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Example Questions
Example Question #11 : Michaelis Menten Equation
Based on Michaelis-Menten enzyme kinetics, if a system has a substrate concentration that is significantly more then the Km, which of the following is a sound inference?
The enzyme is the limiting factor of the reaction rate, adding more substrate would increase the reaction rate.
The system is fully saturated and the rate is below Vmax.
The substrate is the limiting factor. The system is not saturated.
The system is not saturated, adding more enzyme would increase the Vmax.
The enzyme concentration is the limiting factor of the reaction rate, adding more substrate would not increase the rate.
The enzyme concentration is the limiting factor of the reaction rate, adding more substrate would not increase the rate.
With Michaelis-Menten Kinetics, The Vmax is the maximum rate of the enzyme mediated reaction. When a system has a concentration of substrate well above Km (which is the concentration of substrate at which the reaction is proceeding at one-half Vmax), then it is said that the system is saturated. In this state, the reaction is occurring basically at Vmax, since there is plenty of substrate to react with the enzyme, and adding more substrate would not increase the reaction rate. Rather, the concentration of enzyme is the limiting factor of how much reaction product will be produced per unit time.
Example Question #1 : Michaelis Menten Graphs
In a Lineweaver-Burk plot, the slope is __________.
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in form is:
From this graph, we can see that the slope is .
Example Question #1 : Michaelis Menten Graphs
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
All of the substrate has been converted into product
This only happens when a competitive inhibitor is present
This only happens when a non-competitive inhibitor is present
The enzyme becomes degraded
The enzyme becomes saturated
The enzyme becomes saturated
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
Example Question #1 : Michaelis Menten Graphs
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
When enzyme concentration is low
When enzyme concentration is high
When substrate concentration is low
It is never linear
When substrate concentration is high
When substrate concentration is low
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
Example Question #71 : Enzyme Kinetics And Inhibition
On a Lineweaver-Burk plot, which of the following is correct?
X intercept =
Slope =
Y-intercept =
X-axis is
Slope =
Slope =
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
Example Question #1 : Michaelis Menten Graphs
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
The lines will always be exactly the same
The y-intercept for the uninhibited line will be higher than that for the inhibited line
The x-intercept will be closer to the origin for the uninhibited line that for that of the inhibited line
The y-intercept will be the same for the inhibited and uninhibited line
The x-intercept of the inhibited line will be the same for both lines
The y-intercept will be the same for the inhibited and uninhibited line
will remain the same for an inhibited enzyme when a competitive inhibitor is used. With this information, one can figure out what will happen to the line for an inhibited enzyme on a Lineweaver Burk plot. The y-intercept represents on these graphs, and so in the presence of a competitive inhibitor, the y-intercept will remain unchanged for an inhibited enzyme. The x-intercept represents . A competitive inhibitor will raise , and so the inhibited enzyme's x-intercept will be closer to the origin.
Example Question #1 : Vmax And Km
There are at least four types of glucose transporter in the body. GLUT1 and GLUT3 are located in most tissues including the brain and the red blood cells. These glucose transporters rapidly take up glucose from the blood but have the lowest value. GLUT2 is commonly found in the liver and the pancreas. GLUT2 has a lower affinity for glucose but has the highest value. GLUT4 is common in skeletal tissues and in adipose tissues. This transporter is normally not active for uptake unless stimulated by insulin or during exercise.
What might be a consequence of a disease that replaces all GLUT2 with GLUT1?
None of these
All of these
Hyperinsulinemia
Hypoglycemia
Hyperglycemia
Hypoglycemia
GLUT2 have a lower affinity for glucose and is essential for the liver and the pancreas to regulate the blood glucose level. With a lower affinity transporter, glucose will not be taken up immediately by the liver/pancreas while reserving for the high glucose demanding organs (e.g brain, neurons, red blood cells). Therefore, if one were to inherit such disease, extreme hypoglycemia may occur.
Example Question #32 : Enzyme Kinetics And Models
There are at least four types of glucose transporter in the body. GLUT1 and GLUT3 are located in most tissues including the brain and the red blood cells. These glucose transporters rapidly take up glucose from the blood but have the lowest value. GLUT2 is commonly found in the liver and the pancreas. GLUT2 has a lower affinity for glucose but has the highest value. GLUT4 is common in skeletal tissues and in adipose tissues. This transporter is normally not active for uptake unless stimulated by insulin or during exercise.
Sam is performing an experiment and he wants to use the glucose transporter with the lowest value. Which type of glucose transporter should he use?
I. GLUT1
II. GLUT2
III. GLUT3
IV. GLUT4
II only
III only
I and III
I and II
I only
I and III
GLUT1 and GLUT3 have the highest affinity for glucose. The Michaelis constant, is the concentration of the substrate required to reach . The lower the , the higher the affinity is for the substrate.
Example Question #1 : Vmax And Km
You are measuring the activity of an enzyme in solution and notice that enzyme activity increases with increasing substrate concentration to a certain point, after which enzyme activity does not increase even if you add more substrate. What is this called and what can be done to increase activity?
This is called the and adding more enzyme concentration will increase activity.
This is called the maximal velocity and increasing the enzyme concentration will increase activity.
This is called the rate constant and increasing the concentration of the product will increase activity.
This is called the maximal velocity and decreasing the concentration of the production will increase activity.
This is called the rate constant and adding more enzyme will increase activity.
This is called the maximal velocity and increasing the enzyme concentration will increase activity.
The enzyme in this question is said to be saturated with substrate. That means that at any given moment, all of the enzyme in solution is bound to a substrate so that adding more substrate will have no effect. This is referred to as the maximal velocity because the enzymes are working as fast as possible and will not respond to the addition of more substrate. By adding more enzyme, you a providing more active site to bind to more substrate molecules, effectively increasing the velocity of the overall reaction.
Example Question #1 : Vmax And Km
What does a small indicate?
The enzyme has a low affinity for its substrate
That high substrate concentrations are needed to achieve maximum reaction velocity
That the enzyme requires only a small amount of substrate to become saturated
That the enzyme requires a large amount of substrate to become saturated
That the enzyme requires only a small amount of substrate to become saturated
In enzyme kinetics, is the concentration of substrate which allows the enzyme to reach (maximum reaction velocity). A small indicates that only a small amount of substrate is needed for the enzyme to become saturated and thus for the reaction to reach maximum velocity. This also indicates that the enzyme and substrate have high affinity for one another. A large indicates that a large amount of substrate is needed for the enzyme to become saturated and thus for the reaction to reach maximum velocity.
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