Call Now to Set Up Tutoring:

(888) 888-0446

AP Calculus AB : AP Calculus AB

Study concepts, example questions & explanations for AP Calculus AB

Create An Account

All AP Calculus AB Resources

3 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #12 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The rate of change of the length of an elastic is:}\\&\frac{dl(t)}{dt}=\frac{(17sin(t + 2))}{4}\\&\text{Determine the change in length over the time interval }t=[5,6.5]\end{align*}$

Possible Answers:

5.76

31.12

0.66

12.68

Correct answer:

5.76

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[sin(ax)]=-\frac{cos(ax)}{a}\\&\int_{5}^{6.5}(\frac{(17sin(t + 2))}{4})dt=-\frac{(17cos(t + 2))}{4}|_{5}^{6.5}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{5}^{6.5}(\frac{(17sin(t + 2))}{4})dt=-\frac{(17cos((6.5) + 2))}{4}-(-\frac{(17cos((5) + 2))}{4})\\&\int_{5}^{6.5}(\frac{(17sin(t + 2))}{4})dt=5.76\end{align*}$

Report an Error

Example Question #13 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The flow of water into a tank is given as:}\\&\frac{dV(t)}{dt}=\frac{(57cos(3t))}{8}\\&\text{Find the change in volume over the time interval }t=[1,6]\end{align*}$

Possible Answers:

-4.87

-2.12

-19.92

-0.35

Correct answer:

-2.12

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[cos(ax)]=\frac{sin(ax)}{a}\\&\int_{1}^{6}(\frac{(57cos(3t))}{8})dt=\frac{(19sin(3t))}{8}|_{1}^{6}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{1}^{6}(\frac{(57cos(3t))}{8})dt=\frac{(19sin(3(6)))}{8}-(\frac{(19sin(3(1)))}{8})\\&\int_{1}^{6}(\frac{(57cos(3t))}{8})dt=-2.12\end{align*}$

Report an Error

Example Question #14 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The velocity of a particle is given as:}\\&v(t)=\frac{(12e^{(t)})}{37}\\&\text{Find its change in position over the time interval }t=[0.5,3]\end{align*}$

Possible Answers:

17.94

37.07

0.68

5.98

Correct answer:

5.98

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[e^{ax}]=\frac{e^{ax}}{a}\\&\int_{0.5}^{3}(\frac{(12e^{(t)})}{37})dt=\frac{(12e^{(t)})}{37}|_{0.5}^{3}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{0.5}^{3}(\frac{(12e^{(t)})}{37})dt=\frac{(12e^{((3))})}{37}-(\frac{(12e^{((0.5))})}{37})\\&\int_{0.5}^{3}(\frac{(12e^{(t)})}{37})dt=5.98\end{align*}$

Report an Error

Example Question #15 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The rate of change of the length of an elastic is:}\\&\frac{dl(t)}{dt}=\frac{(73sin(t + 1))}{11}\\&\text{Determine the change in length over the time interval }t=[3,5]\end{align*}$

Possible Answers:

-98.53

-24.63

-62.12

-10.71

Correct answer:

-10.71

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[sin(ax)]=-\frac{cos(ax)}{a}\\&\int_{3}^{5}(\frac{(73sin(t + 1))}{11})dt=-\frac{(73cos(t + 1))}{11}|_{3}^{5}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{3}^{5}(\frac{(73sin(t + 1))}{11})dt=-\frac{(73cos((5) + 1))}{11}-(-\frac{(73cos((3) + 1))}{11})\\&\int_{3}^{5}(\frac{(73sin(t + 1))}{11})dt=-10.71\end{align*}$

Report an Error

Example Question #16 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The rate of change of the length of an elastic is:}\\&\frac{dl(t)}{dt}=\frac{(71sin(3t))}{7}\\&\text{Determine the change in length over the time interval }t=[4,6]\end{align*}$

Possible Answers:

0.62

0.18

0.07

3.16

Correct answer:

0.62

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[sin(ax)]=-\frac{cos(ax)}{a}\\&\int_{4}^{6}(\frac{(71sin(3t))}{7})dt=-\frac{(71cos(3t))}{21}|_{4}^{6}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{4}^{6}(\frac{(71sin(3t))}{7})dt=-\frac{(71cos(3(6)))}{21}-(-\frac{(71cos(3(4)))}{21})\\&\int_{4}^{6}(\frac{(71sin(3t))}{7})dt=0.62\end{align*}$

Report an Error

Example Question #17 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The rate of change of the length of an elastic is:}\\&\frac{dl(t)}{dt}=\frac{(37t)}{2}\\&\text{Determine the change in length over the time interval }t=[3,7]\end{align*}$

Possible Answers:

39.36

1147.00

370.00

58.73

Correct answer:

370.00

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\int_{3}^{7}(\frac{(37t)}{2})dt=\frac{(37t^{2})}{4}|_{3}^{7}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{3}^{7}(\frac{(37t)}{2})dt=\frac{(37(7)^{2})}{4}-(\frac{(37(3)^{2})}{4})\\&\int_{3}^{7}(\frac{(37t)}{2})dt=370.00\end{align*}$

Report an Error

Example Question #21 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The velocity of a particle is given as:}\\&v(t)=\frac{9}{17}\\&\text{Find its change in position over the time interval }t=[3,6.5]\end{align*}$

Possible Answers:

1.85

11.67

0.19

6.67

Correct answer:

1.85

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\int_{3}^{6.5}(\frac{9}{17})dt=\frac{(9t)}{17}|_{3}^{6.5}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{3}^{6.5}(\frac{9}{17})dt=\frac{(9(6.5))}{17}-(\frac{(9(3))}{17})\\&\int_{3}^{6.5}(\frac{9}{17})dt=1.85\end{align*}$

Report an Error

Example Question #21 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\text{The rate of change of the length of an elastic is:}\\&\frac{dl(t)}{dt}=\frac{(50e^{(t)})}{7}\\&\text{Determine the change in length over the time interval }t=[0.5,5.5]\end{align*}$

Possible Answers:

5728.88

186.67

1736.02

275.56

Correct answer:

1736.02

Explanation:

$\begin{align*}&\text{If the function defining a rate of change is known, the total}\\&\text{change over a given interval of time is only a matter of integrating}\\&\text{this rate function over this same time interval. Considering}\\&\text{the function given:}\\&\text{Utilizing integral rules:}\\&\int[e^{ax}]=\frac{e^{ax}}{a}\\&\int_{0.5}^{5.5}(\frac{(50e^{(t)})}{7})dt=\frac{(50e^{(t)})}{7}|_{0.5}^{5.5}\\&\text{Now we just subtract the function value at the lower bound from that of the upper bound:}\\&\int_{0.5}^{5.5}(\frac{(50e^{(t)})}{7})dt=\frac{(50e^{((5.5))})}{7}-(\frac{(50e^{((0.5))})}{7})\\&\int_{0.5}^{5.5}(\frac{(50e^{(t)})}{7})dt=1736.02\end{align*}$

Report an Error

Example Question #23 : Interpretations And Properties Of Definite Integrals

A pot of water begins at a temperature of $20^\circ C$ and is heated at a rate of $\tfrac{10}{(t+1)^2}$ degrees Celsius per minute. What will the temperature of the water be after 4 minutes?

Possible Answers:

$28^\circ C$

$32^\circ C$

$30.5^\circ C$

$25^\circ C$

$24^\circ C$

Correct answer:

$28^\circ C$

Explanation:

Let denote the temperature of the pot after minutes.

The first thing to realize is that the quantity $\frac{-10}{(t+1)^2}$ is the derivative of T(t) . Using the fundamental theorem of Calculus, we know that

$\int_{0}^{4}\frac{10}{(t+1)^2} = T(4) - T(0)$

From there, we just need to solve the integral. Letting u = t+1, du=dt, we have the following:

$\int_{0}^{4}\frac{10}{(t+1)^2}dx = 10\int_{0}^{4} \frac{1}{u^2}du = \frac{-10}{(t+1)}]_0^4 = -2 + 10 = 8$

Where the second equality follows by the power rule, and re-substituting t+1 = u.

Thus, we now have the equation 8 = T(4) - T(0) . Because we know that the water started at $20^\circ C$ , all we need to do is rearrange and substitute.

8 + T(0) = T(4)

8 + 20 = T(4)

28 = T(4)

Yielding our final answer, $28^\circ C$

Report an Error

Example Question #1 : Second Derivatives

What is the concavity of f(x)=6x^4-7x^3+8x^2-9x^2+18x at x=1?

Possible Answers:

Concave Down

Concave Horizontal

Concave Diagonal

Concave Up

No Concavity

Correct answer:

Concave Up

Explanation:

First, find the double derivative of the function given.

You should get f''(x)=72x^2-42x-2 .

Next, plug in x=1 to get f''(1)=28 .

The double derivative is a positive number, which means the concavity is Concave Up.

Report an Error

View AP Calculus AB Tutors

Dylan
Certified Tutor

University of California-Berkeley, Bachelor of Science, Cognitive Science.

View AP Calculus AB Tutors

Samuel
Certified Tutor

York University, Bachelor, Physics. York University, Master's/Graduate, Mathematics and Statistics.

View AP Calculus AB Tutors

Tyrus Julian
Certified Tutor

Purdue University-Main Campus, Bachelor of Science, Aerospace Engineering.

All AP Calculus AB Resources

3 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Dallas Fort Worth, GMAT Tutors in Miami, Algebra Tutors in San Francisco-Bay Area, Algebra Tutors in Seattle, GMAT Tutors in San Diego, Computer Science Tutors in Phoenix, Algebra Tutors in Dallas Fort Worth, Math Tutors in Houston, Algebra Tutors in Los Angeles, Algebra Tutors in Houston

Popular Courses & Classes

GRE Courses & Classes in Washington DC, ACT Courses & Classes in Miami, SAT Courses & Classes in Washington DC, Spanish Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in San Diego, ISEE Courses & Classes in Los Angeles, MCAT Courses & Classes in Houston, MCAT Courses & Classes in Seattle, GRE Courses & Classes in Atlanta, SSAT Courses & Classes in Chicago

Popular Test Prep

ISEE Test Prep in Chicago, GRE Test Prep in Denver, GMAT Test Prep in Dallas Fort Worth, SSAT Test Prep in New York City, MCAT Test Prep in Atlanta, ISEE Test Prep in San Diego, LSAT Test Prep in Houston, GRE Test Prep in Boston, SSAT Test Prep in Phoenix, ACT Test Prep in Phoenix

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Calculus AB : AP Calculus AB

Study concepts, example questions & explanations for AP Calculus AB

All AP Calculus AB Resources

Example Questions

Example Question #12 : Interpretations And Properties Of Definite Integrals

Example Question #13 : Interpretations And Properties Of Definite Integrals

Example Question #14 : Interpretations And Properties Of Definite Integrals

Example Question #15 : Interpretations And Properties Of Definite Integrals

Example Question #16 : Interpretations And Properties Of Definite Integrals

Example Question #17 : Interpretations And Properties Of Definite Integrals

Example Question #21 : Interpretations And Properties Of Definite Integrals

Example Question #21 : Interpretations And Properties Of Definite Integrals

Example Question #23 : Interpretations And Properties Of Definite Integrals

Example Question #1 : Second Derivatives

All AP Calculus AB Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: