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Algebra II : Multiplying and Dividing Factorials

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #41 : Multiplying And Dividing Factorials

Multiply the factorials: $0!\cdot 2! \cdot 4!$

Possible Answers:

720

Correct answer:

Explanation:

Identify the values of each factorial. Zero factorial is a special case.

0!=1

$2! = 2\times 1 = 2$

$4! =4\times 3 \times 2\times 1=24$

Multiply all three numbers.

$0!\cdot 2! \cdot 4!=1\cdot2\cdot24 = 48$

The answer is:

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Example Question #42 : Factorials

Simplify the factorials: $\frac{5(3+2)!}{5!\cdot 3!}$

Possible Answers:

$1.186\times 10^{13}$

$\frac{5}{6}$

$\frac{5}{3}$

$\frac{1}{2}$

$\frac{3}{4}$

Correct answer:

$\frac{5}{6}$

Explanation:

Simplify the numerator. Do not distribute the five through the terms inside the parentheses, or it will change the value of the factorial!

$5(3+2)! = 5(5)! = 5[5\cdot 4\cdot 3\cdot 2\cdot 1]$

Simplify the denominator.

$5!\cdot 3! = [5\cdot 4\cdot 3\cdot 2\cdot 1]\cdot [3\cdot 2\cdot 1]$

Divide the numerator with the denominator.

$\frac{5[5\cdot 4\cdot 3\cdot 2\cdot 1]}{[5\cdot 4\cdot 3\cdot 2\cdot 1]\cdot [3\cdot 2\cdot 1]}= \frac{5}{3\cdot 2\cdot 1}= \frac{5}{6}$

The answer is: $\frac{5}{6}$

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Example Question #43 : Factorials

Simplify: $\frac{4(1+3)!}{2(3)!}$

Possible Answers:

$1.74\times 10^{11}$

$2.91\times 10^{10}$

6720

Correct answer:

Explanation:

Simplify the terms in side the parentheses first. Do NOT distribute the four through the binomial or this will change the value of the factorial!

$\frac{4(1+3)!}{2(3)!} = \frac{4(4)!}{2(3\cdot 2\cdot 1)} = \frac{4(4\cdot 3\cdot 2\cdot 1)}{2(3\cdot 2\cdot 1)}$

Notice the there are common terms in the numerator and denominator. Cancel out the terms. The remaining parts are:

$\frac{4\cdot 4}{2} = 8$

The answer is:

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Example Question #44 : Factorials

Multiply: 4(2!)(3!)(2+3!)

Possible Answers:

1935360

384

720

5760

345600

Correct answer:

384

Explanation:

Simplify all the factorials first.

$2!= 2\times 1 = 2$

$3!= 3 \times 2 \times 1 =6$

Substitute each term.

4(2!)(3!)(2+3!) = 4(2)(6)(2+6)

Simplify by order of operations.

48(8) = 384

The answer is: 384

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Example Question #42 : Multiplying And Dividing Factorials

Divide the factorials: $\frac{4(4!)}{3(3!)^2}$

Possible Answers:

$1.92\times 10^7$

$\frac{8}{9}$

$\frac{1}{11340}$

$\frac{1430}{9}$

$\frac{32}{9}$

Correct answer:

$\frac{8}{9}$

Explanation:

Expand the factorials first. Do not distribute the integers inside the parentheses or this will change the value of the factorial.

$\frac{4(4!)}{3(3!)^2}=\frac{4(4\times 3\times 2\times 1)}{3(3\times 2\times 1)^2}=\frac{4(4\times 3\times 2\times 1)}{3(3\times 2\times 1)(3\times 2\times 1)}$

Cross out the common terms in the numerator and denominator.

$\frac{4(4)}{3(3\times 2\times 1)} =\frac{16}{18} = \frac{8}{9}$

The answer is: $\frac{8}{9}$

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Example Question #41 : Factorials

Multiply the factorials: (0!)(2!)(3!)!

Possible Answers:

1440

720

360

Correct answer:

1440

Explanation:

Zero factorial is a special case. It is equal to one.

Expand the other factorials.

$(0!)(2!)(3!)!= (1)(2\times 1)(3 \times 2\times 1)!$

Simplify this expression.

$(1)(2)(6)! = 2(6\times 5\times4\times3\times2\times1) = 2(720) = 1440$

The answer is: 1440

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Example Question #45 : Factorials

Divide the factorials: $\frac{2!}{(0!+0!+0!)!}$

Possible Answers:

$\frac{2}{3}$

$\frac{1}{3}$

$\textup{Undefined}$

$\frac{1}{6}$

Correct answer:

$\frac{1}{3}$

Explanation:

The value of zero factorial is equal to one. This is the special case.

Simplify the expression.

$\frac{2!}{(0!+0!+0!)!} = \frac{2\times 1}{(1+1+1)!} = \frac{2}{3!}$

Write out the terms in the denominator.

$\frac{2}{3!}=\frac{2}{3\times 2\times 1}= \frac{1}{3}$

The answer is: $\frac{1}{3}$

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Example Question #46 : Factorials

Divide the factorials: $\frac{5!}{7!}\div\frac{5}{7}$

Possible Answers:

$\frac{5}{6}$

$\frac{1}{30}$

$\frac{1}{6}$

Correct answer:

$\frac{1}{30}$

Explanation:

Simplify the factorials first. Expand the terms.

$\frac{5!}{7!}\div\frac{5}{7} =\frac{5\times 4\times 3\times 2\times 1 }{7\times 6\times 5\times 4\times 3\times 2\times 1}\div\frac{5}{7}$

Cancel the common terms.

$\frac{1}{42}\div\frac{5}{7}$

Change the sign to multiplication and take the reciprocal of the second fraction.

$\frac{1}{42}\div\frac{5}{7} = \frac{1}{42}\times \frac{7}{5} =\frac{1}{6\times 5} =\frac{1}{30}$

The answer is: $\frac{1}{30}$

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Example Question #51 : Factorials

$\frac{30!\cdot 2!}{30!}$

Possible Answers:

$\frac{1}{4}$

$\frac{2}{29}$

$\frac{30}{29}$

Correct answer:

Explanation:

Simplify the factorials in each fraction by canceling common factors in the numerator and denominator. It would be helpful to write this in expanded form but the factorials are too large for this to be feasible.

$\frac{30!\cdot 2!}{30!}$

$\frac{2\cdot 1}{1}$

$\frac{2}{1}$

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Example Question #52 : Factorials

$\frac{6!}{4!}\div \frac{3!}{5!}$

Possible Answers:

600

$\frac{2}{3}$

$\frac{3}{2}$

$\frac{1}{10}$

Correct answer:

600

Explanation:

First, simplify the factorials in each fraction by canceling common factors in the numerator and denominator. It can help to write it in expanded form.

$\frac{6!}{4!}\div \frac{3!}{5!}$

$\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{4\cdot 3\cdot 2\cdot 1}\div \frac{3\cdot 2\cdot 1}{5\cdot 4\cdot 3\cdot 2\cdot 1}$

$\frac{6\cdot 5}{1}\div \frac{1}{5\cdot 4}$

$\frac{30}{1}\div \frac{1}{20}$

You can now turn this into a multiplication problem and flip the second fraction

$\frac{30}{1}\cdot \frac{20}{1}$

600

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Algebra II : Multiplying and Dividing Factorials

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #41 : Multiplying And Dividing Factorials

Example Question #42 : Factorials

Example Question #43 : Factorials

Example Question #44 : Factorials

Example Question #42 : Multiplying And Dividing Factorials

Example Question #41 : Factorials

Example Question #45 : Factorials

Example Question #46 : Factorials

Example Question #51 : Factorials

Example Question #52 : Factorials

All Algebra II Resources

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