Biochemistry : Catabolic Pathways and Metabolism

Study concepts, example questions & explanations for Biochemistry

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Example Questions

Example Question #14 : Citric Acid Cycle

What is the intermediate between citrate and isocitrate?

Possible Answers:

Fumarate

Oxaloacetate

Cis-aconitate

Succinate

Correct answer:

Cis-aconitate

Explanation:

The citric acid cycle begins when a four-carbon molecule, oxaloacetate combines with acetyl-CoA (a two carbon molecule) to produce the six-carbon molecule citrate. The enzyme citrate synthase carries out this reaction. Citrate then becomes the six-carbon molecule cis-aconitate via catalysis by aconitase. The same enzyme then converts cis-aconitate to isocitrate, which is an isomer of citrate.

Example Question #934 : Biochemistry

What vitamin does pyruvate dehydrogenase need in order to make pyruvate into acetyl-CoA for the citric acid cycle? 

Possible Answers:

Niacin (B3)

Thiamine (B1)

Methylcobalamin (B12)

Pyridoxine (B6)

Correct answer:

Thiamine (B1)

Explanation:

Thiamine (B1) acts as a cofactor to enable pyruvate dehydrogenase to convert pyruvate from glycolysis into acetyl-CoA so it can enter the citric acid cycle. 

Example Question #15 : Citric Acid Cycle

The citric acid cycle begins when the two-carbon acetyl group from acetyl-CoA combines with the four-carbon molecule __________ to form the six-carbon molecule citrate. 

Possible Answers:

Malate

Pyruvate

Oxaloacetate

Aspartate

Aspartate

Correct answer:

Oxaloacetate

Explanation:

Oxaloacetate combines with acetyl-CoA to form citrate. This is the first stage of the citric acid cycle. Eventually, citrate will lose two molecules of  to regenerate the four-carbon molecule oxaloacetate.

Example Question #1 : Citric Acid Cycle Carbohydrate Intermediates

There are at least four types of glucose transporter in the body. GLUT1 and GLUT3 are located in most tissues including the brain and the red blood cells. These glucose transporters rapidly take up glucose from the blood but have the lowest  value. GLUT2 is commonly found in the liver and the pancreas. GLUT2 has a lower affinity for glucose but has the highest  value. GLUT4 is common in skeletal tissues and in adipose tissues. This transporter is normally not active for uptake unless stimulated by insulin or during exercise.  

During strenuous exercise, GLUT4 will be highly active. Which of the following intermediates will also increase?

I. Pyruvate

II. 

III. ADP

Possible Answers:

II and III

I only

I and II

III only

II only

Correct answer:

I and II

Explanation:

During strenuous exercise, GLUT4 will be active to bring glucose into the cell. Glucose is then pushed through glycolysis to generate pyruvate. Pyruvate is then pushed through pyruvate dehydrogenase complex, where it is converted into acetyl-CoA, which feeds into the Krebs cycle (assuming aerobic conditions) to generate ATP, NADH, , and carbon dioxide.  

Example Question #21 : Citric Acid Cycle

Which of the following Krebs cycle intermediate molecules can be used directly in another pathway to make fatty acids?

Possible Answers:

Citrate

Aspartate

Alpha-ketoglutarate

Succinyl-CoA

Oxaloacetate

Correct answer:

Citrate

Explanation:

Most of the intermediate molecules in the Krebs cycle can, rather than continuing through the cycle itself, go through other pathways to form macromolecules. Citrate can be used to create fatty acids and sterols. Alph-ketoglutarate can be used to make some of the amino acids. Succinyl-CoA can be used to make porphyrins, heme, and chlorophyll. Aspartate can be used to make some of the amino acids. Oxaloacetate can be used in gluconeogenesis to create glucose.

Example Question #1 : Citric Acid Cycle Carbohydrate Intermediates

How many atoms of carbon are present in the citric acid cycle intermediate, fumarate?

Possible Answers:

4

2

3

1

6

Correct answer:

4

Explanation:

The citric acid cycle intermediate, fumarate, contains four atoms of carbon.

As a frame of reference, one molecule of glucose, the starting material for glycolysis, contains six atoms of carbon. The carbohydrate products of glycolysis are two molecules of pyruvate, with one molecule of pyruvate containing three atoms of carbon.

In preparation for entering the citric acid cycle, pyruvate loses one molecule of carbon dioxide, and therefore one molecule of carbon, to form acetyl-CoA, which contains two atoms of carbon. Acetyl-CoA is then combined with a molecule of oxaloacetate, which contains four atoms of carbon, to produce a molecule of citrate, which contains six atoms of carbon, and is the starting point for the citric acid cycle.

Citrate undergoes a number of a reactions, via the citric acid cycle, most notably two reactions in which a single molecule of carbon dioxide, and therefore carbon, is lost, thereby decreasing the total number of carbons to four atoms. The two reactions that remove carbons are the conversion of isocitrate to alpha-ketoglutarate and the conversion of alpha-ketoglutarate to succinyl-CoA. No additional carbons are removed prior to the production of fumarate, and therefore, fumarate contains four atoms of carbon. 

Example Question #942 : Biochemistry

How many molecules of carbon are present in the citric acid cycle intermediate, malate?

Possible Answers:

1

4

3

6

2

Correct answer:

4

Explanation:

The citric acid cycle intermediate, malate, contains four atoms of carbon.

A single glucose molecule, which is the starting material for glycolysis, contains six carbon atoms. Glycolysis produces two pyruvate molecules, and one pyruvate molecule contains three carbon atoms.

Prior to entering the citric acid cycle, pyruvate loses one carbon dioxide molecule (e.g. one carbon atom), forming acetyl-CoA, which contains two carbon atoms. Acetyl-CoA then combines with one oxaloacetate molecule, a four-carbon molecule, to produce a molecule of citrate, which contains six carbon atoms, and is the starting material for the citric acid cycle.

Citrate undergoes a number of a reactions in the citric acid cycle, including two reactions where one atom of carbon dioxide (e.g. carbon) is lost, which decreases the total number of carbons to four atoms. The two reactions that remove carbons are the conversion of isocitrate to alpha-ketoglutarate and the conversion of alpha-ketoglutarate to succinyl-CoA. No additional carbons are removed prior to the production of malate. Therefore, malate contains four atoms of carbon. 

Example Question #1 : Citric Acid Cycle Energetics

Which of the following statements about the citric acid cycle is true?

Possible Answers:

Two equivalents of  are produced in the cycle

There is only one decarboxylation in the cycle

Acetyl-CoA is one of the compounds in the cycle

Isocitrate is one of the compounds in the cycle

None of the other answers are true

Correct answer:

Isocitrate is one of the compounds in the cycle

Explanation:

Acetyl-CoA is not part of the cycle but is oxidized by it. There are two decarboxylations in the cycle, from isocitrate to alpha-ketoglutarate, and from alpha-ketoglutarate to succinyl-CoA. In total, three equivalents of  are produced in the cycle. Isocitrate is a compound in the cycle, produced from citrate.

Example Question #2 : Citric Acid Cycle Energetics

Which of the following steps in the citric acid cycle do not have a largely negative 

Possible Answers:

None of these reactions have largely negative  values

Correct answer:

Explanation:

Even though an  is generated when malate is dehydrogenated to oxaloacetate, this oxidation is very unfavorable because of the addition of a reactive ketone in place of an alcohol on the 2nd carbon. In fact, the only way this reaction can proceed is if oxaloacetate concentration is very low. All of the other reactions have large negative  values.

Example Question #1 : Citric Acid Cycle Energetics

Which reaction of the citric acid cycle makes the entire process unidirectional (i.e. irreversible)?

Possible Answers:

Succinate  fumarate

Isocitrate  alpha-ketoglutarate

Alpha-ketoglutarate  succinyl-CoA

Succinyl-CoA  malate

Citrate  isocitrate

Correct answer:

Isocitrate  alpha-ketoglutarate

Explanation:

The formation of alpha-ketoglutarate from isocitrate using the enzyme alpha-ketoglutarate dehydrogenase is an irreversible reaction due to its largely negative  value.

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