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Common Core: 5th Grade Math : Common Core Math: Grade 5

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #53 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}6\\ \times\phantom{0}6\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3574

35840

3594

3584

Correct answer:

3584

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 64 is the multiplier and 56 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 6

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 5 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4 \\ \hline \phantom{\,}2\,2\,4\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4 \\ \hline \phantom{\,}2\,2\,4 \\ \, 0 \end{array}$

Next, we multiply 6 and 6

$\begin{array}{r}\overset{3 \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4 \\ \hline \phantom{\,}2\,2\,4 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 5and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4 \\ \hline \phantom{\,}2\,2\,4 \\ \, 3 \, 3 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 5} \space{\,}6\\ \times \phantom{0} 6\space{\,}4 \\ \hline \phantom{\,}2\,2\,4 \\+\, 3 \, 3 \, 6 \, 0\\ \hline 3\, 5 \, 8\, 4\end{array}$

Report an Error

Example Question #382 : Numbers And Operations

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times\phantom{0}3\space{\,}0 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1280

1300

12900

1290

Correct answer:

1290

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 30 is the multiplier and 43 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 0 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 0 \end{array}$

Next, we multiply 3 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 9 \, 0\end{array}$

Then, we multiply 3 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 1\, 2\, 9 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}3\\ \times \phantom{0} 3\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\+\, 1\, 2\, 9 \, 0\\ \hline 1\, 2 \, 9\, 0\end{array}$

Report an Error

Example Question #383 : Numbers And Operations

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times\phantom{0}1\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1168

11680

1158

1178

Correct answer:

1168

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 16 is the multiplier and 73 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 3

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6\\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 6 and 7 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 0 \end{array}$

Next, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 3 \, 0\end{array}$

Then, we multiply 1 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 7 \, 3 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\+\, 7 \, 3 \, 0\\ \hline 1\, 1 \, 6\, 8\end{array}$

Report an Error

Example Question #81 : How To Multiply

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times\phantom{0}4\space{\,}0 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2850

28400

2830

2840

Correct answer:

2840

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 40 is the multiplier and 71 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 0 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 0 \end{array}$

Next, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 4 \, 0\end{array}$

Then, we multiply 4 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 2\, 8\, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\+\, 2\, 8\, 4 \, 0\\ \hline 2\, 8 \, 4\, 0\end{array}$

Report an Error

Example Question #81 : How To Multiply

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times\phantom{0}4\space{\,}2 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3108

3118

31080

3098

Correct answer:

3108

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 42 is the multiplier and 74 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 2 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 0 \end{array}$

Next, we multiply 4 and 4

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 6 \, 0\end{array}$

Then, we multiply 4 and 7and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 2 \, 9 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\+\, 2 \, 9 \, 6 \, 0\\ \hline 3\, 1 \, 0\, 8\end{array}$

Report an Error

Example Question #383 : Numbers And Operations

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}7\\ \times\phantom{0}3\space{\,}8 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

656

6460

646

636

Correct answer:

646

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 38 is the multiplier and 17 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 7

$\begin{array}{r}\overset{5 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 8 and 1 and add the 5 that was carried

$\begin{array}{r}\overset{5 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 0 \end{array}$

Next, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 1 \, 0\end{array}$

Then, we multiply 3 and 1and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 5 \, 1 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\+\, 5 \, 1 \, 0\\ \hline 6\, 4 \, 6\end{array}$

Report an Error

Example Question #384 : Numbers And Operations

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}7\\ \times\phantom{0}2\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1311

1301

1321

13110

Correct answer:

1311

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 23 is the multiplier and 57 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3\\ \hline \phantom{\,} \,1\end{array}$

Then, we multiply 3 and 5 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 0 \end{array}$

Next, we multiply 2 and 7

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 4 \, 0\end{array}$

Then, we multiply 2 and 5and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 1 \, 1 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\+\, 1 \, 1 \, 4 \, 0\\ \hline 1\, 3 \, 1\, 1\end{array}$

Report an Error

Example Question #385 : Numbers And Operations

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times\phantom{0}8\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

6720

6710

6730

67200

Correct answer:

6720

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 84 is the multiplier and 80 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 4 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 0 \end{array}$

Next, we multiply 8 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 8 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 6\, 4\, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\+\, 6\, 4\, 0 \, 0\\ \hline 6\, 7 \, 2\, 0\end{array}$

Report an Error

Example Question #1051 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times\phantom{0}4\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

22440

2244

2234

2254

Correct answer:

2244

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 44 is the multiplier and 51 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 0 \end{array}$

Next, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 4 \, 0\end{array}$

Then, we multiply 4 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 2\, 0\, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\+\, 2\, 0\, 4 \, 0\\ \hline 2\, 2 \, 4\, 4\end{array}$

Report an Error

Example Question #61 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times\phantom{0}2\space{\,}2 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

836

8360

846

826

Correct answer:

836

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 22 is the multiplier and 38 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 8

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 2 and 3 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 0 \end{array}$

Next, we multiply 2 and 8

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 2 and 3and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 7 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\+\, 7 \, 6 \, 0\\ \hline 8\, 3 \, 6\end{array}$

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 5th Grade Math : Common Core Math: Grade 5

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #53 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #382 : Numbers And Operations

Example Question #383 : Numbers And Operations

Example Question #81 : How To Multiply

Example Question #81 : How To Multiply

Example Question #383 : Numbers And Operations

Example Question #384 : Numbers And Operations

Example Question #385 : Numbers And Operations

Example Question #1051 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #61 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All Common Core: 5th Grade Math Resources

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