All AP Physics 2 Resources
Example Questions
Example Question #91 : Optics
The speed of light in a vacuum, , is calculated to be . The speed of light in a diamond is calculated to be . What is the refractive index of diamond?
The definition of refractive index of a medium is the speed of light in a vacuum divided by the speed of light in the medium:
We have values for and , so we can plug in our numbers into the equation.
Because we're dividing two values with the same units, our answer is unitless.
Example Question #511 : Ap Physics 2
Light rays encounter a mystery optical device, resulting in a new distribution of the light waves as shown. Assume the light travels from right to left.
What type of reflecting or refracting surface is depicted?
Converging lens
Diverging mirror
Converging mirror
Diverging lens
Plane (flat) mirror
Converging lens
In a converging lens, the light waves pass through it and have their angles altered so that they point closer together than they did before they went through the lens. In the picture, the light waves are diverging from a point until they go into the lens, at which point they no longer diverge from each other. Therefore, this is a converging lens. Because the waves are travelling the same direction the whole time, it can't be the converging or diverging mirrors. If the lens were diverging, they'd be more separated. If it were a plane mirror, the waves would get polarized (they'd have the same phase angle).
Example Question #512 : Ap Physics 2
If a person with near point distance of 20cm observes a fine detailed coin with magnifying glass with an angular magnification of 5, what is the focal length?
Use the formula for focal length.
Solve for focal length by substituting known values.
Example Question #1 : Other Optics Principles
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another at angle to the first. What percentage of the original intensity was the light coming out of the second polarizer?
Using Malus' law.
Since the initial light is unpolarized, there will be no intensity lost.
Example Question #3 : Other Optics Principles
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle to the second. What percentage of the original intensity was the light coming out of the third polarizer?
None of these
Use Malus' law.
The light's intensity is reduced by the final two polarizers. It is thus necessary to use Malus' law twice.
Where is the initial intensity after the first polarizer.
is the intensity after the second polarizer.
is the intensity after the third polarizer.
is the angle between the first and second polarizers.
is the angle between the second and third polarizers.
Combining equations:
Plug in values:
Example Question #513 : Ap Physics 2
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle to the second. What percentage of the original intensity was the light coming out of the third polarizer?
None of these
Use Malus' law.
The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.
Where is the initial intensity after the first polarizer.
is the intensity after the second polarizer.
is the intensity after the third polarizer.
is the angle between the first and second polarizers.
is the angle between the second and third polarizers.
Combining equations:
Plug in values:
Example Question #6 : Other Optics Principles
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle to the second. What percentage of the original intensity was the light coming out of the third polarizer?
None of these
Use Malus' law.
The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.
Where is the initial intensity after the first polarizer.
is the intensity after the second polarizer.
is the intensity after the third polarizer.
is the angle between the first and second polarizers.
is the angle between the second and third polarizers.
Combine equations:
Plug in values:
Example Question #101 : Optics
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle to the second. What percentage of the original intensity was the light coming out of the second polarizer?
None of these
Use Malus' law.
The light's intensity is reduced by the final two polarizers. We will need to use Malus' law twice.
Where is the initial intensity after the first polarizer.
is the intensity after the second polarizer.
is the intensity after the third polarizer.
is the angle between the first and second polarizers.
is the angle between the second and third polarizers.
Combine equations:
Plug in values:
Example Question #1 : Other Optics Principles
Malus' law:
Where is the intensity of polarized light that has passed through the polarizer, is the intensity of polarized light before the polarizer, and is the angle between the polarized light and the polarizer.
Unpolarized light passes through a polarizer. It then passes through another polarizer at angle to the first, and then another at angle to the second. What percentage of the original intensity was the light coming out of the third polarizer?
None of these
Use Malus' law.
The light's intensity is reduced by the final two polarizers. We will need to use Malus law twice.
Where is the initial intensity after the first polarizer.
is the intensity after the second polarizer.
is the intensity after the third polarizer.
is the angle between the first and second polarizers.
is the angle between the second and third polarizers.
Combine equations:
Plug in values:
Example Question #3 : Other Optics Principles
You are passing a ray of light through clear alcohol to determine properties. You shine the light ray exactly to the surface of alcohol.
Suppose that the alcohol surface will completely reflect the incoming light beam like a mirror. At what angle will the angle of reflectance be to the normal of the surface of the alcohol?
Assuming the alcohol works like a perfect mirror, the angle of reflectance will equal the angle of incidence. Therefore, the angle of reflectance will be
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