Algebra II : Rational Expressions

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #12 : How To Find A Solution Set

Solve for :

Possible Answers:

There is no solution.

Correct answer:

Explanation:

Subtract 1 from both sides, then multiply all sides by :

A quadratic equation is yielded. We can factor the expression, then set each individual factor to 0.

 

Both of these solutions can be confirmed by substitution.

Example Question #1812 : Algebra Ii

Solve for :

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to consider this equation as two proportions being set equal:

Now, we can cross-multiply.

 

Distribute the  on the right side:

 

Subtract  from both sides to start combining like terms:

Now, this is just a two-step equation. Start by subtracting  from both sides:

Divide by .

Example Question #1813 : Algebra Ii

Solve for :

Possible Answers:

 and 

Imaginary solution

Correct answer:

Explanation:

First, cross-multiply:

Once we simplify we are left with the following two quadratic equations:

In order to solve a quadratic, we need to have it equal to zero and then we can use the quadratic formula. What we need to do now is combine like terms. We can subtract all of the terms on the left from the like terms on the right:

This gives us:

 

Now we can use the quadratic formula:

 

Where the quadratic equation follows the pattern:

Therefore, we can use the terms in our quadratic equation and rewrite the equation as follows:

 

Since we can re-write as and , our answer becomes

Example Question #13 : Solving Rational Expressions

Solve for :

Possible Answers:

Imaginary solution

Correct answer:

Explanation:

Consider this problem as 2 proportions set equal:

Now, we can cross-multiply.

 

Using FOIL (method of simplifying binomials by multiplying following the pattern of first terms, outer terms, inner terms, and last terms), we can multiply the binomials on the right giving us:

In order to solve this equation, we need to have one side of the equation equal to .

Add  to both sides.

Now, we can solve by using the quadratic formula, or by factoring. If we factor, we get:

Solving for each equation leaves us with the following answers:

 and 

Example Question #1814 : Algebra Ii

Solve for :

Possible Answers:

Imaginary solution

Correct answer:

Explanation:

In order to solve, we need to first cross-multiply.

Using FOIL (method of simplifying binomials by multiplying following the pattern of first terms, outer terms, inner terms, and last terms), we can multiply the binomials on the left giving us:

In order to continue solving this quadratic, we need to subtract  from both sides so that the quadratic is equal to .

Now, we can solve using the quadratic formula:

 

Where the quadratic equation follows the pattern:

Therefore, we can use the terms in our quadratic equation and rewrite the equation as follows:

Since we can re-write as  and , our answer becomes:

Example Question #1811 : Algebra Ii

Solving Rational Expressions

Solve the below equation for

Possible Answers:

Correct answer:

Explanation:

When solving two rational expressions that are set equal to each other Cross Multiply. 

In this case we will multiply 4 by the the (3x-2), and also multiply 5 by the (2x+7)

Distribute on both sides to get: 

Subtract 10x from both sides to get: 

Add 8 to both sides to get: 

Divide both sides by 2 to get the final solution: 

 

Finally, double check for extraneaous solutions. Anytime you might get a zero in the bottom of a fraction, this is considered extraneaous because it is a mathematical impossibility to divide by zero. 

In this case there are no x values in the denominators of the original problem, so there are no extraneaous solutions and the only solution will be: 

 

 

Example Question #112 : Solving Rational Expressions

If , what is ?

Possible Answers:

Correct answer:

Explanation:

We start by taking the original function, and replacing all the 's with .  We end up with:

Then we can solve like normal:

 

If we noticed it, we also could have factored the numerator into:

The  terms would have canceled leaving:

Solving that would have been much easier:

Either way, we would still get the exact same answer.

Example Question #17 : Solving Rational Expressions

If , find .

Possible Answers:

Correct answer:

Explanation:

When we first look at this problem, we might be panicking because just plugging  into the function makes us divide by , which we don't like.  For now, let's forget about the denominator and focus on the numerator.  If we look closely, we can see that we can factor the numerator:

Giving us:

As we can see, the  will cancel from the numerator and the denominator, clearing up our "divide by 0" problem:

Now we can solve:

Example Question #21 : Solving Rational Expressions

If  and , what is ?

Possible Answers:

Correct answer:

Explanation:

To begin, let's write the whole problem out plainly:

From here, in order to add the two fractions, we need to get the denominators to be the same.  To do this, we multiply the numerator and denominator of each fraction by the denominator in the OTHER fraction:

Now we can add the fractions together:

Now we can expand using FOIL:

Finally, we collect like terms in the numerator for a final answer of:

Example Question #681 : Intermediate Single Variable Algebra

If , what is ?

Possible Answers:

Correct answer:

Explanation:

First we're going to give the function a quick glance to see if we can simplify by factoring.  We can't, so in order to solve, we're going to replace all the 's with the number we want to solve for, :

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