Substitute  and  for  and , respectively, and solve the resulting system of linear equations:

Multiply the first equation by 2, and the second by 3, on both sides, then add:

Back-solve:

We need to find both  and  to ensure a solution exists. By substituting back:

and

We check this solution in both equations:

 - true.

 - true.

 is the solution, and , the correct choice.

Given the function , the vertical asymptote can be found by observing that a logarithm cannot be taken of a number that is not positive. Therefore, it must hold that , or, equivalently,  and that the graph of  will never cross the vertical line . That makes  the vertical asymptote, so it follows that the graph with vertical asymptote  will have  in the  position. The only choice that meets this criterion is

All of the functions are of the form . To find the -intercept of such a function, we can set  and solve for :

Since we are looking for a function whose graph has -intercept , the equation here becomes , and we can examine each of the functions by finding the value of .

:

: 

: 

: 

All four choices fit the criterion.

All of the functions take the form 

for some integer . To find the choice that has -intercept , set  and , and solve for :

In exponential form:

The correct choice is .

Set  and evaluate  to find the -coordinate of the -intercept.

Rewrite in exponential form:

.

The -intercept is .

Since , the definition of  can be rewritten as follows:

Since , the definition of  can be rewritten as follows:

First, we need to find the -coordinate of the point at which the graphs of  and  meet by setting 

Since the common logarithms of the two polynomials are equal, we can set the polynomials themselves equal, then solve:

However, if we evaluate , the expression becomes

,

which is undefined, since a negative number cannot have a logarithm.

Consequently, the two graphs do not intersect.

All of the functions are of the form . To find the -intercept of a function ,  we can set  and solve for :

.

Since we are looking for a function whose graph has -intercept , the equation here becomes , and we can examine each of the functions by finding the value of  and seeing which case yields this result.

:

:

:

:

The graph of  has -intercept  and is the correct choice.

The -intercept of the graph of  can befound by setting  and solving for :

Rewritten in exponential form:

The -intercept of the graph of  is .

The -intercept of the graph of  can be found by evaluating 

The -intercept of the graph of  is .

If  and  are the - and -intercepts, respectively, of a line, the slope of the line is . Substituting  and , this is

.

Setting  and  in the slope-intercept form of the equation of a line:

Since , the definition of  can be rewritten as follows:

 . 

Find the -coordinate of the point at which the graphs of  and  meet by setting 

Since the common logarithms of the two polynomials are equal, we can set the polynomials themselves equal, then solve:

The quadradic trinomial can be "reverse-FOILed" by noting that 2 and 6 have  product 12 and sum 8:

Either , in which case 

or

, in which case 

Note, however, that we can eliminate  as a possible -value, since

,

an undefined quantity since negative numbers do not have logarithms. 

Since 

and 

,

 is the correct -value, and  is the correct -value.

This point has an x-coordinate of 8, so we can figure out what y is just by plugging in 8 for x:

This can be evaluated using a calculator, or just by understanding what a logarithm means.

This is essentially asking "2 to what power gives us 8," which is 3.