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Common Core: 7th Grade Math : Develop and Compare Probability Models and Find Probabilities of Events: CCSS.Math.Content.7.SP.C.7

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Example Question #1 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

If John were to roll a die 900 times, roughly how many times would he roll a or a

Possible Answers:

200

300

100

Correct answer:

300

Explanation:

A die has sides, with each side displaying a number between 1-6 .

Let's first determine the probability of rolling a or a after John rolls the die a single time.

There is a total of sides on a die and we have one value of and one value of ; thus, our probability is:

$\frac{2}{6}$

This means that roughly $\frac{2}{6}$ of John's rolls will be a or a ; therefore, in order to calculate the probability we can multiply $\frac{2}{6}$ by 900 —the number of times John rolls the die.

$\frac{2}{6}\times\frac{900}{1}=\frac{1800}{6}=300$

If John rolls a die 900 times, then he will roll a or a roughly 300 times.

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Example Question #2 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

If John were to roll a die 120 times, roughly how many times would he roll a

Possible Answers:

200

100

Correct answer:

Explanation:

A die has sides, with each side displaying a number between 1-6 .

Let's first determine the probability of rolling a after John rolls the die a single time.

There is a total of sides on a die and only one value of on one side; thus, our probability is:

$\frac{1}{6}$

This means that roughly $\frac{1}{6}$ of John's rolls will be a ; therefore, in order to calculate the probability we can multiply $\frac{1}{6}$ by 120 —the number of times John rolls the die.

$\frac{1}{6}\times\frac{120}{1}=\frac{120}{6}=20$

If John rolls a die 120 times, then he will roll a roughly times.

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Example Question #3 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

If John were to roll a die $1\textup,200$ times, roughly how many times would he roll a

Possible Answers:

300

100

400

200

500

Correct answer:

200

Explanation:

A die has sides, with each side displaying a number between 1-6 .

Let's first determine the probability of rolling a after John rolls the die a single time.

There is a total of sides on a die and only one value of on one side; thus, our probability is:

$\frac{1}{6}$

This means that roughly $\frac{1}{6}$ of John's rolls will be a ; therefore, in order to calculate the probability we can multiply $\frac{1}{6}$ by $1\textup,200$ —the number of times John rolls the die.

$\frac{1}{6}\times\frac{1200}{1}=\frac{1200}{6}=200$

If John rolls a die $1\textup,200$ times, then he will roll a roughly 200 times.

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Example Question #4 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

The red queens are removed from a standard deck of fifty-two cards. What is the probability that a card randomly drawn from that modified deck will be a face card (jack, queen, king)?

Possible Answers:

$\frac{1}{5}$

$\frac{6}{25}$

$\frac{1}{3}$

$\frac{5}{26}$

$\frac{1}{4}$

Correct answer:

$\frac{1}{5}$

Explanation:

There are four cards of each rank in a standard deck; since three ranks - jacks, queens, kings - are considered face cards, this makes twelve face cards out of the fifty-two. But two of those face cards - two red queens - have been removed, so now there are ten face cards out of fifty. This makes the probability of a randomly drawn card being a face card

$\frac{10}{50} = \frac{1}{5}$ .

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Example Question #1 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Jamie rolled a normal 6-sided die. What is the probability of rolling a number greater than 4?

Possible Answers:

1/2

1/6

1/4

1/3

Correct answer:

1/3

Explanation:

Probability is determined by dividing the number of incidences of a specific outcome (in this case rolling greater than 4, or rolling a 5 or 6) by the total number of outcomes (there are 6 sides to the die).

$P=\frac{2}{6}=\frac{1}{3}$

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Example Question #511 : Data Analysis And Probability

What is the probability of drawing a diamond from a regular set of playing cards?

Possible Answers:

$\frac{1}{13}$

$\frac{1}{8}$

$\frac{1}{26}$

$\frac{1}{4}$

Correct answer:

$\frac{1}{4}$

Explanation:

Probability is determined by dividing the number of outcomes of a particular event by the total number of events. In a regular deck of playing cards, there are 52 cards and 13 diamonds.

$P=\frac{13}{52}=\frac{1}{4}$

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Example Question #7 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

What is the probability of drawing a red jack from a standard deck of playing cards?

Possible Answers:

$P=\frac{1}{26}$

$P=\frac{2}{13}$

$P=\frac{1}{13}$

$P=\frac{1}{52}$

Correct answer:

$P=\frac{1}{26}$

Explanation:

A standard deck contains cards including jacks, of which are red. Therefore, the probability is:

$P=\frac{2}{52}=\frac{1}{26}$

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Example Question #1 : Outcomes

There are 5 yellow pebbles, 12 orange pebbles, and 8 red pebbles. What is the probability of picking a red or yellow pebble?

Possible Answers:

$\frac{5}{25}$

$\frac{13}{24}$

$\frac{8}{25}$

$\frac{13}{25}$

$\frac{12}{25}$

Correct answer:

$\frac{13}{25}$

Explanation:

There are 13 yellow and red pebbles. There are 25 pebbles total. Therefor the probability of choosing a red or yellow pebble is $\frac{13}{25}$ .

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Example Question #1 : How To Find The Probability Of An Outcome

There are 6 red marbles, 4 purple marbles, and 9 green marbles in a bag. What is the probablility of randomly drawing a green marble?

Possible Answers:

$\frac{3}{4}$

$\frac{3}{7}$

$\frac{9}{19}$

$\frac{2}{3}$

Correct answer:

$\frac{9}{19}$

Explanation:

First we need to determine the total number of marbles in the bag:

$\dpi{100} 6+4+9=19\ marbles$

There are 9 green marbles, so the probability of drawing one of those 9 marbles out of 19 possible marbles is $\dpi{100} \frac{9}{19}$ .

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Example Question #1 : Outcomes

A bag contains $\small 2$ red marbles, $\small 7$ pink marbles, and $\small 6$ purple marbles. What is the probability of not choosing a purple marble?

Possible Answers:

$\small \frac{3}2$

$\small \frac{2}{5}$

$\small \frac{3}{5}$

$\small \frac{2}{3}$

Correct answer:

$\small \frac{3}{5}$

Explanation:

The probability (p) is equal to the number of a specific event (purple marbles) divided by the total number of events. The probability of NOT p (called q) is equal to $\small 1-q.$ In this example:

$\small P_{purple}=\frac{6}{2+7+6}=\frac{6}{15}=\frac{2}{5}$

$\small Q_{not\ purple}=1-\frac{2}{5}=\frac{3}{5}$

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Common Core: 7th Grade Math : Develop and Compare Probability Models and Find Probabilities of Events: CCSS.Math.Content.7.SP.C.7

Study concepts, example questions & explanations for Common Core: 7th Grade Math

All Common Core: 7th Grade Math Resources

Example Questions

Example Question #1 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #2 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #3 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #4 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #1 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #511 : Data Analysis And Probability

Example Question #7 : Develop And Compare Probability Models And Find Probabilities Of Events: Ccss.Math.Content.7.Sp.C.7

Example Question #1 : Outcomes

Example Question #1 : How To Find The Probability Of An Outcome

Example Question #1 : Outcomes

All Common Core: 7th Grade Math Resources

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