The range of the numbers is the difference between the largest and smallest numbers.

The largest number is:  \(\displaystyle -7\)

The smallest number is:  \(\displaystyle -26\)

Subtract the quantity of both numbers.

\(\displaystyle (-7)-(-26) = -7+26=19\)

The answer is:  \(\displaystyle 19\)

The range is the difference between the highest and lowest numbers.

Identify the highest and lowest numbers.

The highest number is:  \(\displaystyle 31\)

The lowest number is:  \(\displaystyle -26\)

Subtract both numbers.

\(\displaystyle 31-(-26) = 31+26 = 57\)

The answer is:  \(\displaystyle 57\)

The range can be found by subtracting the smallest value from the largest value.

\(\displaystyle 8.5-3\)

\(\displaystyle 5.5\)

Solution: 5.5

The range corresponds the lowest and highest values in a data set. In this case, that corresponds to \(\displaystyle 1\) and \(\displaystyle 26\). \(\displaystyle 10\) corresponds to the median. \(\displaystyle 11.7\) corresponds to the mean. \(\displaystyle 2-12\) corresponds to the first and last numbers in the set. Each of these options are incorrect. 

\(\displaystyle \small mean=\frac{\sum n}{n}\)

where n equals the number of events.

\(\displaystyle \small 12=\frac{14+11+10+8+x}{5}\)

\(\displaystyle \small 60=14+11+10+8+x=43+x\)

\(\displaystyle \small x=17\)

First we need to find the values of the function: f(2) = 3 * 2 + 2 = 8, f(3) = 11, f(4) = 14, f(5) = 17, and f(6) = 20. Then we can take the average of the five numbers:

average = (8 + 11 + 14 + 17 + 20) / 5 = 14

To answer this question, you must first calculate John's total points from the four exams. The total points will be equal to four times the original average:

\(\displaystyle 94 * 4 = 376\)

Now, if the 89 is removed, his new total will be:

\(\displaystyle 376 - 89 = 287\)

With the score dropped, his new total number of exams is 3. Therefore, the new average is:

\(\displaystyle \frac{287}{3} = 95.6666667\)

Round this up to 95.67.

To solve this, first calculate the total number of points that Isidore has earned. To find this total, multiply his original average by the original number of exams:

\(\displaystyle 88 * 5 = 440\)

Then, to this you must add his new scores to get the new total:

\(\displaystyle 440 + 77 + 103 = 620\)

After taking the two new exams, he has 7 total exams. Therefore, his average is:

\(\displaystyle \frac{620}{7} = 88.57142857142857\)

This rounds to an 88.57.

To calculate the mean, you will need to figure out each person's height. Start with what we know.

Patrick is 67 inches tall: \(\displaystyle P=67\).

Mike is three inches shorter than Patrick: \(\displaystyle M=P-3=67-3=64\).

Sally is five inches taller than Mike: \(\displaystyle S=M+5=64+5=69\).

Find the sum of their heights:

\(\displaystyle 64+67+69 = 200\)

Their average height is therefore:

\(\displaystyle \frac{200}{3} = 66.67\)

To answer this, you need to know the total inches of all the plants. You must multiply the number of each type by its respective height:

\(\displaystyle 6*55 =330\)

\(\displaystyle 12 * 70 =840\)

\(\displaystyle 3*80 =240\)

Then, add these together:

\(\displaystyle 330+840+240=1410\)

Now, the total number of plants is:

\(\displaystyle 6+12+3=21\)

The mean (or average) of this group is:

\(\displaystyle \frac{1410}{21}=67.14285714285714\)

Round this to the nearest hundreth to get 67.14 inches.