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Common Core: High School - Geometry : Geometric Measurement & Dimension

Study concepts, example questions & explanations for Common Core: High School - Geometry

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Find the volume of a sphere with radius 224 . Round your answer to the nearest hundredth.

Possible Answers:

23539794.58

11239424

47079589.16

14985898.67

7492949.33

Correct answer:

47079589.16

Explanation:

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$V = \frac{4 \pi}{3} r^{3}$

We simply plug in 224 for $\uptext{r}$ .

$V=\frac{4}{3}\cdot\pi\cdot ( 224 )^3$

V= 47079589.15864107

Now we round our answer to the nearest hundredth.

V= 47079589.16

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Example Question #4 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Find the volume of a hemisphere with radius 163 . Round your answer to the nearest hundredth.

Possible Answers:

4330747

18140590.61

2887164.67

5774329.33

9070295.31

Correct answer:

9070295.31

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in 163 for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 163 )^3$

V= 9070295.306504022

Now we round our answer to the nearest hundredth.

V= 9070295.31

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Example Question #1 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Find the volume of a sphere with radius 409 . Round your answer to the nearest hundredth.

Possible Answers:

45611952.67

143294175.41

91223905.33

68417929

286588350.83

Correct answer:

286588350.83

Explanation:

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$V = \frac{4 \pi}{3} r^{3}$
We simply plug in 409 for $\uptext{r}$ .

$V=\frac{4}{3}\cdot\pi\cdot ( 409 )^3$

V= 286588350.82697076

Now we round our answer to the nearest hundredth.

V= 286588350.83

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Example Question #5 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Find the volume of a hemisphere with radius 464 . Round your answer to the nearest hundredth.

Possible Answers:

99897344

418449016.03

209224508.02

133196458.67

66598229.33

Correct answer:

209224508.02

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in 464 for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 464 )^3$

V= 209224508.01568824

Now we round our answer to the nearest hundredth.

V= 209224508.02

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Example Question #31 : Geometric Measurement & Dimension

Find the volume of a hemisphere with radius 341 . Round your answer to the nearest hundredth.

Possible Answers:

26434547.33

39651821

166093159.41

83046579.7

52869094.67

Correct answer:

83046579.7

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in 341 for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 341 )^3$

V= 83046579.70337164

Now we round our answer to the nearest hundredth.

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Example Question #32 : Geometric Measurement & Dimension

Find the volume of a hemisphere with radius . Round your answer to the nearest hundredth.

Possible Answers:

718.38

1436.76

457.33

228.67

343

Correct answer:

718.38

Explanation:

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$V = \frac{2 \pi}{3} r^{3}$

We simply plug in for $\uptext{r}$ .

$V=\frac{2}{3}\cdot\pi\cdot ( 7 )^3$

V= 718.3775201208659

Now we round our answer to the nearest hundredth.

V= 718.38

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Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = \frac{2048}{3}$

$V = 512 \pi$

$V = \frac{2048 \pi}{3}$

V = 512

$V = \frac{256 \pi}{3}$

Correct answer:

$V = \frac{2048 \pi}{3}$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = \frac{2048 \pi}{3}$

Thus the volume is, $\frac{2048 \pi}{3}$

Here is a picture representation of the sphere.

Plot1

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Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = 108 \pi$

V = 729

$V = 972 \pi$

V = 972

$V = 729 \pi$

Correct answer:

$V = 972 \pi$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = 972 \pi$

Thus the volume is, $972 \pi$

Here is a picture representation of the sphere.

Plot2

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Example Question #3 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

$V = 768 \pi$

V = 18432

V = 13824

$V = 18432 \pi$

$V = 13824 \pi$

Correct answer:

$V = 18432 \pi$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = 18432 \pi$

Thus the volume is, $18432 \pi$

Here is a picture representation of the sphere.

Plot6

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Example Question #4 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Find the volume of a sphere, where the radius is .

Possible Answers:

V = 12167

$V = 12167 \pi$

$V = \frac{48668 \pi}{3}$

$V = \frac{2116 \pi}{3}$

$V = \frac{48668}{3}$

Correct answer:

$V = \frac{48668 \pi}{3}$

Explanation:

Before we find the volume of a sphere, we need to recall the equation.

$V = \frac{4 \pi}{3} r^{3}$

Since we are given the radius ( $\uptext{r}$ ), we can plug it into the equation.

$V = \frac{48668 \pi}{3}$

Thus the volume is, $\frac{48668 \pi}{3}$

Here is a picture representation of the sphere.

Plot12

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: High School - Geometry : Geometric Measurement & Dimension

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #3 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Example Question #4 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Example Question #1 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Example Question #5 : Cavalieri's Principle: Ccss.Math.Content.Hsg Gmd.A.2

Example Question #31 : Geometric Measurement & Dimension

Example Question #32 : Geometric Measurement & Dimension

Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #1 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #3 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

Example Question #4 : Cylinders, Pyramids, Cones, And Spheres Volume Formulas: Ccss.Math.Content.Hsg Gmd.A.3

All Common Core: High School - Geometry Resources

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