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Common Core: 5th Grade Math : Common Core Math: Grade 5

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.14.33 am

Possible Answers:

48in^3

48in^2

36n^3

38in^3

42in^3

Correct answer:

36n^3

Explanation:

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

Screen shot 2015 12 22 at 11.15.43 am

In order to find the length of the rectangular prism on the bottom, we had to take the height of the original figure (which was ) and subtract the height of the rectangular prism on the top (which is )

6-3=3

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=4\times2\times3$ and $v=2\times2\times3$

v=24in^3 and v=12in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}24in^3\\ +\ 12in^3\end{array}}{ \ \ \ \space 36in^3}$

*Remember, volume is always measured in cubic units!

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Example Question #12 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.17.01 am

Possible Answers:

6in^3

8in^3

10in^3

16in^3

14in^3

Correct answer:

14in^3

Explanation:

Screen shot 2015 12 22 at 11.16.38 am

5-2=3

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=4\times1\times2$ and $v=2\times1\times3$

v=8in^3 and v=6in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}8in^3\\ +\ 6in^3\end{array}}{ \ \ \space 14in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #13 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.17.50 am

Possible Answers:

30in^3

56in^3

60in^3

42in^3

54in^3

Correct answer:

54in^3

Explanation:

Screen shot 2015 12 22 at 11.18.16 am

6-2=4

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=5\times3\times2$ and $v=3\times2\times4$

v=30in^3 and v=24in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}30in^3\\ +\ 24in^3\end{array}}{ \ \ \ \space 54in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #14 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.19.45 am

Possible Answers:

174in^3

72in^3

126in^3

96in^2

168in^3

Correct answer:

168in^3

Explanation:

Screen shot 2015 12 22 at 11.19.28 am

9-3=6

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=8\times4\times3$ and $v=3\times4\times6$

v=96in^3 and v=72in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}96in^3\\ +\ 72in^3\end{array}}{ \ \ \space 168in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #15 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.20.10 am

Possible Answers:

84in^3

48in^3

120in^3

116in^3

126in^2

Correct answer:

84in^3

Explanation:

Screen shot 2015 12 22 at 11.20.28 am

9-2=7

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=7\times3\times2$ and $v=2\times3\times7$

v=42in^3 and

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}42in^3\\ +\ 42in^3\end{array}}{ \ \ \ \space 84in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #16 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.21.49 am

Possible Answers:

296in^3

285in^3

270in^3

294in^3

282in^3

Correct answer:

270in^3

Explanation:

Screen shot 2015 12 22 at 11.21.31 am

11-3=8

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=10\times5\times3$ and $v=3\times5\times8$

v=150in^3 and v=120in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}150in^3\\ +\ 120in^3\end{array}}{ \ \ \ \space 270in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #17 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.22.15 am

Possible Answers:

300in^3

135in^3

165in^3

178in^3

320in^3

Correct answer:

300in^3

Explanation:

Screen shot 2015 12 22 at 11.22.33 am

12-3=9

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=11\times5\times3$ and $v=3\times5\times9$

v=165in^3 and v=135in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}165in^3\\ +\ 135in^3\end{array}}{ \ \ \ \space 300in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #18 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.23.12 am

Possible Answers:

493in^3

512in^3

456in^3

520in^3

580in^3

Correct answer:

456in^3

Explanation:

Screen shot 2015 12 22 at 12.55.35 pm

12-4=8

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=11\times6\times4$ and $v=4\times6\times8$

v=264in^3 and v=192in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}264in^3\\ +\ 192in^3\end{array}}{ \ \ \ \space 456in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #1829 : Common Core Math: Grade 5

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.23.46 am

Possible Answers:

235in^3

285in^3

256in^3

150in^3

135in^3

Correct answer:

285in^3

Explanation:

Screen shot 2015 12 22 at 11.24.14 am

12-3=9

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=10\times5\times3$ and $v=3\times5\times9$

v=150in^3 and v=135in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}150in^3\\ +\ 135in^3\end{array}}{ \ \ \ \space 285in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #1821 : Common Core Math: Grade 5

What is the volume of the figure below?

Screen shot 2015 12 22 at 11.25.07 am

Possible Answers:

110in^3

130in^3

240 in^3

240in^2

130in^2

Correct answer:

240 in^3

Explanation:

Screen shot 2015 12 22 at 11.24.53 am

15-2=13

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=11\times5\times2$ and $v=2\times5\times13$

v=110in^3 and v=130in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}110in^3\\ +\ 130in^3\end{array}}{ \ \ \ \space 240in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

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Common Core: 5th Grade Math : Common Core Math: Grade 5

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #11 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #12 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #13 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #14 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #15 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #16 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #17 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #18 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #1829 : Common Core Math: Grade 5

Example Question #1821 : Common Core Math: Grade 5

All Common Core: 5th Grade Math Resources

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