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Common Core: 6th Grade Math : Evaluate Expressions: CCSS.Math.Content.6.EE.A.2c

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

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Example Questions

Example Question #252 : Expressions & Equations

Solve for $\displaystyle y$.

y-7=10 $\displaystyle y-7=10$

Possible Answers:

y=2 $\displaystyle y=2$

y=3 $\displaystyle y=3$

y=-3 $\displaystyle y=-3$

y=17 $\displaystyle y=17$

y=0 $\displaystyle y=0$

Correct answer:

y=17 $\displaystyle y=17$

Explanation:

To get y by itself, you must add 7 to both sides of the equation

$\displaystyle y-7+7=10+7$

which simplifies to

y=17 $\displaystyle y=17$

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Example Question #253 : Expressions & Equations

-x=4-2x $\displaystyle -x=4-2x$

Solve for $\displaystyle x$.

Possible Answers:

$\displaystyle -4$

$\displaystyle 0$

$\displaystyle 2$

$\displaystyle 4$

$\displaystyle 3$

Correct answer:

$\displaystyle 4$

Explanation:

Add 2x to each side to get all variables on one side:

-x=4-2x $\displaystyle -x=4-2x$

+2x +2x $\displaystyle +2x +2x$

x=4 $\displaystyle x=4$

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Example Question #31 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

32s=128 $\displaystyle 32s=128$

Solve for $\displaystyle s$.

Possible Answers:

$\displaystyle 3$

$\displaystyle 0$

$\displaystyle 1$

$\displaystyle 7$

$\displaystyle 4$

Correct answer:

$\displaystyle 4$

Explanation:

To isolate the variable "s" from the expression 32s, divide both sides of the equation by 32. 128/32=4, so s=4

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Example Question #32 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

$\displaystyle -3652+y=1372$

Solve for $\displaystyle y$.

Possible Answers:

$\displaystyle 15$

5024 $\displaystyle 5024$

2280 $\displaystyle 2280$

$\displaystyle -2280$

$\displaystyle -5024$

Correct answer:

5024 $\displaystyle 5024$

Explanation:

Add 3625 to each side to isolate y. This gives you the answer 5024

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Example Question #33 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: $\frac{x}{10} = 100$ $\displaystyle \frac{x}{10} = 100$

Possible Answers:

$\frac{1}{10}$ $\displaystyle \frac{1}{10}$

$\displaystyle 90$

110 $\displaystyle 110$

$\displaystyle 10$

1000 $\displaystyle 1000$

Correct answer:

1000 $\displaystyle 1000$

Explanation:

To solve for $\displaystyle x$, multiply ten on both sides of the equation to eliminate the denominator.

$\frac{x}{10} \times 10= 100\times 10$ $\displaystyle \frac{x}{10} \times 10= 100\times 10$

x=1000 $\displaystyle x=1000$

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Example Question #34 : One Step Equations

solve for $\displaystyle x$:

x+15=7 $\displaystyle x+15=7$

Possible Answers:

x=8 $\displaystyle x=8$

x=-8 $\displaystyle x=-8$

x=22 $\displaystyle x=22$

None of the other answers.

x=-22 $\displaystyle x=-22$

Correct answer:

x=-8 $\displaystyle x=-8$

Explanation:

To solve for x you simply isolate it on one side of the equation. To do this, apply the opposite operations to manipulate the equation.

x+15=7 $\displaystyle x+15=7$

Subtract 15 from both sides:

$x{\color{Red} +15-15}=7-15$ $\displaystyle x{\color{Red} +15-15}=7-15$

The red terms canceled.

x=7-15 $\displaystyle x=7-15$

We just subtract as normal on the right side.

x=-8 $\displaystyle x=-8$

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Example Question #261 : Expressions & Equations

Solve: $\frac{x}{8}=8$ $\displaystyle \frac{x}{8}=8$

Possible Answers:

$\displaystyle 0$

$\displaystyle 16$

$\frac{1}{16}$ $\displaystyle \frac{1}{16}$

$\displaystyle 1$

$\displaystyle 64$

Correct answer:

$\displaystyle 64$

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To eliminate the fraction, multiply both sides by eight to cancel the denominator.

$\frac{x}{8} \times 8=8\times 8$ $\displaystyle \frac{x}{8} \times 8=8\times 8$

x=64 $\displaystyle x=64$

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Example Question #262 : Expressions & Equations

Solve: $\displaystyle -2x= -26$

Possible Answers:

$\displaystyle 13$

$\frac{1}{13}$ $\displaystyle \frac{1}{13}$

$\displaystyle 52$

$-\frac{1}{13}$ $\displaystyle -\frac{1}{13}$

$\displaystyle -13$

Correct answer:

$\displaystyle 13$

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

Divide both sides by negative two.

$\frac{-2x}{-2}= \frac{-26}{-2}$ $\displaystyle \frac{-2x}{-2}= \frac{-26}{-2}$

Simplify. A double negative will eliminate each other when dividing.

x=13 $\displaystyle x=13$

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Example Question #263 : Expressions & Equations

Solve for $\displaystyle x$:

5-x-6=0 $\displaystyle 5-x-6=0$

Possible Answers:

$\displaystyle -11$

$\displaystyle -1$

$\displaystyle 11$

$\displaystyle 1$

$\displaystyle 10$

Correct answer:

$\displaystyle -1$

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

To determine what the unknown variable is in this particular equation, add $\displaystyle x$ on both sides of the equation.

$\displaystyle 5-x-6 + (x)=0 + (x)$

$\displaystyle x=5-6= -1$

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Example Question #34 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve: 9x = 40 $\displaystyle 9x = 40$

Possible Answers:

360 $\displaystyle 360$

$\displaystyle 49$

$\displaystyle 31$

$\frac{40}{9}$ $\displaystyle \frac{40}{9}$

$\frac{9}{40}$ $\displaystyle \frac{9}{40}$

Correct answer:

$\frac{40}{9}$ $\displaystyle \frac{40}{9}$

Explanation:

To isolate the $\displaystyle x$ variable, divide both sides of the equation by nine.

$\frac{9x }{9}= \frac{40}{9}$ $\displaystyle \frac{9x }{9}= \frac{40}{9}$

$x=\frac{40}{9}$ $\displaystyle x=\frac{40}{9}$

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All Common Core: 6th Grade Math Resources

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Common Core: 6th Grade Math : Evaluate Expressions: CCSS.Math.Content.6.EE.A.2c

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #252 : Expressions & Equations

Example Question #253 : Expressions & Equations

Example Question #31 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #32 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #33 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #34 : One Step Equations

Example Question #261 : Expressions & Equations

Example Question #262 : Expressions & Equations

Example Question #263 : Expressions & Equations

Example Question #34 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

All Common Core: 6th Grade Math Resources

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