Common Core: 6th Grade Math : The Number System

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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Example Questions

Example Question #1612 : Grade 6

Shawn bought two coats at the jacket store for \displaystyle \$195.69.  He returned one of the two coats the next day and received \displaystyle \$84.20 back on his credit card.  How much did the other coat cost?

Possible Answers:

\displaystyle \$111.99

\displaystyle \$111.49

\displaystyle \$111.29

\displaystyle \$110.99

\displaystyle \$110.49

Correct answer:

\displaystyle \$111.49

Explanation:

In order to find the cost of the coat that Shawn kept you must subtract the amount of money that went back on his credit card from the total that he spent on the two coats.  

\displaystyle \$195.69-84.20= \$111.49

Example Question #1 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum \displaystyle 40+36 as the multiple of a sum of two whole numbers with no common factor. 

Possible Answers:

\displaystyle 3(10+9)

\displaystyle 9(10+4)

\displaystyle 10(4+9)

None of these

\displaystyle 4(10+9)

Correct answer:

\displaystyle 4(10+9)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 40+36

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=4

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 4(10+9)

Example Question #1 : Find Greatest Common Factor

Use the distributive property to express the sum \displaystyle 16+28 as the multiple of a sum of two whole numbers with no common factor. 

Possible Answers:

\displaystyle 7(4+7)

\displaystyle 4(4+7)

\displaystyle 7(4+4)

\displaystyle 4(4+4)

\displaystyle 5(4+7)

Correct answer:

\displaystyle 4(4+7)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 16+28

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=4

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 4(4+7)

Example Question #2 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum \displaystyle 28+32 as the multiple of a sum of two whole numbers with no common factor. 

Possible Answers:

\displaystyle 3(7+8)

\displaystyle 8(7+5)

None of these

\displaystyle 5(7+8)

\displaystyle 4(7+8)

Correct answer:

\displaystyle 4(7+8)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 28+32

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=4

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 4(7+8)

Example Question #2 : Find Greatest Common Factor

Use the distributive property to express the sum \displaystyle 20+36 as the multiple of a sum of two whole numbers with no common factor. 

Possible Answers:

\displaystyle 9(5+4)

\displaystyle 4(5+9)

\displaystyle 5(4+9)

\displaystyle 5(5+9)

\displaystyle 9(5+9)

Correct answer:

\displaystyle 4(5+9)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 20+36

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=4

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 4(5+9)

Example Question #3 : Find Greatest Common Factor

Use the distributive property to express the sum \displaystyle 20+25 as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

None of these

\displaystyle 5(4+5)

\displaystyle 5(5+5)

\displaystyle 5(4+5)

\displaystyle 3(4+5)

Correct answer:

\displaystyle 5(4+5)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 20+25

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=5

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 5(4+5)

Example Question #1 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum \displaystyle 55+100 as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

\displaystyle 20(11+5)

\displaystyle 5(11+20)

\displaystyle 55(10+4)

\displaystyle 5(10+20)

\displaystyle 8(11+20)

Correct answer:

\displaystyle 5(11+20)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 55+100

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=5

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 5(11+20)

Example Question #5 : Find Greatest Common Factor

Use the distributive property to express the sum \displaystyle 10+15 as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

\displaystyle 3(2+5)

\displaystyle 2(5+3)

\displaystyle 5(2+3)

\displaystyle 6(2+3)

None of these

Correct answer:

\displaystyle 5(2+3)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 10+15

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=5

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 5(2+3)

Example Question #3 : Find Greatest Common Factor

Use the distributive property to express the sum \displaystyle 10+45 as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

\displaystyle 9(2+5)

\displaystyle 2(5+9)

\displaystyle 3(5+9)

\displaystyle 5(2+9)

\displaystyle 3(2+9)

Correct answer:

\displaystyle 5(2+9)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 10+45

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=5

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 5(2+9)

Example Question #2 : Find Greatest Common Factor And Least Common Multiple: Ccss.Math.Content.6.Ns.B.4

Use the distributive property to express the sum \displaystyle 12+18 as the multiple of a sum of two whole numbers with no common factor.

Possible Answers:

\displaystyle 2(6+3)

\displaystyle 6(2+3)

\displaystyle 3(2+6)

None of these

\displaystyle 4(5+3)

Correct answer:

\displaystyle 6(2+3)

Explanation:

The distributive property can be used to rewrite an expression. When we use this property we will identify and pull out the greatest common factor of each of the addends. Then we can create a quantity that represents the sum of two whole numbers with no common factor multiplied by their greatest common factor.

 \displaystyle 12+18

In this case, the greatest common factor shared by each number is:

 \displaystyle \text{GCF}=6

After we reduce each addend by the greatest common factor we can rewrite the expression:

\displaystyle 6(2+3)

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