Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #58 : Transformations Of Linear Functions

Translate the equation  down six units.  What is the new equation?

Possible Answers:

Correct answer:

Explanation:

Use distribution to simplify the equation.

The equation in slope-intercept form is:  

Shift the equation down six units means subtract the y-intercept by six.

The answer is:  

Example Question #59 : Transformations Of Linear Functions

For the function  we will define a linear transformation  such that .  Find the slope and y-intercept of the inverse function  of 

Possible Answers:

   

 



   

 

 

   

 



   

 



Correct answer:

   

 



Explanation:

Use the given function  to find the linear transformation defined by .  

 

First understand that in order to write  we have to take our function  and evaluate it for  and then add  to the result. 

 

 

Adding 

 

Now that we have , compute the inverse . Conventionally we replace the  notation with the  notation and solve for 

 

 

 

Therefore, 

 

 

At this point it's conventional to interchange  and  to write the inverse since we want to express it as a function of 

 

 

 

Therefore the slope is  and the y-intercept is 

 

 

 

 

 

Example Question #59 : Transformations Of Linear Functions

Transform the equation into slope-intercept form.

Possible Answers:

 

Correct answer:

 

Explanation:

In order to take an action from standard form to slope-intercept form you want to make it of the form:

where  is the y-intercept (constant/number without a variable attached to it)

 is the slope and coefficient of the  term

and the equation is set equal to  making it easier to plot graphically.

Given:

 

I. Isolate  on one side of the equation. This is done by shifting either  over to the other side of equation or the  term and the constant to the other side of the equation. It is generally preferable to shift it to make so the  term is positive by itself to simply operations and sign mixups. So in this case both  and  would be subtracted from both sides of the equation leaving:

II. Now that  is isolated by itself you want to simplify the equation so there is no coefficient other than  attached to , so in this case it'd mean dividing both sides by   leaving:

III. Simplify the expression. If you are given fractions that are divisible by each other they can be simplified.

In the case   is simplified to  and   is simplified to  leaving the final answer of:

 

Example Question #1 : Quadratic Functions

Write a quadratic equation having  as the vertex (vertex form of a quadratic equation).

Possible Answers:

Correct answer:

Explanation:

The vertex form of a quadratic equation is given by

Where the vertex is located at

giving us .

Example Question #1 : Quadratic Functions

What are the -intercepts of the equation?

Possible Answers:

There are no -intercepts.

Correct answer:

Explanation:

To find the x-intercepts of the equation, we set the numerator equal to zero.

Example Question #1 : Quadratic Functions

What is the minimum possible value of the expression below?

Possible Answers:

The expression has no minimum value.

Correct answer:

Explanation:

We can determine the lowest possible value of the expression by finding the -coordinate of the vertex of the parabola graphed from the equation . This is done by rewriting the equation in vertex form.

The vertex of the parabola  is the point .

The parabola is concave upward (its quadratic coefficient is positive), so  represents the minimum value of . This is our answer.

Example Question #924 : Algebra Ii

Find the coordinates of the vertex of this quadratic function:

Possible Answers:

Correct answer:

Explanation:

Vertex of quadratic equation  is given by .

For ,

,

so the coordinate of vertex is .

Example Question #925 : Algebra Ii

What are the x-intercepts of the graph of  ? 

Possible Answers:

Correct answer:

Explanation:

Assume y=0,

 , 

Example Question #2 : Quadratic Functions

Find the vertex of the parabola given by the following equation:

Possible Answers:

Correct answer:

Explanation:

In order to find the vertex of a parabola, our first step is to find the x-coordinate of its center. If the equation of a parabola has the following form:

Then the x-coordinate of its center is given by the following formula:

For the parabola described in the problem, a=-2 and b=-12, so our center is at:

Now that we know the x-coordinate of the parabola's center, we can simply plug this value into the function to find the y-coordinate of the vertex:

So the vertex of the parabola given in the problem is at the point

Example Question #1 : Parabolic Functions

Give the minimum value of the function .

Possible Answers:

This function does not have a minimum.

Correct answer:

Explanation:

This is a quadratic function. The -coordinate of the vertex of the parabola can be determined using the formula , setting :

Now evaluate the function at :

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