All Calculus 1 Resources
Example Questions
Example Question #11 : Equation Of Line
Give the general equation for the line tangent to at the point .
The equation of the tangent line has the form .
The slope can be determined by evaluating the derivative of the function at .
Plugging this into the point slope equation, we get
can be determined by evaluating the original function at .
Plugging this into the previous equation and simplifying gives us
Example Question #2714 : Calculus
Find the slope of the line tangent to the following function at .
None of these
To find the slope of the line tangent you must take the derivative of the function. The derivative of cosine is negative sine and the derivative of sine is cosine.
This makes the derivative of the function
.
Plug in the given x to get the slope.
Example Question #11 : Lines
Find the slope of the tangent line to the following function at .
None of these
To find the slope of the line tangent to the function at a point you must first find the derivative.
The power rule states that the derivative of is .
The derivative of is .
The derivative of the function is
.
Plugging in 1 for x gives
.
Example Question #11 : Equation Of Line
Given the differential function , we are told that , , and . Which of the following must be true?
must have at least one relative maximum.
is decreasing at .
The line is tangent to .
is increasing over the interval .
has a point of inflection at .
The line is tangent to .
" is decreasing at ." is incorrect. The function is increasing at because .
" is increasing over the interval ." is possibly true, but there is not enough information to conclude that it must be true.
" has a point of inflection at ." is possibly true. Although we know that , a requirement for an inflection point, we do not know that changes signs at .
" must have at least one relative maximum." is possibly true, but there is not enough information to conclude that it must be true.
"The line is tangent to ." must be true. Because , the function travels through the point . Because , the slope of the line tangent to the curve at is 5. Use point-slope form to determine the equation of the tangent line.
Example Question #242 : Graphing Functions
Find the equation for the line tangent to the curve at .
The derivative of the function is , and is found using the power rule
and the rule for the derivative of natural log which is,
so plugging in gives , which must be the slope of the line since the tangent line's slope is determined by the derivative.
Thus, the line is of the form , where b is unknown.
Solve for b by setting the equation equal to and plugging in for x since that is the given point.
, which gives us
Example Question #11 : How To Find Equation Of Line By Graphing Functions
Find the slope of the tangent line through the given point of the following function.
at the point
In order to find the slope of the tangent line through a certain point, we must find the rate of change (derivative) of the function. The derivative of is written as . This tells us what the slope of the tangent line is through any point in our function . In other words, all we need to do is plug-in (because our point has an x-value of 1) into . This will give us our answer, .
Example Question #17 : Equation Of Line
Find the tangent line to the function at the point .
To find the tangent line one must first find the slope, this can be given by the derivative evaluated at a point.
To find the derivative of this function use the power rule which states,
The derviative of is .
Evaluated at our point ,
we find that the slope, m is also 3.
Now we may use the point-slope equation of a line to find the tangent line.
The point slope equation is
Where is the point at which the line is tangent.
Using this definition we find the tangent line to be defined by .