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Basic Geometry : How to find the area of a right triangle

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Example Questions

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Example Question #51 : How To Find The Area Of A Right Triangle

Find the area of the triangle.

Possible Answers:

3000

4000

5000

6000

Correct answer:

3000

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Since this is a right triangle, the base and the height are the two leg lengths given.

$\text{Area}=\frac{100\times60}{2}=300$

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Example Question #451 : Triangles

Find the area.

Possible Answers:

1000

800

600

1200

Correct answer:

600

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Since this is a right triangle, the base and the height are the two leg lengths given.

$\text{Area}=\frac{40\times30}{2}=600$

Report an Error

Example Question #452 : Triangles

Find the area.

Possible Answers:

300

180

240

360

Correct answer:

240

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Since this is a right triangle, the base and the height are the two leg lengths given.

$\text{Area}=\frac{40\times12}{2}=240$

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Example Question #1431 : Plane Geometry

Find the area.

Possible Answers:

400

100

800

600

Correct answer:

400

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Since this is a right triangle, the base and the height are the two leg lengths given.

$\text{Area}=\frac{40\times20}{2}=400$

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Example Question #452 : Triangles

Find the area.

Possible Answers:

144

$72\sqrt3$

$36\sqrt3$

Correct answer:

$72\sqrt3$

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

However, the question gives us the length of a height and the length of the hypotenuse. Thus, we will need to use the Pythagorean Theorem to find the length of the base.

$\text{Hypotenuse}^2=\text{base}^2+\text{height}^2$

Now, rewrite the equation to solve for the height.

$\text{height}^2=\text{Hypotenuse}^2-\text{base}^2$

$\text{height}=\sqrt{\text{Hypotenuse}^2-\text{base}^2}$

Plug in the values of the hypotenuse and base to find the height.

$\text{height}=\sqrt{24^2-12^2}=\sqrt{432}=12\sqrt3$

Now, plug the values of the base and the height to find the area.

$\text{Area}=\frac{12\sqrt3\times12}{2}=72\sqrt3$

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Example Question #453 : Triangles

Find the area.

Possible Answers:

0.875

1.350

1.225

0.3125

Correct answer:

0.3125

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Since this is a right triangle, the base and the height are the two leg lengths given.

$\text{Area}=\frac{2.5\times0.25}{2}=0.3125$

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Example Question #451 : Triangles

Find the area.

Possible Answers:

$\frac{169}{}$

$\frac{13\sqrt3}{2}$

$\frac{169\sqrt3}{2}$

169

Correct answer:

$\frac{169\sqrt3}{2}$

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Now, we have the height and the hypotenuse from the question. Use the Pythagorean Theorem to find the length of the base.

$\text{hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{base}^2=\text{hypotenuse}^2-\text{height}^2$

$\text{base}=\sqrt{\text{hypotenuse}^2-\text{height}^2}$

Substitute in the values of the height and hypotenuse.

$\text{base}=\sqrt{26^2-13^2}=\sqrt{507}=13\sqrt3$

Simplify.

$\text{base}=\sqrt{507}$

Reduce.

$\text{base}=13\sqrt3$

Now, substitute in the values of the base and the height to find the area.

$\text{Area}=\frac{13 \times 13\sqrt3}{2}$

Solve.

$\text{Area}=\frac{169\sqrt3}{2}$

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Example Question #454 : Triangles

Find the area.

Possible Answers:

$4\sqrt3$

$2\sqrt3$

Correct answer:

$2\sqrt3$

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Now, we have the height and the hypotenuse from the question. Use the Pythagorean Theorem to find the length of the base.

$\text{hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{base}^2=\text{hypotenuse}^2-\text{height}^2$

$\text{base}=\sqrt{\text{hypotenuse}^2-\text{height}^2}$

Substitute in the values of the height and hypotenuse.

$\text{base}=\sqrt{4^2-2^2}$

Simplify.

$\text{base}=\sqrt{12}$

Reduce.

$\text{base}=2\sqrt3$

Now, substitute in the values of the base and the height to find the area.

$\text{Area}=\frac{2 \times 2\sqrt3}{2}$

Solve.

$\text{Area}=2\sqrt3$

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Example Question #455 : Triangles

Find the area.

Possible Answers:

$\frac{9\sqrt3}{2}$

$18\sqrt3$

$9\sqrt3$

$\frac{9}{2}$

Correct answer:

$\frac{9\sqrt3}{2}$

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Now, we have the height and the hypotenuse from the question. Use the Pythagorean Theorem to find the length of the base.

$\text{hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{base}^2=\text{hypotenuse}^2-\text{height}^2$

$\text{base}=\sqrt{\text{hypotenuse}^2-\text{height}^2}$

Substitute in the values of the height and hypotenuse.

$\text{base}=\sqrt{6^2-3^2}$

Simplify.

$\text{base}=\sqrt{27}$

Reduce.

$\text{base}=3\sqrt3$

Now, substitute in the values of the base and the height to find the area.

$\text{Area}=\frac{3 \times 3\sqrt3}{2}$

Solve.

$\text{Area}\frac{9\sqrt3}{2}$

Report an Error

Example Question #456 : Triangles

Find the area.

Possible Answers:

$4\sqrt3$

$12\sqrt3$

$8\sqrt3$

$15\sqrt3$

Correct answer:

$8\sqrt3$

Explanation:

Recall how to find the area of a triangle:

$\text{Area}=\frac{\text{base}\times\text{height}}{2}$

Now, we have the height and the hypotenuse from the question. Use the Pythagorean Theorem to find the length of the base.

$\text{hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{base}^2=\text{hypotenuse}^2-\text{height}^2$

$\text{base}=\sqrt{\text{hypotenuse}^2-\text{height}^2}$

Substitute in the values of the height and hypotenuse.

$\text{base}=\sqrt{8^2-4^2}$

Simplify.

$\text{base}=\sqrt{48}$

Reduce.

$\text{base}=4\sqrt3$

Now, substitute in the values of the base and the height to find the area.

$\text{Area}=\frac{4 \times 4\sqrt3}{2}$

Solve.

$\text{Area}=8\sqrt3$

Report an Error

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Basic Geometry : How to find the area of a right triangle

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #51 : How To Find The Area Of A Right Triangle

Example Question #451 : Triangles

Example Question #452 : Triangles

Example Question #1431 : Plane Geometry

Example Question #452 : Triangles

Example Question #453 : Triangles

Example Question #451 : Triangles

Example Question #454 : Triangles

Example Question #455 : Triangles

Example Question #456 : Triangles

All Basic Geometry Resources

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