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Common Core: 6th Grade Math : Evaluate Expressions: CCSS.Math.Content.6.EE.A.2c

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #39 : One Step Equations

Solve: -6 +x =75

Possible Answers:

$-\frac{25}{2}$

Correct answer:

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To isolate the unknown variable, add six on both sides.

-6 +x +6=75+6

x=81

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Example Question #41 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: 13x = 1313

Possible Answers:

101

112

1001

111

110

Correct answer:

101

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To isolate , divide both sides by 13.

$\frac{13x}{13} = \frac{1313}{13}$

x=101

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Example Question #41 : One Step Equations

Solve:

10x = 6

Possible Answers:

$\frac{1}{4}$

$\frac{1}{16}$

$\frac{5}{3}$

$\frac{3}{5}$

Correct answer:

$\frac{3}{5}$

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To solve this equation, divide both sides by ten.

$\frac{10x}{10} = \frac{6}{10}$

Once we divide, then factor the numerator to find any common factors that can cancel out. Since there is a two in the numerator and in the denominator, they cancel out and we are left with out final, simplified answer.

$x=\frac{6}{10} = \frac{2\cdot 3}{2\cdot 5}=\frac{3}{5}$

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Example Question #42 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: 12x = 1224

Possible Answers:

120

112

202

102

Correct answer:

102

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

Divide both sides by twelve.

$\frac{12}{12}x = \frac{1224}{12}$

From here, factor the numerator to further simplify.

$x=\frac{1224}{12}=\frac{12\cdot 102}{12}$

The twelve in the numerator and the denominator cancel out and we arrive at the final solution.

x=102

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Example Question #43 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: 3+x = 103

Possible Answers:

100

106

103

Correct answer:

100

Explanation:

Subtract from both sides of the equation.

3+x-3 = 103-3

x=100

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Example Question #44 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: 7x = 91

Possible Answers:

Correct answer:

Explanation:

Divide by seven on both sides of the equation.

$\frac{7x}{7} =\frac{ 91}{7}$

x=13

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Example Question #45 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve the equation:

2+x = 88

Possible Answers:

Correct answer:

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To solve for . subtract two from both sides of the equation.

2+x -2= 88-2

x=86

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Example Question #791 : Pre Algebra

Solve:

9x= 24

Possible Answers:

$\frac{1}{13}$

$\frac{3}{8}$

$\frac{8}{3}$

Correct answer:

$\frac{8}{3}$

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

Divide nine on both sides and reduce the fraction.

$\frac{9x}{9}= \frac{24}{9}$

From here, factor the numerator and denominator to find values that can cancel.

$\frac{24}{9}=\frac{3\cdot 8}{3\cdot 3}$

Since there is a three in both the numerator and denominator it reduces to one and we are left with the final answer of,

$x=\frac{8}{3}$ .

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Example Question #792 : Pre Algebra

Solve: x+19 = -19

Possible Answers:

Correct answer:

Explanation:

To solve for , simply subtract 19 from both side of the equation to isolate .

x+19 -19= -19-19

x=-38

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Example Question #793 : Pre Algebra

Solve for the unknown variable:

13x = 13013

Possible Answers:

110

1010

1011

101

1001

Correct answer:

1001

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

Divide both sides by 13 to isolate the variable.

$\frac{13x }{13}= \frac{13013}{13}$

Now factor the numerator to find values that can cancel out.

$\frac{13013}{13}=\frac{13\cdot 1001}{13}$

The 13 in the numerator and denominator reduces to one and we are left with,

x=1001 .

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All Common Core: 6th Grade Math Resources

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Common Core: 6th Grade Math : Evaluate Expressions: CCSS.Math.Content.6.EE.A.2c

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #39 : One Step Equations

Example Question #41 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #41 : One Step Equations

Example Question #42 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #43 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #44 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #45 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #791 : Pre Algebra

Example Question #792 : Pre Algebra

Example Question #793 : Pre Algebra

All Common Core: 6th Grade Math Resources

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