All Algebra II Resources
Example Questions
Example Question #55 : Solving Quadratic Equations
Find the roots of this quadratic equation:
This equation has complex roots.
None of these.
There are multiple methods to solve quadratics. Use whichever is easiest for the problem.
Solve by factoring:
What numbers will multiply to get and what two numbers will multiply to get -14?
To solve for the roots, set the factors equal to 0 and solve:
Example Question #56 : Solving Quadratic Equations
What are the roots of
To find the roots, or solutions, of this quadratic equation, first factor it.
Recall that when a function is in the form, the factors of a and c when multiplied and added together must equal b.
First, identify factors of 6 that could equal -1. Y
ou have to think of your positive and negative signs here. Remember that and you need to have one positive and one negative number to get -6.
Therefore, after factoring, you should get:
.
Then, set each of those expressions equal to 0.
Therefore, your roots are:
.
Example Question #371 : Intermediate Single Variable Algebra
What are the roots of ?
Since this function is already factored and equal to 0, you can just set each expression equal to 0 to get your roots.
and
.
Example Question #58 : Solving Quadratic Equations
Find a root for the parabolic function:
The equation will need to be simplified to its standard form.
Simplify this equation by using the FOIL method to expand .
Simplify the terms.
The equation becomes:
Distribute the negative two through the parentheses.
Combine like terms.
The equation in standard for becomes:
The standard form for a polynomial is:
Write the quadratic equation.
Substitute the coefficients corresponding to the equation in standard form.
Simplify the radical. The roots will be imaginary.
Simplify the fractions and replace with .
The answer is:
Example Question #59 : Solving Quadratic Equations
Find the roots for the quadratic equation
You can solve this quadratic in many different ways, including by graphing or using the quadratic formula. This particular quadratic can be factored:
we're looking for 2 numbers that add to 5 and multiply to
The numbers that work are 8 and -3:
continue factoring
The factors are and . Set each factor equal to zero:
Example Question #60 : Solving Quadratic Equations
Find the roots of the quadratic equation
You can solve this quadratic equation in many different ways, including by graphing or factoring. You can also use the quadratic formula:
This will give us two answers:
Example Question #212 : Quadratic Equations And Inequalities
Find the roots of the quadratic equation
This quadratic equation can be solved in several ways, including the quadratic equation or by graphing. It can also be solved by factoring:
For this quadratic, we are looking for 2 numbers that add to -19 and multiply to 6x10=60. The numbers satisfying these conditions are -4 and -15:
continue factoring
The factors are and . Set each equal to zero:
Example Question #62 : Finding Roots
Find the roots of the quadratic equation
This quadratic can be solved in several different ways, including by graphing or factoring. You can also use the quadratic formula:
This gives us two answers:
Example Question #213 : Quadratic Equations And Inequalities
Given the equation , find a possible root.
Use the quadratic equation to determine roots of a parabolic function.
The quadratic formula is:
The equation in the form of .
Substitute the known coefficients.
Simplify the equation.
The fraction can be broken into two.
Either or is a possible root.
The answer is:
Example Question #63 : Finding Roots
Find the roots of this quadratic:
None of these
Simplify the equation by dividing by 2:
Find the roots using the quadratic equation:
*Because the discriminant (part under the radical) comes to 0, we know our quadratic will have just one repeated solution.