Call Now to Set Up Tutoring:

(888) 888-0446

Common Core: High School - Geometry : Prove Line and Angle Theorems: CCSS.Math.Content.HSG-CO.C.9

Study concepts, example questions & explanations for Common Core: High School - Geometry

Create An Account

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $50^{\circ}$ ?

Possible Answers:

$130^{\circ}$

$100^{\circ}$

$40^{\circ}$

$140^{\circ}$

$50^{\circ}$

Correct answer:

$140^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $50^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $50^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 50 \\y = 40$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for $\uptext{x}$ .

$\\180 = y + 40 \\y = 140$

So the answer is $140^{\circ}$ .

Report an Error

Example Question #71 : Congruence

What is the supplement of the complement of $81^{\circ}$ ?

Possible Answers:

$162^{\circ}$

$81^{\circ}$

$171^{\circ}$

$99^{\circ}$

$9^{\circ}$

Correct answer:

$171^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $81^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $81^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 81 \\y = 9$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 9 \\y = 171$

So the answer is $171^{\circ}$ .

Report an Error

Example Question #74 : Congruence

What is the supplement of the complement of $40^{\circ}$ ?

Possible Answers:

$80^{\circ}$

$140^{\circ}$

$130^{\circ}$

$50^{\circ}$

$40^{\circ}$

Correct answer:

$130^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $40^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $40^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 40 \\y = 50$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 50 \\y = 130$

So the answer is $130^{\circ}$

Report an Error

Example Question #3 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $66^{\circ}$ ?

Possible Answers:

$156^{\circ}$

$66^{\circ}$

$114^{\circ}$

$24^{\circ}$

$132^{\circ}$

Correct answer:

$156^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $66^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $66^{\circ}$ we can substitute it for $\uptext{x}$ , and solve for $\uptext{y}$ .

$\\90 = y + 66 \\y = 24$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 24 \\y = 156$

So the answer is $156^{\circ}$

Report an Error

Example Question #4 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $71^{\circ}$ ?

Possible Answers:

$109^{\circ}$

$19^{\circ}$

$161^{\circ}$

$142^{\circ}$

$71^{\circ}$

Correct answer:

$161^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $71^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $71^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 71 \\y = 19$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 19 \\y = 161$

So the answer is $161^{\circ}$

Report an Error

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $65^{\circ}$ ?

Possible Answers:

$155^{\circ}$

$130^{\circ}$

$65^{\circ}$

$25^{\circ}$

$115^{\circ}$

Correct answer:

$155^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $65^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $65^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 65 \\y = 25$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for

$\\180 = y + 25 \\y = 155$

So the answer is $155^{\circ}$

Report an Error

Example Question #5 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $45^{\circ}$ ?

Possible Answers:

$135^{\circ}$

$90^{\circ}$

$45^{\circ}$

Correct answer:

$135^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $45^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $45^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 45 \\y = 45$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for

$\\180 = y + 45 \\y = 135$

So the answer is $135^{\circ}$ .

Report an Error

Example Question #8 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $76^{\circ}$ ?

Possible Answers:

$76^{\circ}$

$104^{\circ}$

$152^{\circ}$

$14^{\circ}$

$166^{\circ}$

Correct answer:

$166^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $76^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $76^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 76 \\y = 14$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 14 \\y = 166$

So the answer is $166^{\circ}$ .

Report an Error

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $48^{\circ}$ ?

Possible Answers:

$42^{\circ}$

$138^{\circ}$

$48^{\circ}$

$132^{\circ}$

$96^{\circ}$

Correct answer:

$138^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $48^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $48^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 48 \\y = 42$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 42 \\y = 138$

So the answer is $138^{\circ}$

Report an Error

Example Question #7 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $4^{\circ}$ ?

Possible Answers:

$94^{\circ}$

$4^{\circ}$

$86^{\circ}$

$176^{\circ}$

$8^{\circ}$

Correct answer:

$94^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $4^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $4^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 4 \\y = 86$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 86 \\y = 94$

So the answer is $94^{\circ}$

Report an Error

View Tutors

Shubham
Certified Tutor

Jaypee University of Information and Technology, Bachelor of Technology, Computer Science.

View Tutors

Lauren
Certified Tutor

Ohio University-Eastern Campus, Bachelor in Arts, Early Childhood Education.

View Tutors

Makayla
Certified Tutor

Highline Community College, Associate in Arts, Arts, General. Washington State University, Bachelor of Science, International...

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

SAT Tutors in New York City, Physics Tutors in San Diego, Physics Tutors in Phoenix, French Tutors in Denver, Statistics Tutors in San Diego, Algebra Tutors in Miami, Biology Tutors in Atlanta, SAT Tutors in Atlanta, LSAT Tutors in Boston, Calculus Tutors in Houston

Popular Courses & Classes

GRE Courses & Classes in San Diego, GRE Courses & Classes in Chicago, SSAT Courses & Classes in New York City, SAT Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Los Angeles, ACT Courses & Classes in Denver, Spanish Courses & Classes in San Diego, MCAT Courses & Classes in Dallas Fort Worth, Spanish Courses & Classes in Los Angeles, SSAT Courses & Classes in Chicago

Popular Test Prep

SSAT Test Prep in New York City, ISEE Test Prep in Houston, SAT Test Prep in Boston, GRE Test Prep in San Diego, SSAT Test Prep in Boston, LSAT Test Prep in Chicago, MCAT Test Prep in Houston, MCAT Test Prep in Denver, SAT Test Prep in Washington DC, ACT Test Prep in New York City

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Common Core: High School - Geometry : Prove Line and Angle Theorems: CCSS.Math.Content.HSG-CO.C.9

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #1 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #71 : Congruence

Example Question #74 : Congruence

Example Question #3 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #4 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #5 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #8 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #7 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

All Common Core: High School - Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: