All Algebra II Resources
Example Questions
Example Question #3 : Imaginary Numbers
What is the absolute value of
The absolute value is a measure of the distance of a point from the origin. Using the pythagorean distance formula to calculate this distance.
Example Question #1 : Basic Operations With Complex Numbers
Consider the following definitions of imaginary numbers:
Then,
Example Question #2021 : Mathematical Relationships And Basic Graphs
Simplify the expression.
None of the other answer choices are correct.
Combine like terms. Treat as if it were any other variable.
Substitute to eliminate .
Simplify.
Example Question #1 : Basic Operations With Complex Numbers
What is the value of ?
When dealing with imaginary numbers, we multiply by foiling as we do with binomials. When we do this we get the expression below:
Since we know that we get which gives us .
Example Question #1 : Basic Operations With Complex Numbers
What is the value of ?
Recall that the definition of imaginary numbers gives that and thus that . Therefore, we can use Exponent Rules to write
Example Question #2022 : Mathematical Relationships And Basic Graphs
Find .
Multiply the numerator and denominator by the numerator's complex conjugate.
Reduce/simplify.
Example Question #2023 : Mathematical Relationships And Basic Graphs
Subtract:
This is essentially the following expression after translation:
Now add the real parts together for a sum of , and add the imaginary parts for a sum of .
Example Question #2024 : Mathematical Relationships And Basic Graphs
Multiply:
Answer must be in standard form.
The first step is to distribute which gives us:
which is in standard form.
Example Question #1 : Complex Numbers
Add:
When adding complex numbers, add the real parts and the imaginary parts separately to get another complex number in standard form.
Adding the real parts gives , and adding the imaginary parts gives .
Example Question #101 : Classifying Algebraic Functions
Divide:
The answer must be in standard form.
Multiply both the numerator and the denominator by the conjugate of the denominator which is which results in
The numerator after simplification give us
The denominator is equal to
Hence, the final answer in standard form =
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