All Algebra II Resources
Example Questions
Example Question #1545 : Algebra Ii
Solve by completing the square.
To complete the square, we need the left side in a form or so that we can factor it into form or .
To do this, we first divide out three on the left-hand side to obtain:
We then take 1/2 of the number in our term (in this case ) to obtain :
We then must add this to each side, but because we are completing the square inside of a parenthesis which is being multiplied by 3, we don't add 36 to each side, but rather 3 times 36, or 108. Therefore, we obtain:
and
Example Question #411 : Intermediate Single Variable Algebra
Solve for .
Once the polynominal is factored out and everything is moved to the left, the equation becomes which does not factor evenly, so you could use the quadratic formula, or complete the square. To complete the square, a coefficient must be found to factor the polynominal into a perfect square. The polynominal factors to so we know that so and . To complete the square you add and subtract from the left side of the equation and strategically place parentheses to get , this simplifies to , which simplifies to ,
Example Question #411 : Intermediate Single Variable Algebra
What is/are the solution(s) to the quadratic equation
.
Hint: Complete the square
When using the complete the square method we will divide the coefficient by two and then square it. This will become our term which we will add to both sides.
In the form,
our , and we will complete the square to find the value.
Therefore we get:
Example Question #24 : Completing The Square
Solve the equation by completing the square:
In order to complete the square, we must get all the terms with x in them to one side of the equation. For this problem, we subtract 9 on both sides in order to yield:
.
Remember that completing the square means that we take half of the coefficient of x (), square this new value (), and add it to both sides of the equation. Our equation now looks like:
The left side is a perfect square polynomial, as we have set it up this way. We factor it as such:
After some cleanup, we arrive at:
In order to solve for x, we must take the square root of both sides of the equation.
Finally, we add 6 to both sides of the equation, and simplify the square root of 27:
Example Question #93 : Solving Quadratic Equations
Put the quadratic equation into vertex form by completing the square.
To complete the square, first set our equation equal to 0:
add 7 to both sides
we want to find the number we can add to both sides so that the left side can be factored as one binomial squared. This binomial must be , since when multiplied by itself you'd end up adding which is what we need. Multiplying:
so the number we want to add to both sides is 6.25
we constructed the left side so we could re-write it as:
simplifying the right gives
now we can subtract 13.25 from both sides to get 0 again:
so our equation is
Example Question #94 : Solving Quadratic Equations
Put into vertex form by completing the square.
To complete the square, first set the equation equal to 0:
subtract 1 from both sides
factor out the 2 on the left side
Now we're trying to figure out what we can add in that space so that the expression in parentheses can be factored as a binomial squared. works as the binomial since we know we will be adding . Squaring this yields:
So the number we want to add is 1. BUT BE CAREFUL! We're adding a 1 to inside those parentheses, so really, we're adding 2, since we distribute that 2. Add 2 to both sides:
we can easily simplify the right side, plus we know that we can factor the left since we set it up to be able to:
now subtract 1 from both sides
so our equation is
Example Question #27 : Completing The Square
Find the roots of this quadratic equation by completing the square:
This equation does not have x intercept (s).
To solve a quadratic with an "a" term of 1 (from the standard form ) by completing the square you must first move over the constant. Next, halve the "b" term, square it, and add to both sides. Then factor the left side and set it equal to the constant. Note that the factor of the quadratic you "made" will always be of the format where the sign is the original sign of the b term.
Move the constant:
Halve the b term, square it, and add to both sides:
Factor the left side and simplify the right:
Take the square root of both sides:
Solve for x:
Example Question #28 : Completing The Square
Josephine wanted to solve the quadratic equation below by completing the square. Her first two steps are shown below:
Equation:
Step 1:
Step 2:
Which of the following equations would best represent the next step in solving the equation?
To solve an equation by completing the square, you must factor the perfect square. The factored form of is . Once the left side of the equation is factored, you may take the square root of both sides.
Example Question #29 : Completing The Square
Re-write this quadratic in vertex form by completing the square:
First, factor out the 2 from the first 2 terms:
add 3 to both sides
inside the parentheses, add
since the 4 was added in the parentheses, it's multiplied by 2. That means we added 8, so add 8 to the other side too
simplify by re-writing the left and adding 3 and 8 on the right
subtract 11 from both sides
Example Question #101 : Solving Quadratic Equations
Ahmed is trying to solve the equation by completing the square. His first two steps are shown below:
Step 1:
Step 2:
Ahmed knows that he needs to add a number to both sides in the next step.
What number should Ahmed add to both sides?
A perfect square has the form .
In this case, , so is or .
To square a fraction, simply square the numerator and the denominator: .