All Algebra II Resources
Example Questions
Example Question #38 : Solving Logarithms
Evaluate:
The expression can be rewritten as a fraction.
The log based 100 can be rewritten as ten squared.
The answer is:
Example Question #35 : Solving Logarithms
Solve the logs:
For logs that are added, the inner quantities can be multiplied with each other to be combined as a single log.
For logs that are subtracted, the inner quantities would each be divided instead.
Rewrite the expression:
The answer is:
Example Question #36 : Solving Logarithms
Evaluate:
Recall that log has a base of ten.
The equation can be rewritten as:
Add 1 on both sides.
To eliminate the log based 10 on the left, we will need to raise both terms as exponents of base 10.
The answer is:
Example Question #41 : Solving Logarithms
Find if .
First, we start with the full equation:
Now we can expand the right side of the equation:
A log of it's own base equals :
Now we add the logs on the right side of the equation by multiplying the terms inside the logs:
Example Question #181 : Logarithms
Solve
By definition, a logarithm of any base that has the term inside is equal to . So we set that term equal to :
Example Question #41 : Solving And Graphing Logarithms
Solve .
When a logarithm equals , the equation in the logarithm equals the logarithms base:
Example Question #42 : Solving And Graphing Logarithms
Solve
Rearranging the logarithm so that we exchange an exponent for the log we get:
Example Question #43 : Solving And Graphing Logarithms
Solve .
First we rearrange the equation, trading the logarithm for an exponent:
And then we solve:
Example Question #3093 : Algebra Ii
Solve .
The first thing we can do is combine the log terms:
Now we can change to exponent form:
We can combine terms and set the equation equal to to have a quadratic equation:
We then solve the equation and get the answers:
and
can't be an answer, because the values inside a log can't be negative, so that leaves us with a single answer of .
Example Question #3093 : Algebra Ii
Solve .
The first thing we can do is combine log terms:
Simplifying the log term gives:
Now we can change the equation to exponent form:
And to solve:
Here, the solution can't be because the term inside a logarithm can't be negative, so the only solution is .