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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #19 : Inverse Functions

Find the inverse function and simplify your solution:

f(x) = 3x + 21

Possible Answers:

$f^{-1}(x) = \frac{1}{3}x - 7$

$f^{-1}(x) = 3x-7$

$f^{-1}(x) = \frac{1}{3}x + 7$

$f^{-1}(x) = -3x - 21$

$f^{-1}(x) = x -21$

Correct answer:

$f^{-1}(x) = \frac{1}{3}x - 7$

Explanation:

To find the Inverse function of:

f(x) = 3x + 21

1. Replace f(x) with :

y = 3x + 21

2. Switch the variables and :

x = 3y + 21

3. Solve for :

$y = \frac{x - 21}{3}$

4. Simplify:

$y = \frac{1}{3}x - 7$

5. Replace with $f^{-1}(x)$ and the final solution is:

$f^{-1}(x) = \frac{1}{3}x - 7$

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Example Question #19 : Inverse Functions

Find the inverse function and simplify your solution:

f(x) = 3x + 21

Possible Answers:

$f^{-1}(x) = \frac{1}{3}x - 7$

$f^{-1}(x) = 3x-7$

$f^{-1}(x) = \frac{1}{3}x + 7$

$f^{-1}(x) = -3x - 21$

$f^{-1}(x) = x -21$

Correct answer:

$f^{-1}(x) = \frac{1}{3}x - 7$

Explanation:

To find the Inverse function of:

f(x) = 3x + 21

1. Replace f(x) with :

y = 3x + 21

2. Switch the variables and :

x = 3y + 21

3. Solve for :

$y = \frac{x - 21}{3}$

4. Simplify:

$y = \frac{1}{3}x - 7$

5. Replace with $f^{-1}(x)$ and the final solution is:

$f^{-1}(x) = \frac{1}{3}x - 7$

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Example Question #21 : Inverse Functions

Find the the inverse of f(x):

$f(x)=\frac{1}{5}x+2$

Possible Answers:

$f^{-1}(x)=5x-2$

$f^{-1}(x)=5x+10$

$f^{-1}(x)=10x+5$

$f^{-1}(x)=\frac{1}{5}x-2$

$f^{-1}(x)=5x-10$

Correct answer:

$f^{-1}(x)=5x-10$

Explanation:

To find an inverse of a function, switch x and y variables and solve:

$f^{-1}(x)=\frac{1}{5}x+2$

$x=\frac{1}{5}y+2$

Subtract 2 from both sides:

$x-2=\frac{1}{5}y$

Multiply both sides by 5:

5(x-2)=y

Distribute:

5x-10=y

The inverse is:

$f^{-1}(x)=5x-10$

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Example Question #21 : Inverse Functions

Find the inverse of the following function:

$f(x)=\frac{6x+1}{x}, x>0$

Possible Answers:

$f^{-1}(x)=\frac{-6x-1}{-x}$

$f^{-1}(x)=\frac{1}{x-6}$

$f^{-1}(x)=\frac{1}{x+6}$

$f^{-1}(x)=0$

$f^{-1}(x)=-\frac{1}{x-6}$

Correct answer:

$f^{-1}(x)=\frac{1}{x-6}$

Explanation:

To find the inverse function of the function given, we must replace all of the x's with y's and, vice versa:

$x=\frac{6y+1}{y}$

Note that in the problem statement we were given f(x) and not , but they mean the same thing in the sense that is a function of .

Now, we just solve for y:

xy=6y+1

xy-6y=1

y(x-6)=1

$y=\frac{1}{x-6}$

To denote that this is the inverse of the original function, we can use the notation

$f^{-1}(x)=\frac{1}{x-6}$ .

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Example Question #23 : Inverse Functions

What is the inverse function of $f(x)=\frac{x^2 + 4x + 3}{x + 1}$ ?

Possible Answers:

$\frac{x+1}{x^2 + 4x + 3}$

x-3

$\frac{1}{x-1}$

$\frac{(x^2+1)}{(x-3)}$

$\frac{(x^2 + 2)(x-1)}{(x-3)}$

Correct answer:

x-3

Explanation:

Before we begin, it would help to try and simplify the problem. Let's start by factoring the numerator:

x^2 + 4x + 3 = (x+1)(x+3)

$f(x)=\frac{(x+1)(x+3)}{x + 1}$

We can see that the (x+1) terms will cancel, making this problem much easier:

f(x)= x+3

To find the inverse, we can put a where the is currently, put a for the f(x) , and then solve for .

x = y + 3

y = x-3

$f(x)^{-1}=x-3$

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Example Question #741 : Algebra Ii

Find the inverse of $f(x)= \frac{4}{x^2 +3}$ .

Possible Answers:

$3-\sqrt{\frac{4}{x}}$

$\pm\sqrt{\frac{4}{x}-3}$

4(x+2)^2

$\frac{x^{2}+3}{4}$

$\frac{4}{(x+3)(x-1)}$

Correct answer:

$\pm\sqrt{\frac{4}{x}-3}$

Explanation:

First we're going to change the in the function to a , set the function equal to , and solve for :

$x=\frac{4}{y^2 + 3}$

Multiply each side by y^2 + 3 :

x(y^2 + 3)=4

Divide each side by :

$y^2 + 3=\frac{4}{x}$

Subtract from each side:

$y^2 = \frac{4}{x}-3$

Finally, take the square root of each side:

$y=\pm\sqrt{\frac{4}{x}-3}$

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Example Question #742 : Algebra Ii

Find the inverse of the given function:

$y=\frac{x+3}{x+1}$

Possible Answers:

$\frac{3+x}{x+1}$

$\frac{3-x}{x-1}$

$\frac{y+3}{y+1}$

$\frac{x+y+3}{x}$

Correct answer:

$\frac{3-x}{x-1}$

Explanation:

To find the inverse of the function, we must first replace all x in the equation with y, and all y in the equation with x:

$x=\frac{y+3}{y+1}$

Now, solve for y:

x(y+1)=y+3

xy+x=y+3

xy-y=3-x

y(x-1)=3-x

$y=\frac{3-x}{x-1}$

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Example Question #26 : Inverse Functions

Find the inverse function of f(x)=x^3-1 .

Possible Answers:

$y=\sqrt[3]{x+1}$

$y=\sqrt[3]{-x+1}$

$y=\sqrt[3]{x-1}$

There is no inverse for f(x)

Correct answer:

$y=\sqrt[3]{x+1}$

Explanation:

Step 1: To find the inverse of a function f(x) , we will first switch the places of x and y. Wherever we saw y, we put x. Where we see x, we put y.

y=x^3+1

After changing places of letters:

x=y^3+1

Step 2: We want to solve for y, so we ned to get rid of the on the right side.

x-1=y^3

Step 3: We want to find , but we have y^3 . To find , we will take the cube root of both sides

$\sqrt[3]{x-1}=\sqrt[3]{y^3}$

This simplifies to:

$\sqrt[3]{x-1}=y$

The inverse function of f(x) is $\sqrt[3]{x-1}=y$

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Example Question #743 : Algebra Ii

What is the inverse for the function $y=\frac{x-7}{8}$

Possible Answers:

y=8x+7

y=x+7

$y=\frac{8}{x-7}$

Inverse does not exist

y=8x-7

Correct answer:

y=8x+7

Explanation:

To find the inverse of a function switch the position of x and y and solve to y.

$x=\frac{y-7}{8}\Rightarrow8x=y-7\Rightarrow8x+7=y$

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Example Question #28 : Inverse Functions

Find the inverse of: y=4(x-6)

Possible Answers:

y=-4x+24

$y=\frac{1}{4}x+\frac{2}{3}$

$y=-\frac{1}{4}x+6$

y=-4x-24

$y=\frac{1}{4}x+6$

Correct answer:

$y=\frac{1}{4}x+6$

Explanation:

Interchange the x and y-variables.

x=4(y-6)

Solve for y. Distribute the constant through the binomial.

x=4y-24

Add 24 on both sides.

x+24=4y-24+24

The equation becomes:

x+24=4y

Divide by four on both sides.

$\frac{x+24}{4}=\frac{4y}{4}$

Simplify both sides.

The answer is: $y=\frac{1}{4}x+6$

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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #19 : Inverse Functions

Example Question #19 : Inverse Functions

Example Question #21 : Inverse Functions

Example Question #21 : Inverse Functions

Example Question #23 : Inverse Functions

Example Question #741 : Algebra Ii

Example Question #742 : Algebra Ii

Example Question #26 : Inverse Functions

Example Question #743 : Algebra Ii

Example Question #28 : Inverse Functions

All Algebra II Resources

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