3\sqrt5}{14}$ $\displaystyle \frac{3\sqrt5}{14}$

$\textup{The answer is not given.}$

$\frac{6\sqrt5}{7}$ $\displaystyle \frac{6\sqrt5}{7}$

$\frac{3\sqrt{10}}{14}$ $\displaystyle \frac{3\sqrt{10}}{14}$

$\frac{3\sqrt{10}}{7}$ $\displaystyle \frac{3\sqrt{10}}{7}$

Correct answer:

$\frac{3\sqrt5}{14}$ $\displaystyle \frac{3\sqrt5}{14}$

Explanation:

The radius is half the diameter. To find the radius, multiply the diameter by half.

$\frac{3\sqrt5}{7} \cdot \frac{1}{2} = \frac{3\sqrt5}{14}$ $\displaystyle \frac{3\sqrt5}{7} \cdot \frac{1}{2} = \frac{3\sqrt5}{14}$

The answer is: $\frac{3\sqrt5}{14}$ $\displaystyle \frac{3\sqrt5}{14}$

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Example Question #16 : Geometry And Graphs

Determine the radius of the circle if the diameter of a circle is $\frac{3}{50}$ $\displaystyle \frac{3}{50}$ .

Possible Answers:

$\frac{3}{100}$ $\displaystyle \frac{3}{100}$

$\frac{9}{100}$ $\displaystyle \frac{9}{100}$

$\frac{3}{50}$ $\displaystyle \frac{3}{50}$

$\frac{9}{50}$ $\displaystyle \frac{9}{50}$

$\frac{3}{25}$ $\displaystyle \frac{3}{25}$

Correct answer:

$\frac{3}{100}$ $\displaystyle \frac{3}{100}$

Explanation:

The radius is half the diameter.

Multiply the diameter by one-half.

$\frac{3}{50} \cdot \frac{1}{2} = \frac{3}{100}$ $\displaystyle \frac{3}{50} \cdot \frac{1}{2} = \frac{3}{100}$

The answer is: $\frac{3}{100}$ $\displaystyle \frac{3}{100}$

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GED Math : Geometry and Graphs

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #11 : Geometry And Graphs

Example Question #12 : Geometry And Graphs

Example Question #12 : Geometry And Graphs

Example Question #13 : Geometry And Graphs

Example Question #13 : Geometry And Graphs

Example Question #14 : Radius And Diameter

Example Question #14 : Geometry And Graphs

Example Question #15 : Geometry And Graphs

Example Question #981 : Ged Math

Example Question #16 : Geometry And Graphs

All GED Math Resources

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