AP Physics 2 : AP Physics 2

Study concepts, example questions & explanations for AP Physics 2

varsity tutors app store varsity tutors android store

Example Questions

Example Question #91 : Optics

The speed of light in a vacuum, , is calculated to be . The speed of light in a diamond is calculated to be . What is the refractive index of diamond?

Possible Answers:

Correct answer:

Explanation:

The definition of refractive index of a medium  is the speed of light in a vacuum divided by the speed of light in the medium:

We have values for  and , so we can plug in our numbers into the equation.

Because we're dividing two values with the same units, our answer is unitless. 

Example Question #511 : Ap Physics 2

Light rays encounter a mystery optical device, resulting in a new distribution of the light waves as shown. Assume the light travels from right to left.

Photo 2 1

What type of reflecting or refracting surface is depicted?

Possible Answers:

Converging lens

Diverging mirror

Converging mirror

Diverging lens

Plane (flat) mirror

Correct answer:

Converging lens

Explanation:

In a converging lens, the light waves pass through it and have their angles altered so that they point closer together than they did before they went through the lens. In the picture, the light waves are diverging from a point until they go into the lens, at which point they no longer diverge from each other. Therefore, this is a converging lens. Because the waves are travelling the same direction the whole time, it can't be the converging or diverging mirrors. If the lens were diverging, they'd be more separated. If it were a plane mirror, the waves would get polarized (they'd have the same phase angle).

Example Question #512 : Ap Physics 2

If a person with near point distance of 20cm observes a fine detailed coin with magnifying glass with an angular magnification of 5, what is the focal length?

Possible Answers:

Correct answer:

Explanation:

Use the formula for focal length.

Solve for focal length by substituting known values.

Example Question #1 : Other Optics Principles

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.Malus law

Unpolarized light passes through a polarizer. It then passes through another at angle  to the first. What percentage of the original intensity was the light coming out of the second polarizer?

Possible Answers:

Correct answer:

Explanation:

Malus law

Using Malus' law.

Since the initial light is unpolarized, there will be no intensity lost.

Example Question #3 : Other Optics Principles

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.Malus law

Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle  to the second. What percentage of the original intensity was the light coming out of the third polarizer?

Possible Answers:

None of these

Correct answer:

Explanation:

Malus law

Use Malus' law.

The light's intensity is reduced by the final two polarizers. It is thus necessary to use Malus' law twice.

Where is the initial intensity after the first polarizer.

is the intensity after the second polarizer.

is the intensity after the third polarizer.

is the angle between the first and second polarizers.

is the angle between the second and third polarizers.

Combining equations:

Plug in values:

Example Question #513 : Ap Physics 2

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.Malus law

Unpolarized light passes through a polarizer. It then passes through another polarizer at angle  to the first, and then another at angle  to the second. What percentage of the original intensity was the light coming out of the third polarizer?

Possible Answers:

None of these

Correct answer:

Explanation:

Malus law

Use Malus' law.

The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.

Where is the initial intensity after the first polarizer.

is the intensity after the second polarizer.

is the intensity after the third polarizer.

is the angle between the first and second polarizers.

is the angle between the second and third polarizers.

Combining equations:

Plug in values:

Example Question #6 : Other Optics Principles

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.

Unpolarized light passes through a polarizer. It then passes through another polarizer at angle  to the first, and then another at angle  to the second. What percentage of the original intensity was the light coming out of the third polarizer?

Possible Answers:

None of these

Correct answer:

Explanation:

Malus law

Use Malus' law.

The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.

Where is the initial intensity after the first polarizer.

is the intensity after the second polarizer.

is the intensity after the third polarizer.

is the angle between the first and second polarizers.

is the angle between the second and third polarizers.

Combine equations:

Plug in values:

Example Question #101 : Optics

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.

Unpolarized light passes through a polarizer. It then passes through another polarizer at angle  to the first, and then another at angle  to the second. What percentage of the original intensity was the light coming out of the second polarizer?

Possible Answers:

None of these

Correct answer:

Explanation:

Malus law

Use Malus' law.

The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.

Where is the initial intensity after the first polarizer.

is the intensity after the second polarizer.

is the intensity after the third polarizer.

is the angle between the first and second polarizers.

is the angle between the second and third polarizers.

Combine equations:

Plug in values:

Example Question #1 : Other Optics Principles

Malus' law:

Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.

Unpolarized light passes through a polarizer. It then passes through another polarizer at angle  to the first, and then another at angle  to the second. What percentage of the original intensity was the light coming out of the third polarizer?

Possible Answers:

None of these

Correct answer:

Explanation:

Malus law

Use Malus' law.

The light's intensity is reduced by the final two polarizers. We will need to use Malus law twice.

Where is the initial intensity after the first polarizer.

is the intensity after the second polarizer.

is the intensity after the third polarizer.

is the angle between the first and second polarizers.

is the angle between the second and third polarizers.

Combine equations:

Plug in values:

Example Question #3 : Other Optics Principles

You are passing a ray of light through clear alcohol to determine properties. You shine the light ray exactly  to the surface of alcohol. 

Suppose that the alcohol surface will completely reflect the incoming light beam like a mirror. At what angle will the angle of reflectance be to the normal of the surface of the alcohol? 

Possible Answers:

Correct answer:

Explanation:

Assuming the alcohol works like a perfect mirror, the angle of reflectance will equal the angle of incidence. Therefore, the angle of reflectance will be 

Learning Tools by Varsity Tutors