ACT Science : How to find experimental design in biology

Study concepts, example questions & explanations for ACT Science

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Example Questions

Example Question #531 : Act Science

     Invasive species lack the natural competitors in a given area to properly regulate population growth and development. Myriophyllum spicatum is a Eurasian milfoil. It was first used in the United States as an aesthetic for aquatic fish tanks. Later, it was accidentally introduced into local ponds and lakes where it became a dominant invasive species and has began to choke out native and naturally occurring plant life. To make matters worse, phosphorus-rich fertilizers and cleaners have contaminated many freshwater biomes due to runoff and pollution. As a result, many standing freshwater pools contain heavy amounts of phosphorus. These species readily utilize the phosphorus and have become nearly unmanageable. Two ecologists express their views on how to control the invasive population.

Ecologist 1

     The best way to control the problem is to limit the nutrients in the biome. If the nutrients are controlled then the plants will be unable to grow and flourish. After several generations, the nutrients will be depleted and the plant species will become more manageable or disappear altogether.

Ecologist 2

     The best way to control the vegetation would be to physically cut and remove it from the biome. Seasonal cuttings would minimize the population and decrease reproductive success. Furthermore, any nutrients contained in the decomposing plant litter would be removed with the waste. Therefore, after several sweeps the plants would be removed altogether.

The ecologists decide to study the lake together. They choose to study three other local lakes with the same issues in order to get a representative sample. They notice a small stream running adjacent to the lakes. Should the researchers sample the stream as well?

Possible Answers:

No, because the stream does not experience nutrient fluctuations caused by winter turnover and icing.

No, the differing mechanics of the two systems are incomparable to one another.

Yes, the stream may add valuable insight.

Yes, the stream may contain a similiar invasive species for a comparative study.

Correct answer:

No, the differing mechanics of the two systems are incomparable to one another.

Explanation:

No, the differing mechanics of the two systems are incomparable to one another.

This is the only correct choice because the differing variables of each system make them incomparable. These differences exceed the choice related to turnover and icing. While these are important processes in standing lakes they are not the only factors collaborating with this phenomenon. Standing lakes and ponds often act as biological sinks for nutrients and wastes. A moving stream does not contain the same components and cannot be used in a study of an invasive species that inhabits standing, freshwater biomes.

Example Question #532 : Act Science

     Invasive species lack the natural competitors in a given area to properly regulate population growth and development. Myriophyllum spicatum is a Eurasian milfoil. It was first used in the United States as an aesthetic for aquatic fish tanks. Later, it was accidentally introduced into local ponds and lakes where it became a dominant invasive species and has began to choke out native and naturally occurring plant life. To make matters worse, phosphorus-rich fertilizers and cleaners have contaminated many freshwater biomes due to runoff and pollution. As a result, many standing freshwater pools contain heavy amounts of phosphorus. These species readily utilize the phosphorus and have become nearly unmanageable. Two ecologists express their views on how to control the invasive population.

Ecologist 1

     The best way to control the problem is to limit the nutrients in the biome. If the nutrients are controlled then the plants will be unable to grow and flourish. After several generations, the nutrients will be depleted and the plant species will become more manageable or disappear altogether.

Ecologist 2

     The best way to control the vegetation would be to physically cut and remove it from the biome. Seasonal cuttings would minimize the population and decrease reproductive success. Furthermore, any nutrients contained in the decomposing plant litter would be removed with the waste. Therefore, after several sweeps the plants would be removed altogether.

A field researcher suggests using copper sulfate as a herbicide to introduce to the lake and kill off the invasive species completely. Which ecologist would agree with this idea?

Possible Answers:

Both

Ecologist 2

Ecologist 1

Neither

Correct answer:

Neither

Explanation:

Neither ecologist would agree to this idea. The idea centers on introducing yet another component to the biome to control an invasive population. Both ecologists present management procedures that aim at stopping pollution or cutting out the invasive species. The addition of harsh chemical herbicides would not be supported.

Example Question #533 : Biology

     Osmoregulation is a necessary function to maintain homeostasis in organisms. Fish gills form the boundary between fish body fluid and environmental conditions. The regulation of water transport across barrier epithelial membranes in gills is assisted by membrane composition and affected by solute concentration on either side of the membrane. Fish body fluids are isotonic and have compositions of about 300 milliosmoles of solutes per liter. Freshwater environments are hypotonic and typically have compositions of about 1 milliosmole of solutes per liter. Saltwater environments are hypertonic and typically have a composition of about 1,000 milliosmoles of solutes per liter. Based on observed osmoregulation across varying concentration gradients, it is expected that gills exposed to isotonic solutions maintain steady water weight, while those exposed to hypotonic solutions increase in water weight, and those exposed to hypertonic solutions decreased in water weight.

Study 1

     Gills dissected from a fish were exposed to different ambient environments of salinity including an isotonic control solution (301.5 milliosmoles), a hypotonic solution (1.5 milliosmoles), and a hypertonic solution (601.5 milliosmoles). Percent water weight change between treatments was observed and calculated.

Which of the treatment groups could be considered as an analog for a saltwater environment?

Possible Answers:

1.5 milliosmole solution

301.5 milliosmole solution

1001.5 milliosmole solution

None of the choices are correct.

Correct answer:

1001.5 milliosmole solution

Explanation:

The 1001.5 milliosmole hypertonic solution is most closely related to the tonicity of saltwater. The solute composition of this laboratory solution is closely related to and meant to represent the characteristics of saltwater.

Example Question #534 : Biology

     Osmoregulation is a necessary function to maintain homeostasis in organisms. Fish gills form the boundary between fish body fluid and environmental conditions. The regulation of water transport across barrier epithelial membranes in gills is assisted by membrane composition and affected by solute concentration on either side of the membrane. Fish body fluids are isotonic and have compositions of about 300 milliosmoles of solutes per liter. Freshwater environments are hypotonic and typically have compositions of about 1 milliosmole of solutes per liter. Saltwater environments are hypertonic and typically have a composition of about 1,000 milliosmoles of solutes per liter. Based on observed osmoregulation across varying concentration gradients, it is expected that gills exposed to isotonic solutions maintain steady water weight, while those exposed to hypotonic solutions increase in water weight, and those exposed to hypertonic solutions decreased in water weight.

Study 1

     Gills dissected from a fish were exposed to different ambient environments of salinity including an isotonic control solution (301.5 milliosmoles), a hypotonic solution (1.5 milliosmoles), and a hypertonic solution (601.5 milliosmoles). Percent water weight change between treatments was observed and calculated.

Which of the treatment groups could be considered as an analog for a freshwater environment?

Possible Answers:

301.5 milliosmole solution

1.5 milliosmole solution

None of the choices are correct.

1001.5 milliosmole solution

Correct answer:

1.5 milliosmole solution

Explanation:

The 1.5 milliosmole hypotonic solution is closely related to and meant to represent a freshwater environment. The solute composition of this solution was meant to mimic a freshwater environment in the study.

Example Question #535 : Biology

Carbonic anhydrase is an enzyme that is used by the human body to interconvert carbon dioxide (a gaseous compound) and bicarbonate (a compound composed of hydrogen, carbon, and oxygen), using water as a reactant. The human body needs to convert carbon dioxide to bicarbonate in the tissues to transport it in the blood to the lungs, as carbon dioxide is relatively insoluble. In the lungs, bicarbonate is converted back to carbon dioxide to be exhaled. In humans, there are two different carbonic anhydrase isomers, one that works in the lungs (isomer A) and one that works in the tissues (isomer B). Mutations in the chromosomes can prevent carbonic anhydrase from converting carbon dioxide to bicarbonate. In the following four experiments, the chromosomes of none, one, or both of the isomers were mutated per experiment.

 

Experiment 1

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Bicarbonate was measured in the tissues but carbon dioxide was not measured in the lungs.

 

Experiment 2

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Carbon dioxide levels were found to be abnormally high in the tissues and no bicarbonate was measured in the lungs.

 

Experiment 3

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Carbon dioxide levels were found to be slightly low in the tissues and bicarbonate levels were abnormally high in the lungs.

 

Experiment 4

Radiation was not used, A probe was placed into the tissues and lungs of a model animal and found normal carbon dioxide and bicarbonate levels.

Mutating the chromosomes of the animal cells is most likely useful in this passage because it __________.

Possible Answers:

produces new cells

produces unknown, unpredictable isoforms

changes the natural function of a cell

can be used to direct all types of research

Correct answer:

changes the natural function of a cell

Explanation:

The passage describes how mutating DNA allows scientists to deactivate certain isoforms of enzymes to study them; thus, mutating the DNA in this passage does not produce new cells or unknown, unpredicatable isoforms. The passage does not extend the technique of DNA mutation beyond this passage, so we cannot assume that it is useful in all types of research.

Example Question #536 : Biology

Carbonic anhydrase is an enzyme that is used by the human body to interconvert carbon dioxide (a gaseous compound) and bicarbonate (a compound composed of hydrogen, carbon, and oxygen), using water as a reactant. The human body needs to convert carbon dioxide to bicarbonate in the tissues to transport it in the blood to the lungs, as carbon dioxide is relatively insoluble. In the lungs, bicarbonate is converted back to carbon dioxide to be exhaled. In humans, there are two different carbonic anhydrase isomers, one that works in the lungs (isomer A) and one that works in the tissues (isomer B). Mutations in the chromosomes can prevent carbonic anhydrase from converting carbon dioxide to bicarbonate. In the following four experiments, the chromosomes of none, one, or both of the isomers were mutated per experiment.

 

Experiment 1

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Bicarbonate was measured in the tissues but carbon dioxide was not measured in the lungs.

 

Experiment 2

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Carbon dioxide levels were found to be abnormally high in the tissues and no bicarbonate was measured in the lungs.

 

Experiment 3

Radiation was used to mutate one of the chromosomes of one or more isomers of carbonic anhydrase. A probe was placed into the tissues and lungs of a model animal. Carbon dioxide levels were found to be slightly low in the tissues and bicarbonate levels were abnormally high in the lungs.

 

Experiment 4

Radiation was not used, A probe was placed into the tissues and lungs of a model animal and found normal carbon dioxide and bicarbonate levels.

Which of the experiments most likely served as the control experiment?

Possible Answers:

Experiment 2

Experiment 1

Experiment 3

Experiment 4

Correct answer:

Experiment 4

Explanation:

The passage tells us that no radiation was used to mutate the chromosomes of carbonic anhydrase in Experiment 4, in contrast to the previous three experiments, where radiation was used. Additionally, Experiment 4 found normal levels of carbon dioxide and bicarbonate in both the tissues and lungs, making it the control experiment against which the other experiments were compared.

Example Question #537 : Biology

Many motile organisms exhibit “fight or flight” responses in order to survive and reproduce. Aggressive posturing and combative behavior are important for the reproductive success and the formation of pack hierarchies of some species. Submissive actions and retreats permit other species the ability to evade capture or danger and enhance survival capabilities. Scientists have debated about the mechanics and moderation of these behaviors within organisms. Two studies regarding this behavior were performed.

Study 1

Researchers decided to study crayfish, a type of freshwater arthropod, in an aquarium. They placed two crayfish opposing one another in an enclosed space. The crayfish were divided by an opaque screen that inhibited their ability to notice one another. The screen was lifted and the crayfish were permitted to interact with one another. The scientists observed their interactions and noted the crayfish's submissive and aggressive behaviors. The scientists noticed that more dominant and aggressive behaviors correlated with larger sized individuals. Their observations indicate that large size and aggression are traits actively selected for within the crayfish population and are necessary for survivorship and reproductive success.

Study 2

Researchers in this study suggest that aggressive behaviors are linked to chemical messengers. They attempted to alter the crayfish’s lateral giant escape reaction through chemical manipulation. They injected crayfish with serotonin, an aggression stimulant, and octopamine, a natural facilitator of the flight response. They monitored and recorded the crayfish’s response to aggressive stimuli (see Figure 1). The researchers concluded that the crayfish escape response is significantly different in the chemical trials in comparison to the control trial that observed the injection of an inert saline solution into the arthropods.

Arthropod

Figure 1

Why was the control trial completed in Study 2?

Possible Answers:

The control trial was perfromed in order to sedate the crayfish for the chemical trials.

The control trial was performed in order to create a baseline for behavior comparison.

None of the other choices are correct.

The control trial was performed in order to observe a crayfish not exposed to aggressive stimuli.

Correct answer:

The control trial was performed in order to create a baseline for behavior comparison.

Explanation:

A control trial is conducted in order to create a baseline of comparison for treatment trials. The crayfish in the control trial were injected with an inert saline solution and exposed to aggressive stimuli. This meant that the crayfish underwent the stress involved with the injection and were exposed to the aggressive stimuli. This creates a standard that controls for other variables in order to determine the chemical effects on the lateral giant escape response.

Example Question #538 : Biology

Bacterial resistance is a common issue encountered in various infections. Scientists have attributed this phenomenon to the overuse of anti-bacterial sanitizers and prescription antibiotics. Two groups of researchers performed studies to test bacterial resistance.

Study 1

Researchers in this study state that bacterial resistance is the result of bacterial plasmid translocation. Bacteria carry their genes on circular rings of bacterial DNA and on small, physically separate molecules known as plasmids. Plasmids are unique because they are replicons that are capable of replication autonomously within a suitable host. Researchers radioactively marked plasmids in bacterial specimens and noted that they could be easily transmitted from one bacterium to another via horizontal gene transfer. They then observed that the genes transferred from the plasmid could be incorporated into the bacteria’s genetic makeup. These genetic alterations enhanced survivorship within the environment and promoted resistance to antibiotics. They concluded that plasmids carry genes important for survival and facilitate bacterial resistance to antibiotics.

Study 2

Researchers in this study state that resistance is the result of the misuse of antibiotics. Researchers administered various antibiotics to a culture of E. coli and studied their effects over time (Figure 1). They concluded that bacterial resistance is the result of natural selection. In other words, the strongest bacteria survive antibiotics and reproduce, which produces anitbiotic-resistant offspring bacteria. 

Bacterial_fixed

Figure 1

What happened to the control culture over the 15-day trial in Figure 1?

Possible Answers:

The bacterial population fluctuated slightly between days but remains relatively constant.

The bacterial population grew uninhibited over the 15-day period.

The bacterial population died off because of the presence of antibiotics.

The bacterial population grew due to the presence of anitbiotics.

Correct answer:

The bacterial population grew uninhibited over the 15-day period.

Explanation:

A control population is the population that is not administered the independent variable. In this case, the control group was not given any antibiotics. The bacteria were only limited by their food source and their population grew continuously.

Example Question #21 : How To Find Experimental Design In Biology

Bacterial resistance is a common issue encountered in various infections. Scientists have attributed this phenomenon to the overuse of anti-bacterial sanitizers and prescription antibiotics. Two groups of researchers performed studies to test bacterial resistance.

Study 1

Researchers in this study state that bacterial resistance is the result of bacterial plasmid translocation. Bacteria carry their genes on circular rings of bacterial DNA and on small, physically separate molecules known as plasmids. Plasmids are unique because they are replicons that are capable of replication autonomously within a suitable host. Researchers radioactively marked plasmids in bacterial specimens and noted that they could be easily transmitted from one bacterium to another via horizontal gene transfer. They then observed that the genes transferred from the plasmid could be incorporated into the bacteria’s genetic makeup. These genetic alterations enhanced survivorship within the environment and promoted resistance to antibiotics. They concluded that plasmids carry genes important for survival and facilitate bacterial resistance to antibiotics.

Study 2

Researchers in this study state that resistance is the result of the misuse of antibiotics. Researchers administered various antibiotics to a culture of E. coli and studied their effects over time (Figure 1). They concluded that bacterial resistance is the result of natural selection. In other words, the strongest bacteria survive antibiotics and reproduce, which produces anitbiotic-resistant offspring bacteria. 

Bacterial_fixed

Figure 1

What was the independent variable in Study 2?

Possible Answers:

The type of antibiotic used

The population of the bacterial culture

The period of incubation

The bacterial food supply

Correct answer:

The type of antibiotic used

Explanation:

The type of antibiotic was the independent variable because it elicited a response in the dependent variable (population size). The passage does not mention varying food supply or incubation period, so we can assume they were held constant.

Example Question #21 : How To Find Experimental Design In Biology

A group of scientists wanted to test the effects of Nitra-Grow, a chemical additive that can be given to plants to help them grow. 3 test groups of plants were given all the same time of sunlight, the same type of soil, and the same amount of water. Plant A was given no extra chemicals. Plant B was given 5g of Nitra-Grow. Plant C was given 5g of Ammonia to see if Nitra-Grow worked any better than a basic nitrogen-based household product. The plants are then measured on 5 consecutive days to find their average height (in cm).

 

DAY

Height Plant A (cm)

Height Plant B (cm)

Height Plant C (cm)

1

1.2

1.2

1.2

2

1.4

1.4

1.2

3

1.6

1.8

1.3

4

1.8

2.4

1.3

5

2.0

2.6

1.4

What is the dependent variable?

Possible Answers:

Type of chemical added

Day of measurement

Height of the plant

Type of soil

Correct answer:

Height of the plant

Explanation:

Answer, is the height of the plant. The Height of the plant DEPENDS on what type of chemical was being added to the plant. (The type of chemical added is the independent variable, because the scientist controlled what chemical went in each plant).

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