All AP Calculus AB Resources
Example Questions
Example Question #166 : Computation Of The Derivative
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Which of the following expressions is equal to ?
Differentiate both sides with respect to :
By the sum rule:
By the chain rule:
Applying some algebra:
Example Question #166 : Computation Of The Derivative
Which of the following is equal to ?
Differentiate both sides with respect to :
Apply the sum, difference, and constant multiple rules:
In the first term, apply the chain rule; in the second, apply the constant multiple rule:
Apply the power rule:
Now apply some algebra:
Example Question #256 : Derivatives
We have three functions,
Find the derivative of
Given that
So now this is a three layer chain rule differentiation. The more functions combine to form the composite function the harder it will be to keep track of the derivative. I find it helpful to lay out each equation and each derivative, so:
Then a three layer chain rule is just the same as a two layer, except... there's one more layer!
It is still the outermost layer evaluated at the inner layers, and then move another layer in and repeat
Example Question #71 : Chain Rule And Implicit Differentiation
Find at with the equation
So with implicit differentiation, you are going to be taking the derivative of every variable, in the entire equation. Every time you take the derivative of a variable, you have it's rate of change multiplied on the right. In this case, dx or dy.
The result of the derivative is:
The first step is to create the term that you are looking to solve for. This is done by dividing the entire equation by to get it on the bottom of the fraction. After distributing this division to each term, the dx in the first term will cancel with itself, and you will be left with one term that is multiplied by . At that point, you want to get the term with onto its own side. This can be accomplished by subtracting the to the right side of the equation.
The result so far:
Then to finish getting on its own, you divide to the right side, ending up with:
So now looking at the question, we know that , so in order to figure out we need to plug into the equation.
This gives us .
So this gives us two possible answers:
Example Question #72 : Chain Rule And Implicit Differentiation
Find the derivative of
So the derivative of a natural log is always equal to or one over whatever is inside the natural log. In this case is inside the natural log, so the derivative of should be:
But since the inside of the natural log is a function as well, this is the chain rule and the derivative of the natural log will be multiplied by the derivative of the inside, in this case , which is .
So the final derivative is
Example Question #73 : Chain Rule And Implicit Differentiation
Compute the derivative of the following expression:
This problem involves using product rule, and chain rule.
By product rule,
Then, using power rule, and ten chain.
Another application of chain rule to get at the angle,
Taking the derivative of the angle and then simplifying, we get
Example Question #74 : Chain Rule And Implicit Differentiation
Find the first derivative of the function:
The derivative of the function is equal to
and was found using the following rules:
, , , ,
Note that the chain rule is used for the exponential function (the secant is the inner function) and for the cosine function (the linear term is the inner function).
Example Question #81 : Chain Rule And Implicit Differentiation
Find the derivative of the function:
The derivative of the function is equal to
and was found using the following rules:
, , ,
Note that the chain rule was used on the natural logarithm derivative and the derivative of the cosine function.
Example Question #82 : Chain Rule And Implicit Differentiation
Compute the second derivative of the following function:
The first step in finding our second derivative is finding the first.
For our function we note that it is a composite function, and therefore requires the use of the chain rule. The chain rule states if then .
In our case this becomes:
To find the second derivative we must take the derivative of this function we've now computed. To do this we will require both the chain rule as stated, and the product rule since our function is of the form , our derivative will be of the form .
Therefore, our second derivative is:
or equivalently,
Example Question #83 : Chain Rule And Implicit Differentiation
Given the relation , find .
None of the other answers
We start by taking the derivative of both sides of the equation, and proceeding as follows,
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