All Calculus 1 Resources
Example Questions
Example Question #621 : Functions
Find the derivative.
Find the derivative using the power rule.
Remember the power rule:
We can now apply this to our situation.
The derivative is
Example Question #622 : Functions
Find the derivative at .
First, find the derivative using the power rule.
Remember the power rule:
We can now apply this to our situation.
The derivative is
Now, substitute for .
Example Question #623 : Functions
Find the derivative.
Use the product rule to find the derivative.
Remember the product rule:
We can now apply this to our situation.
Simplify.
Example Question #624 : Functions
Find the derivative.
Use the quotient rule to find the derivative.
Remember the quotient rule:
We can now apply this to our situation.
Example Question #431 : Other Differential Functions
Find the derivative.
Find the derivative using the quotient rule.
Remember the quotient rule:
We can now apply this to our situation.
Example Question #626 : Functions
Find the derivative.
Find the derivative using the quotient rule.
Remember the quotient rule:
We can now apply this to our situation.
Example Question #1656 : Calculus
Let on the interval . Find a value for the number(s) that satisfies the mean value theorem for this function and interval.
The mean value theorem states that for a planar arc passing through a starting and endpoint , there exists at a minimum one point, , within the interval for which a line tangent to the curve at this point is parallel to the secant passing through the starting and end points.
In other words, if one were to draw a straight line through these start and end points, one could find a point on the curve where the tangent would have the same slope as this line.
Note that the value of the derivative of a function at a point is the function's slope at that point; i.e. the slope of the tangent at said point.
First, find the two function values of on the interval
Then take the difference of the two and divide by the interval.
Now find the derivative of the function; this will be solved for the value(s) found above.
The solution validates the mean value theorem by falling within
Example Question #1657 : Calculus
Let on the interval . Find a value for the number(s) that satisfies the mean value theorem for this function and interval.
The mean value theorem states that for a planar arc passing through a starting and endpoint , there exists at a minimum one point, , within the interval for which a line tangent to the curve at this point is parallel to the secant passing through the starting and end points.
In other words, if one were to draw a straight line through these start and end points, one could find a point on the curve where the tangent would have the same slope as this line.
Note that the value of the derivative of a function at a point is the function's slope at that point; i.e. the slope of the tangent at said point.
First, find the two function values of on the interval
Then take the difference of the two and divide by the interval.
Now find the derivative of the function; this will be solved for the value(s) found above.
Of these two solutions validates the mean value theorem by valling within
Example Question #441 : Other Differential Functions
Let on the interval . How many values of x exist that satisfy the mean value theorem for this function and interval?
The mean value theorem states that for a planar arc passing through a starting and endpoint , there exists at a minimum one point, , within the interval for which a line tangent to the curve at this point is parallel to the secant passing through the starting and end points.
In other words, if one were to draw a straight line through these start and end points, one could find a point on the curve where the tangent would have the same slope as this line.
Note that the value of the derivative of a function at a point is the function's slope at that point; i.e. the slope of the tangent at said point.
First, find the two function values of on the interval
Then take the difference of the two and divide by the interval.
Now find the derivative of the function; this will be solved for the value(s) found above.
Both of these solutions validate the mean value theorem by falling within .
Note that for a function that's differentiable on an interval like the one given, there will always be at least one point that satisfies the MVT.
Example Question #1659 : Calculus
Let on the interval . How many values of x such that the mean value theorem is validated?
The mean value theorem states that for a planar arc passing through a starting and endpoint , there exists at a minimum one point, , within the interval for which a line tangent to the curve at this point is parallel to the secant passing through the starting and end points.
In other words, if one were to draw a straight line through these start and end points, one could find a point on the curve where the tangent would have the same slope as this line.
Note that the value of the derivative of a function at a point is the function's slope at that point; i.e. the slope of the tangent at said point.
First, find the two function values of on the interval
Then take the difference of the two and divide by the interval.
Now find the derivative of the function; this will be solved for the value(s) found above.
Note that we do not include the start and end points as values that satisfy the mean value theorem. Therefore, there are nine values which fall within the open interval and satisfy the MVT
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