Calculus 1 : Differential Functions

Study concepts, example questions & explanations for Calculus 1

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Example Questions

Example Question #1562 : Calculus

Which of the following is an inflection point for the function  ?

Possible Answers:

Correct answer:

Explanation:

The points of inflection of a function occur where the second derivative of the funtion is equal to zero.

Find this second derivative by taking the derivative of the function twice:

 

Set the second derivative to zero and find the values that satisfy the equation:

The only value of  which satisfies the equation is  

This can be shown to be a point of inflection due to  having opposite signs on either side of it:

Now, plug these values back in to the original function to find the values of the function that match to them:

 

The point of inflection is .

It can be confirmed that  is a point of inflection due to the sign change around this point. Picking a greater and lower value , observe the difference in sign of the second derivative:

Example Question #1571 : Calculus

Find the slope of the line normal to the function  at the point .

Possible Answers:

Correct answer:

Explanation:

The first step to finding the slope of the line normal to a point is to find the slope of the tangent at this point.

The slope of this tangent, in turn, is found by finding the value of the derivative of the function at this point.

We'll need to make use of the following derivative rule(s):

Derivative of an exponential: 

Trigonometric derivative: 

Product rule: 

Note that u and v may represent large functions, and not just individual variables!

Evaluating the function  at the point 

The slope of the tangent is

 

The slope of the normal line is the negative reciprocal of this value. Thus for this problem the normal is

Example Question #541 : Functions

Find the derivative.

Possible Answers:

Correct answer:

Explanation:

Use the power rule to find this derivative. 

Remember the power rule is:

Now lets apply this to our problem.

Recall that the derivative of a constant is zero.

Thus, the derivative is .

Example Question #355 : How To Find Differential Functions

Find the derivative at .

Possible Answers:

Correct answer:

Explanation:

First, use the power rule to find the derivative. 

Remember the power rule is:

Now lets apply this to our problem.

Recall that the derivative of a constant is zero.

Thus, the derivative is 

Now, substitute  for .

Example Question #544 : Differential Functions

Find the derivative.

Possible Answers:

Correct answer:

Explanation:

Use the power rule to find this derivative. 

Remember the power rule is:

Now lets apply this to our problem.

Thus, the derivative is .

Example Question #545 : Differential Functions

Find the derivative at .

Possible Answers:

Correct answer:

Explanation:

First, find the derivative using the power rule. 

Remember the power rule is:

Now lets apply this to our problem.

Recall that the derivative of a constant is zero.

The derivative is .

Now, substitute  for .

Example Question #541 : Differential Functions

Find the derivative. 

Possible Answers:

Correct answer:

Explanation:

Use the power rule to find this derivative. 

Remember the power rule is:

Now lets apply this to our problem.

Example Question #361 : How To Find Differential Functions

Find the derivative. 

Possible Answers:

Correct answer:

Explanation:

Use the power rule to find the derivative.

Remember the power rule is:

Now lets apply this to our problem.

Recall that the derivative of a constant is zero.

Thus, the derivative is 

Example Question #362 : How To Find Differential Functions

Find the derivative at .

Possible Answers:

Correct answer:

Explanation:

Find the derivative using the power rule. 

Remember the power rule is:

Now lets apply this to our problem.

Now, substitute  for .

Example Question #1576 : Calculus

Find the derivative at .

Possible Answers:

Correct answer:

Explanation:

First, find the derivative using the power rule. 

Remember the power rule is:

Now lets apply this to our problem.

Thus, the derivative is . Now, substitute  for .

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