All AP Calculus AB Resources
Example Questions
Example Question #21 : Antiderivatives By Substitution Of Variables
Integrate:
To integrate, the following substitution was made:
Now, we rewrite the integral in terms of u and integrate:
The following rule was used for integration:
Finally, rewrite the final answer in terms of our original x term:
Example Question #231 : Integrals
Evaluate the integral
We can make a u substitution in the following way:
, and therefore
Simplifying the integral, we get
Rewriting in terms of x, we get
Example Question #231 : Integrals
Solve:
To integrate, we must make the following substitution:
Rewriting the integral in terms of u and integrating, we get
The following rule was used for integration:
Replacing u with our original x term, we get
Example Question #21 : Antiderivatives By Substitution Of Variables
Solve:
To integrate, we must make the following substitution:
Rewriting the integral in terms of u and integrating, we get
The following rule was used for integration:
Replacing u with our original x term, we get
Example Question #21 : Antiderivatives By Substitution Of Variables
Calculate:
Rewrite the integrand as follows:
.
The integral can be rewritten as
Now, use -substitution, setting . It follows that
The limits of integration can be rewritten as
The integral becomes
Integrate:
,
the correct response.
Example Question #22 : Antiderivatives By Substitution Of Variables
Evaluate the following integral
The integral can be solved by using a variable substitution
,
Replacing with , we get our final answer, which is
Example Question #23 : Antiderivatives By Substitution Of Variables
Evaluate the following integral
We solve the problem by making a variable substitution
,
The integral then becomes
Substituting for , we get our final answer
Example Question #73 : Techniques Of Antidifferentiation
Solve:
To integrate, it is easiest to break the integral into the sum of two integrals:
To integrate the first integral, we must make the following substitution:
The derivative was found using the rule itself.
Rewriting the first integral in terms of u and integrating, we get
which was found using the rule itself.
Replacing u with our original x term, we get
The second integral is equal to
and was found using the following rule:
Adding our two results, and combining the two constants of integration into a single integration constant, we get
Example Question #76 : Techniques Of Antidifferentiation
Calculate the integral in the following expression:
The simplest path to follow when trying to integrate a lot of trig expressions is often to put everything in terms of sin(x) and cos(x). Doing this for the above expressions yields:
Next, we look for expressions that we know how to integrate, based on the following facts:
And, of course, the simpler derivatives of sin(x) and cos(x).
Looking for these above expressions in our integral, we note that
Breaking this up into two integrals, we see that the second immediately can be simplified into -csc(x) + C. The first, while a bit more tricky, just requires you to realize that sec(x)tan(x) is the derivative of sec(x). Thus, if you use a substitution of variables (u-sub) with u = sec(x), you will get,
and
In this form, it is clear to see that the integral is just where u = sec(x)
Combining our two integrals, we get a final answer of
Example Question #24 : Antiderivatives By Substitution Of Variables
Evaluate the integral
To evaluate the integral, we make a variable substitution for
,
The integral then becomes
Substituting back in for , the final answer is