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Advanced Geometry : Coordinate Geometry

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Example Questions

Example Question #51 : Coordinate Geometry

Give the -coordinate of the -intercept of the graph of the function

$f(x) = 2 \cdot 10 ^{x} - 8$

Possible Answers:

10,000

$\log 4$

Correct answer:

$\log 4$

Explanation:

The -intercept(s) of the graph of f(x) are the point(s) at which it intersects the -axis. The -coordinate of each is 0,; their -coordinate(s) are those value(s) of for which f(x) = 0 , so set up, and solve for , the equation:

f(x)= 0

$2 \cdot 10 ^{x} - 8 = 0$

Add 8 to both sides:

$2 \cdot 10 ^{x} - 8 + 8 = 0 + 8$

$2 \cdot 10 ^{x} = 8$

Divide both sides by 2:

$\frac{2 \cdot 10 ^{x}}{2} =\frac{ 8}{2}$

$10 ^{x} =4$

Take the common logarithm of both sides to eliminate the base:

$\log 10 ^{x} =\log 4$

$x=\log 4$

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Example Question #52 : Coordinate Geometry

Give the domain of the function $f(x) = 2e^{x-3}- 7$ .

Possible Answers:

$\left \{ x|x \ge -7\right \}$

The set of all real numbers

$\left \{ x|x> -3\right \}$

$\left \{ x|x> -7\right \}$

$\left \{ x|x \ge -3\right \}$

Correct answer:

The set of all real numbers

Explanation:

Let $g(x) = e^{x}$ . This function is defined for any real number , so the domain of g(x) is the set of all real numbers. In terms of g(x) ,

f(x) = 2g(x-3) - 7

Since g(x) is defined for all real , so is g(x-3) ; it follows that f(x) is as well. The correct domain is the set of all real numbers.

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Example Question #51 : Graphing

Give the range of the function $f(x) = 2e^{x-3}- 7$ .

Possible Answers:

$[-7, \infty )$

The set of all real numbers

$(-3, \infty )$

$[-3, \infty )$

$(-7, \infty )$

Correct answer:

$(-7, \infty )$

Explanation:

Since a positive number raised to any power is equal to a positive number,

$e^{x-3} > 0$

Applying the properties of inequality, we see that

$2 \cdot e^{x-3} > 2 \cdot 0$

$2 e^{x-3} > 0$

$2 e^{x-3} -7 > 0 - 7$

$2 e^{x-3} -7 > - 7$

f(x) > - 7 ,

and the range of f(x) is the set $(-7, \infty )$ .

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Example Question #51 : Graphing

What are the possible values of if the parabola of the quadratic function $f (x) = Ax^{2} + 4x- 2$ is concave upward and does not intersect the -axis?

Possible Answers:

-2 < A < 0

-2 < A < 4

A > 4

The parabola cannot exist for any value of .

A > -2

Correct answer:

The parabola cannot exist for any value of .

Explanation:

If the graph of $f (x) = Ax^{2} + 4x- 2$ is concave upward, then A > 0 .

If the graph does not intersect the -axis, then $Ax^{2} + 4x- 2 = 0$ has no real solution, and the discriminant $4^{2} - 4 \cdot A \cdot \left ( -2\right )$ is negative:

$4^{2} - 4 \cdot A \cdot \left ( -2\right ) < 0$

16 +8 A < 0

16 +8 A - 16 < 0 - 16

8 A < - 16

$8 A \div 8< - 16 \div 8$

A < -2

For the parabola to have both characteristics, it must be true that A < -2 and A > 0 , but these two events are mutually exclusive. Therefore, the parabola cannot exist.

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Example Question #991 : Gmat Quantitative Reasoning

Which of the following equations has as its graph a vertical parabola with line of symmetry x = 7 ?

Possible Answers:

$f(x)=7x^{2} +140$

$f(x)=7x^{2}-49x+140$

$f(x)=7x^{2}+98x+140$

$f(x)=7x^{2}-98x+140$

$f(x)= 7x^{2}+49x+140$

Correct answer:

$f(x)=7x^{2}-98x+140$

Explanation:

The graph of $f(x)= Ax^{2}+Bx+ C$ has as its line of symmetry the vertical line of the equation

$x=- \frac{B}{2A}$

Since A=7 in each choice, we want to find such that

$7=- \frac{B}{2A} = - \frac{B}{2(7)} = - \frac{B}{14}$

$- \frac{B}{14} = 7$

$B = 7\cdot (-14)=-98$

so the correct choice is $f(x)=7x^{2}-98x+140$ .

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Example Question #52 : Graphing

Which of the following equations has as its graph a concave-right horizontal parabola?

Possible Answers:

None of the other responses gives a correct answer.

$x=- 7y^{2}- 4y+13$

$y=- 7x^{2}- 4x+13$

$y= 7x^{2}- 4x+13$

$x=7y^{2}- 4y+13$

Correct answer:

$x=7y^{2}- 4y+13$

Explanation:

A horizontal parabola has as its equation, in standard form,

$x= Ay^{2}+ By+ C$ ,

with A,B,C real, nonzero.

Its orientation depends on the sign of . In the equation of a concave-right parabola, is positive, so the correct choice is $x=7y^{2}- 4y+13$ .

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Example Question #53 : Graphing

The graphs of the functions f(x) and g(x) have the same line of symmetry.

If we define $f(x) = 2x^{2}+ 4x+7$ , which of the following is a possible definition of g(x) ?

Possible Answers:

$g(x) = x^{2}+ 4x+7$

$g(x) = 4x^{2}+8x+7$

None of the other responses gives a correct answer.

$g(x) = 2x^{2}+ 8x+7$

$g(x) = 2x^{2}-4x-7$

Correct answer:

$g(x) = 4x^{2}+8x+7$

Explanation:

The graph of a function of the form $f(x)= Ax^{2}+Bx+C$ - a quadratic function - is a vertical parabola with line of symmetry $x= - \frac{B}{2A}$ .

The graph of the function $f(x) = 2x^{2}+ 4x+7$ therefore has line of symmetry

$x= - \frac{4}{2 (2)}$ , or x = -1

We examine all four definitions of to find one with this line of symmetry.

$g(x) = 2x^{2}-4x-7$ :

$x= - \frac{-4}{2 (2)}$ , or x = 1

$g(x) = x^{2}+ 4x+7$ :

$x= - \frac{ 4}{2 (1)}$ , or x = -2

$g(x) = 2x^{2}+ 8x+7$

$x= - \frac{ 8}{2 (2)}$ , or x = -2

$g(x) = 4x^{2}+8x+7$

$x= - \frac{ 8}{2 (4)}$ , or x = -1

Since the graph of the function $g(x) = 4x^{2}+8x+7$ has the same line of symmetry as that of the function $f(x) = 2x^{2}+ 4x+7$ , that is the correct choice.

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Example Question #51 : Coordinate Geometry

Give the -coordinate of a point at which the graphs of the equations

$y= x^{2}+ 2x- 7$

and

$y = 2x^{2}- 6x+5$

intersect.

Possible Answers:

Correct answer:

Explanation:

We can set the two quadratic expressions equal to each other and solve for .

$y= x^{2}+ 2x- 7$ and $y = 2x^{2}- 6x+5$ , so

$2x^{2}- 6x+5 = x^{2}+ 2x- 7$

$2x^{2}- 6x+5 -( x^{2}+ 2x- 7)= x^{2}+ 2x- 7 -( x^{2}+ 2x- 7)$

$2x^{2}- 6x+5 - x^{2}- 2x+ 7=0$

$x^{2}- 8x+12=0$

(x-2)(x-6) = 0

The -coordinates of the points of intersection are 2 and 6. To find the -coordinates, substitute in either equation:

$y= x^{2}+ 2x- 7$

$y= 2^{2}+ 2 \cdot 2 - 7$

y= 4+4 - 7

y=1

One point of intersection is (2,1) .

$y= x^{2}+ 2x- 7$

$y= 6^{2}+ 2 \cdot 6 - 7$

y= 36+ 12 - 7

y = 41

The other point of intersection is (6,41) .

1 is not among the choices, but 41 is, so this is the correct response.

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Example Question #995 : Gmat Quantitative Reasoning

Give the set of intercepts of the graph of the function $f(x)= \frac{1}{7} (x-7)^{2}$ .

Possible Answers:

$\left \{ (7,0), (0,-7),(0,7) \right \}$

$\left \{ (-7,0), (0,7) \right \}$

$\left \{ (7,0), (0,7) \right \}$

$\left \{ (7,0), (0,-7) \right \}$

$\left \{ (-7,0), (0,-7),(0,7) \right \}$

Correct answer:

$\left \{ (7,0), (0,7) \right \}$

Explanation:

The -intercepts, if any exist, can be found by setting f(x) = 0 :

$f(x)= \frac{1}{7} (x-7)^{2} = 0$

$\frac{1}{7} (x-7)^{2} \cdot 7 = 0\cdot 7$

$(x-7)^{2} = 0$

x-7 = 0

x= 7

The only -intercept is (7,0) .

The -intercept can be found by substituting 0 for :

$f(0)= \frac{1}{7} (0-7)^{2} = \frac{1}{7} ( -7)^{2}= \frac{1}{7} \cdot 49 = 7$

The -intercept is (0,7) .

The correct set of intercepts is $\left \{ (7,0), (0,7) \right \}$ .

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Example Question #996 : Gmat Quantitative Reasoning

Give the -coordinate of a point of intersection of the graphs of the functions

$f(x) = x^{2}- 4x+ 7$

and

g(x) = 4x .

Possible Answers:

Correct answer:

Explanation:

The system of equations can be rewritten as

$y= x^{2}- 4x+ 7$

y = 4x .

We can set the two expressions in equal to each other and solve:

$x^{2}- 4x+ 7 = 4x$

$x^{2}- 8x+ 7 =0$

(x-1)(x-7)= 0

x= 1,x=7

We can substitute back into the equation y = 4x , and see that either y = 4 or y = 28 . The latter value is the correct choice.

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Advanced Geometry : Coordinate Geometry

Study concepts, example questions & explanations for Advanced Geometry

All Advanced Geometry Resources

Example Questions

Example Question #51 : Coordinate Geometry

Example Question #52 : Coordinate Geometry

Example Question #51 : Graphing

Example Question #51 : Graphing

Example Question #991 : Gmat Quantitative Reasoning

Example Question #52 : Graphing

Example Question #53 : Graphing

Example Question #51 : Coordinate Geometry

Example Question #995 : Gmat Quantitative Reasoning

Example Question #996 : Gmat Quantitative Reasoning

All Advanced Geometry Resources

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