In order to find the volume, we need to remember the equation that involves both surface area, and volume.

$\displaystyle SA = 6 l$

Where $\displaystyle SA$ is surface area and $\displaystyle l$ is the length.

Now we plug 897 for $\displaystyle SA$ and solve for $\displaystyle l$.

$\displaystyle \\897 = 6 l \\l = 149.5$

Now since we have the width, we can plug it into the volume formula, which is

$\displaystyle V = w^{3}$

Where $\displaystyle w$ is the width and$\displaystyle V$ volume.

Now plug in 149.5 for $\displaystyle w$.

$\displaystyle \\V = \left( 149.5 \right)^{3} \\V = 3341362.375$

So the final answer is.

$\displaystyle 3341362.38$

In order to find the volume, we need to remember the equation that involves both surface area, and volume.

$\displaystyle SA = 6 l$

Where $\displaystyle SA$ is surface area and $\displaystyle l$ is the length.

Now we plug 800 for $\displaystyle SA$ and solve for $\displaystyle l$.

$\displaystyle \\800 = 6 l \\l = 133.333333333333$

Now since we have the width, we can plug it into the volume formula, which is

$\displaystyle V = w^{3}$

Where w is the width and $\displaystyle V$ volume.

Now plug in 133.33333333333334 for $\displaystyle w$.

$\displaystyle \\V = \left( 133.33333333333334 \right)^{3} \\V = 2370370.37037037$

So the final answer is.

$\displaystyle 2370370.37$

In order to find the volume, we need to remember the equation that involves both surface area, and volume.

$\displaystyle SA = 6 l$

Where $\displaystyle SA$ is surface area and $\displaystyle l$ is the length.

Now we plug 738 for $\displaystyle SA$ and solve for $\displaystyle l$.

$\displaystyle \\738 = 6 l \\l = 123.0$

Now since we have the width, we can plug it into the volume formula, which is

$\displaystyle V = w^{3}$

Where $\displaystyle w$ is the width and $\displaystyle V$ volume.

Now plug in 123.0 for $\displaystyle w$.

$\displaystyle \\V = \left( 123.0 \right)^{3} \\V = 1860867.0$

So the final answer is.

$\displaystyle 1860867.0$

In order to find the volume, we need to remember the equation that involves both surface area, and volume.

$\displaystyle SA = 6 l$

Where $\displaystyle SA$ is surface area and $\displaystyle l$ is the length.

Now we plug 925 for $\displaystyle SA$ and solve for $\displaystyle l$.

$\displaystyle \\925 = 6 l \\l = 154.166666666667$

Now since we have the width, we can plug it into the volume formula, which is

$\displaystyle V = w^{3}$

Where $\displaystyle w$ is the width and $\displaystyle V$ volume.

Now plug in 154.16666666666666 for $\displaystyle w$.

$\displaystyle \\V = \left( 154.16666666666666 \right)^{3} \\V = 3664134.83796296$

So the final answer is.

$\displaystyle 3664134.84$

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$\displaystyle V = \frac{4 \pi}{3} r^{3}$

We simply plug in $\displaystyle 344$ for $\displaystyle \uptext{r}$.

$\displaystyle V=\frac{4}{3}\cdot\pi\cdot ( 344 )^3$

$\displaystyle V= 170515529.1197192$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 170515529.12$

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$\displaystyle V = \frac{4 \pi}{3} r^{3}$

We simply plug in $\displaystyle 399$ for $\displaystyle \uptext{r}$.

$\displaystyle V=\frac{4}{3}\cdot\pi\cdot ( 399 )^3$

$\displaystyle V= 266076976.16748706$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 266076976.17$

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$\displaystyle V = \frac{4 \pi}{3} r^{3}$

We simply plug in $\displaystyle 93$ for $\displaystyle \uptext{r}$.

$\displaystyle V=\frac{4}{3}\cdot\pi\cdot ( 93 )^3$

$\displaystyle V= 3369282.722751367$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 3369282.72$

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$\displaystyle V = \frac{2 \pi}{3} r^{3}$

We simply plug in $\displaystyle 495$ for $\displaystyle \uptext{r}$.

$\displaystyle V=\frac{2}{3}\cdot\pi\cdot ( 495 )^3$

$\displaystyle V= 254023684.18212688$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 254023684.18$

In order to find the volume of a sphere, we need to recall the volume of a sphere equation.

$\displaystyle V = \frac{4 \pi}{3} r^{3}$

We simply plug in $\displaystyle 188$ for $\displaystyle \uptext{r}$.
$\displaystyle V=\frac{4}{3}\cdot\pi\cdot ( 188 )^3$

$\displaystyle V= 27833136.987618394$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 27833136.99$

In order to find the volume of a hemisphere, we need to recall the volume of a hemisphere equation.

$\displaystyle V = \frac{2 \pi}{3} r^{3}$

We simply plug in $\displaystyle 347$ for $\displaystyle \uptext{r}$.

$\displaystyle V=\frac{2}{3}\cdot\pi\cdot ( 347 )^3$

$\displaystyle V= 87507854.8997696$

Now we round our answer to the nearest hundredth.

$\displaystyle V= 87507854.9$