AP Physics 2 : AP Physics 2

Study concepts, example questions & explanations for AP Physics 2

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Example Questions

Example Question #111 : Fluids

Water is flowing through a hose. It comes out of the tap at a pressure of, velocity of , and height of . It leaves the nozzle at a pressure of  and a height of . What is the velocity of the water when it leaves the hose?

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we will use Bernoulli's equation, a simplified form of the law of conservation of energy. It applies to fluids that are incompressible (constant density) and non-viscous.

Bernoulli's equation is:

Where  is pressure,  is density,  is the gravitational constant,  is velocity, and  is the height. 

In our question, state 1 is at the tap and state 2 is at the nozzle. Input the variables from the question into Bernoulli's equation:

Simplify and solve for the final velocity.

Example Question #11 : Bernoulli's Equation

Water is flowing through a horizontal pipe. Water enters the left side of the pipe at a pressure  and a velocity of . It leaves the pipe at a velocity of . What is the pressure of the water when it leaves the pipe?

.

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we will use Bernoulli's equation, a simplified form of the law of conservation of energy. It applies to fluids that are incompressible (constant density) and non-viscous.

Bernoulli's equation is:

 

Where  is pressure,  is density,  is the gravitational constant,  is velocity, and  is the height. In our question, state 1 is at the entrance of the pipe and state 2 is at the exit of the pipe. Both states of the pipe are at the same height because the pipe is horizontal. Input the variables from the question into Bernoulli's equation and solve for the final pressure:

Example Question #11 : Bernoulli's Equation

Water is flowing through a horizontal pipe. Water enters the left side of the pipe at a pressure  and a velocity of . It leaves the pipe at a pressure of . What is the velocity of the water when it leaves the pipe?

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we will use Bernoulli's equation, a simplified form of the law of conservation of energy. It applies to fluids that are incompressible (constant density) and non-viscous.

Bernoulli's equation is:

Where  is pressure,  is density,  is the gravitational constant,  is velocity, and  is the height. 

In our question, state 1 is at the entrance of the pipe and state 2 is at the exit of the pipe. Both states of the pipe are at the same height because the pipe is horizontal. Input the variables from the question into Bernoulli's equation and solve for the final velocity:

 

Example Question #12 : Bernoulli's Equation

As the velocity of a fluid increases, what happens to the pressure? Assume both states of the fluid are at the same height and the pipe has a constant diameter.

Possible Answers:

As velocity increases, the pressure stays the same

As velocity increases, the pressure increases

As velocity increases, the pressure decreases

Velocity has no effect on pressure

Correct answer:

As velocity increases, the pressure decreases

Explanation:

To solve this problem, we will use Bernoulli's equation, a simplified form of the law of conservation of energy. It applies to fluids that are incompressible (constant density) and non-viscous.

Bernoulli's equation is: 

Where  is pressure,  is density,  is the gravitational constant,  is velocity, and  is the height. Since the height of the pipe is constant, we can eliminate the height term leaving us with:

The velocity is increasing, making the velocity term negative. We are subtracting some amount from , therefore , meaning the pressure is decreasing.

Example Question #11 : Bernoulli's Equation

Suppose a physician is considering the flow of blood through a blood vessel. Dissolved within the blood are several important gasses, such as oxygen. If there is a blood clot that is partially obstructing one of the blood vessels, how will the blood's partial pressure of oxygen change as it is flowing past this clot?

Possible Answers:

It will decrease

There is no way to predict how it will change

It depends on the amount of blood in circulation

It will increase

It will not change

Correct answer:

It will decrease

Explanation:

In this question, we're presented with a scenario in which blood is flowing through a blood vessel with a clot. We're asked to determine how the partial pressure of oxygen changes as the blood flows pass the clot. To answer this, we'll need to understand the concepts of the continuity equation, Bernoulli's equation, and partial pressures.

Since the blood is flowing past an obstruction, and because the volume flow rate is the same everywhere, we can use the continuity equation to show the relationship between velocity and area.

What this equation shows is that, when the volume flow rate is constant, the velocity of the fluid is inversely proportional to the area in which it is flowing. When the blood passes through the narrow space caused by the obstruction, it temporarily speeds up and thus has a higher velocity.

Next, we can use the Bernoulli equation to show how the velocity is related to pressure.

In this case, we can assume that the height does not change, and thus we can take the potential energy component out of the equation. What we are left with is an inverse relationship between velocity and pressure. Thus, as the velocity increases, the pressure decreases.

The next thing to do is relate total pressure with partial pressure. Remember that partial pressure refers to the proportion of pressure that a certain gas contributes to the overall pressure when there is a mixture of gasses. For instance, the partial pressure of oxygen in the atmosphere is roughly , meaning that oxygen is responsible for contributing  of the overall pressure of the atmosphere. The expression for partial pressure is as follows.

Again, what this means is that the partial pressure of a certain gas is dependent on both the fraction of that gas out of all other gasses present, and also the total pressure. Even though the proportion of oxygen will remain the same as blood flows pass the clot, the total pressure in that region decreases. Thus, the partial pressure of oxygen in this region will decrease as well.

All in all, let's summarize what happened by bringing it all together. As the blood flows through a narrower space due to the obstruction, its velocity increases. As a result of the increase in velocity, the pressure lessens. And as the pressure decreases, so too does the partial pressure of any of the gasses within that region, including that of oxygen.

Example Question #121 : Fluids

Viscosity is defined loosely as internal friction in a fluid. Which of the following fluids would you expect to have the highest viscosity? 

Possible Answers:

Air 

Gasoline 

Water 

Molasses 

Correct answer:

Molasses 

Explanation:

The correct answer is molasses. Since this liquid is notably thicker and more difficult to move, it is intuitively sensed that is has the highest viscosity of this group of fluids. 

Example Question #121 : Fluids

An object with mass  and volume  and reference area of  is sinking in water with a constant velocity of . What is the drag coefficient of the object?

Possible Answers:

Correct answer:

Explanation:

We will start with Newton's second law:

Since the block is sinking at a constant velocity, we know that the net force is 0:

There are three forces acting on the ball: gravitational, buoyant, and drag. If we designate any downward force as positive, we get:

 (1)

Where:

 (2)

   

Where:

 

 (3)

 (4)

Plugging expressions 2, 3, and 4 into 1, we get:

Now we need to rearranging for the drag coefficient:

Plugging in our values, we get:

Example Question #121 : Fluids

A spherical ball of mass  and radius  is sinking in water. What is the terminal velocity of the ball?

Possible Answers:

Correct answer:

Explanation:

We will start with Newton's second law for this problem:

When the ball reaches terminal velocity, we know that the net force on the ball is equal to 0:

There are three forces acting on the ball: gravitational, buoyant, and drag. If we designate any downward force as positive, we get:

 (1)

Where:

 (2)

   

Where:

 (3)

 (4)

Substituting expressions (2), (3), and (4) into (1), we get:

Now we just need to rearranging for velocity.

We have all of these values, so time to plug and chug:

Example Question #1 : Magnetism And Electromagnetism

There is a particle with a charge of  moving  perpendicular through a magnetic field with a strength of . What is the force on the particle?

Possible Answers:

Correct answer:

Explanation:

The equation for force on a moving charged particle in a magnetic field is

.

Because the charge is moving perpendicularly through the magnetic field, we don't have to worry about the cross product, and the equation becomes simple multiplication. 

Therefore, the force experienced by the particle is 3619N.

Example Question #2 : Magnetism And Electromagnetism

V blv

 

A conductive rod is moving through a region of magnetic field, directed out of the page as diagrammed above. As a result of its motion, the mobile charge in the rod separates, creating an electric potential across the length of the rod. The length of the rod is 0.12m and the magnitude of the magnetic field is 0.022T. If the rod is moving with velocity , what is the magnitude and direction of the potential from one end of the rod to the other?

Possible Answers:

 the top is at a higher potential than the bottom

 the top is at a higher potential than the bottom

 the top is at a higher potential than the bottom

 the top is at a lower potential than the bottom

 the top is at a lower potential than the bottom

Correct answer:

 the top is at a higher potential than the bottom

Explanation:

For a conductor moving in a magnetic field, cutting straight across the field lines, a potential is generated  where  is the potential or EMF,  is the magnetic field strength, and  is the conductor's velocity relative to the field.

As the rod moves, the positive charge feels an upward-directed force by the right-hand rule, and the negative a downward force resulting in the top being at a higher potential than the bottom of the rod.

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