Biochemistry : Catabolic Pathways and Metabolism

Study concepts, example questions & explanations for Biochemistry

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Example Questions

Example Question #1 : Other Glycogenolysis Concepts

Which one of the following can store the largest total amount of Glycogen in the human body?

Possible Answers:

Liver

Brain

Fat

Skeletal muscle

Correct answer:

Skeletal muscle

Explanation:

Glycogen is the storage form of glucose, and is more readily accessible than starches or fats. It is used for short-term supply of glucose and in starvation conditions is used up in a matter of hours. It is mainly stored in the liver and skeletal muscle. Glycogenolysis in the liver results in glucose release into the bloodstream, whereas in the muscle the glucose is immediately used up. The highest demand for the glucose is in the muscle, and that is where most of it is stored.

Example Question #191 : Carbohydrate Metabolism

Which enzyme(s) bypass the pyruvate kinase reaction of glycolysis in gluconeogenesis?

Possible Answers:

phosphoglycerate mutase and pyruvate carboxylase

phosphoenolpyruvate carboxykinase (PEPCK) only

fructose bis-phosphatase only

pyruvate carboxylase and phosphoenolpyruvate carboxykinase (PEPCK)

pyruvate carboxylase only

Correct answer:

pyruvate carboxylase and phosphoenolpyruvate carboxykinase (PEPCK)

Explanation:

In the first step of gluconeogenesis, pyruvate carboxylase (with ATP and bicarbonate) converts pyruvate to oxaloacetate. Then phosphoenolpyruvate carboxykinase (PEPCK) (with GTP) releases carbon dioxide to give phosphoenolpyruvate.

Example Question #991 : Biochemistry

Which one of the following statements about PEP (phosphoenolpyruvate) synthesis is correct?

Possible Answers:

Pyruvate is converted to PEP by the citric acid cycle.

Pyruvate can be converted to PEP by a mutase.

Pyruvate can be converted to PEP by a combination of reactions that use energy from two different types of nucleotide triphosphate.

Pyruvate can be converted to PEP by pyruvate kinase.

Correct answer:

Pyruvate can be converted to PEP by a combination of reactions that use energy from two different types of nucleotide triphosphate.

Explanation:

GTP and ATP are used to drive the reactions that make pyruvate into PEP. Specifically, ATP catalyzes PEP carboxylase and GTP catalyzes PEP carboxykinase. A mutase moves phosphate groups already on a molecule, so it cannot be used to introduce one. The citric acid cycle can make pyruvate into any of the citric acid intermediates, but PEP isn't one of them. Pyruvate kinase is the enzyme that makes pyruvate into PEP, which is only favorable in the forward direction.

Example Question #271 : Catabolic Pathways And Metabolism

In order for gluconeogenesis to generate one molecule of glucose, how many molecules of ATP and/or GTP are needed?

Possible Answers:

Correct answer:

Explanation:

Answering this question requires knowledge of the pathway of gluconeogenesis. In this pathway, non-carbohydrate carbon substrates such as lactate, pyruvate, and certain amino acids are used to generate glucose as the final product. Much of this pathway utilizes the same enzymes used in glycolysis, which is essentially the reverse of gluconeogenesis. However, it is critical to note that there are 3 reactions in glycolysis that are irreversible. Therefore, gluconeogenesis is not an exact reverse of glycolysis, and instead there are a few different enzymes in gluconeogenesis that bypass these irreversible reactions. One of the irreversible steps in glycolysis is the formation of pyruvate from phosphoenolpyruvate (PEP), catalyzed by the glycolytic enzyme pyruvate kinase. To bypass this irreversible reaction, gluconeogenesis makes use of two enzymes. First, the enzyme pyruvate carboxylase converts pyruvate into oxaloacetate, which requires the input of one molecule of ATP per molecule of pyruvate used. Next, the gluconeogenic enzyme PEP carboxykinase converts oxaloacetate into PEP, using one molecule of GTP per molecule of oxaloacetate used. The other step that requires an investment of energy is by a reaction that is reversible. The conversion of 3-phosphoglycerate into 1,3-bisphosphoglycerate (1,3-BPG) by the enzyme phosphoglycerate kinase utilizes one molecule of ATP per molecule of 1,3-BPG generated. This is a reversible reaction. Now, we can add up the energy requirements. Since each of these reactions need to occur twice in order to generate a single molecule of glucose, we'll need to multiply the energy investment by two in each step. Thus, we have two molecules of ATP from the reaction catalyzed by pyruvate carboxylase. We also have two molecules of GTP from the reaction catalyzed by PEP carboxykinase. And lastly, we have two molecules of ATP used from the reaction catalyzed by phosphoglycerate kinase. Adding all of these up, we have a total of four molecules of ATP and two molecules of GTP.

Example Question #201 : Carbohydrate Metabolism

Which of the following are true about oxaloacetate?

Possible Answers:

It is a lipid

It can cross mitochondrial membranes

It is an intermediary in glycolysis

It is an intermediary in the synthesis of glucose from glycerol

It is an intermediary in the synthesis of glucose from lactate

Correct answer:

It is an intermediary in the synthesis of glucose from lactate

Explanation:

Oxaloacetate contributes to fatty acid synthesis, but it’s not a lipid, because, among other reasons, it’s not hydrophobic. This is also why it cannot cross mitochondrial membranes. Glucose can be synthesized from glycerol, but this process occurs via dihydroxyacetone phosphate, and doesn’t involve oxaloacetate. Oxaloacetate is synthesized from pyruvate, which is the end product of glycolysis, so oxaloacetate cannot be an intermediary in glycolysis. However, lactate can be converted to pyruvate, which is the principle substrate for gluconeogenesis (sometimes called “reverse glycolysis”). In gluconeogenesis, oxaloacetate is an intermediary in the conversion of pyruvate to phosphoenolpyruvate, and so that makes it an intermediary, too, in the synthesis of glucose from lactate.

Example Question #1 : Gluconeogenesis

Which of the following is an example of futile cycling?

Possible Answers:

Glycolysis and ketogenesis occurring simultaneously.

Glycolysis and beta oxidation occurring simultaneously.

Glycolysis and the Krebs cycle occurring simultaneously.

Glycolysis and gluconeogenesis occurring simultaneously.

Glycolysis and oxidative phosphorylation occurring simultaneously.

Correct answer:

Glycolysis and gluconeogenesis occurring simultaneously.

Explanation:

Futile cycling occurs when two metabolic processes occur in opposite directions, and thus result in no net change. This is very wasteful, and not ideal. The only example of the answer choices of metabolic processes occurring in opposite directions is glycolysis and gluconeogenesis occurring simultaneously. Other possible examples could include: glycogenesis and glycogenolysis, beta-oxidation and fatty acid synthesis, etc.

Example Question #6 : Gluconeogenesis

Which of the following is not true about the gluconeogenesis pathway's role in organismal homeostasis? 

Possible Answers:

Gluconeogenesis is a pathway for cells to create glucose from various precursors when glucose itself is unavailable

Pyruvate and glycerol can be substrates for conversion to glucose in gluconeogenesis

Gluconeogenesis is primarily restricted to the liver and kidneys in mammalian species

Gluconeogenesis will typically remain quiescent if the cell has an overabundance of energy from other pathways

Gluconeogenesis occurs when an organism consumes abnormally high amounts of carbohydrates and fatty acids

Correct answer:

Gluconeogenesis occurs when an organism consumes abnormally high amounts of carbohydrates and fatty acids

Explanation:

Gluconeogenesis occurs in times of starvation, fasting, and low access to sources of glucose. This is the cells way of creating its own precursor when none is available, albeit at a high energetic cost (one cycle of gluconeogenesis can cost 6 ATP). Thus, it is untrue that gluconeogenesis occurs during high consumption of carbohydrates and fatty acids. Each other selection is true regarding gluconeogenesis. 

Example Question #1 : Other Gluconeogenesis Concepts

During anaerobic conditions, lactate travels from the muscle to the liver via the bloodstream. 

What is lactic acid converted into when it reaches the liver before it returns back to the muscle?

Possible Answers:

Glucose

Glycogen

Glucagon 

Acetyl-CoA

Citrate

Correct answer:

Glucose

Explanation:

The Cori cycle comes into play during anaerobic conditions; where lactate from glycolysis travels from the muscle to the liver to be converted into glucose via gluconeogenesis. The glucose is then sent back to the muscle to be used for energy. Note that some of the lactate that is converted into glucose can be stored as glycogen in the liver, but glycogen is not transported from the liver to the skeletal muscle. 

Example Question #1 : Fermentation And Anaerobic Respiration

Which of the following best describes how fermentation of pyruvate to lactic acid facilitates the production of ATP in the absence of oxygen?

Possible Answers:

It removes pyruvate, shifting the equilibrium favorably toward the forward reactions of glycolysis

It provides NADH for continued glycolysis

It lowers the pH of the cytosol, increasing the efficiency of ATP synthase

It provides lactic acid, which can phosphorylate ADP via substrate-level phosphorylation

It provides  for continued glycolysis

Correct answer:

It provides  for continued glycolysis

Explanation:

In the absence of oxygen, oxidative phosphorylation cannot be used to produce ATP, so glycolysis becomes the primary source of ATP for the cell. The importance of lactic acid fermentation is that it replenishes cellular  for the glyceraldehyde-3-phosphate dehydrogenase reaction, which precedes the ATP-producing steps. Without lactic acid fermentation,  concentrations would become too low for the glyceraldehyde-3-phosphate dehydrogenase reaction to occur, and the ATP-producing steps would not continue to be reached. 

Example Question #1 : Lactic Acid Fermentation

Which of the following is the correct pairing between the initial reactant and major product of a type of fermentation?

Possible Answers:

Glucose; carbon dioxide

Ethanol; lactate

Acetate; ethylene glycol

Glucose; lactate

Lactate; glucose

Correct answer:

Glucose; lactate

Explanation:

When glucose is fermented, it forms the product lactate.  Lactate can then continue on to be fermented to acetate. However, the other answer choices do not represent the correct direction from reactant to product in fermentation. In some organisms, ethanol and carbon dioxide may be produced via fermentation, but carbon dioxide is a byproduct, not a major product in these organisms. 

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