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ACT Math : How to find the period of the tangent

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Example Questions

Example Question #1 : How To Find The Period Of The Tangent

Which of the following equations represents a tangent function with a period that is $0.25\pi$ radians?

Possible Answers:

f(x) = 3tan(4x)-15

f(x) = 4tan(x)-15

f(x) =0.25tan(x)

f(x) = 4tan(x)-4

f(x) = tan(0.25x)

Correct answer:

f(x) = 3tan(4x)-15

Explanation:

The standard period of a tangent function is $\pi$ radians. In other words, it completes its entire cycle of values in that many radians. To alter the period of the function, you need to alter the value of the parameter of the trigonometric function. You multiply the parameter by the number of periods that would complete in $\pi$ radians. With a period of $0.25\pi$ , you are quadrupling your method. Therefore, you will have a function of the form:

f(x) =a*tan(4x)+b

Since and do not alter the period, these can be anything.

Therefore, among your options, f(x) = 3tan(4x)-15 is correct.

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Example Question #1 : How To Find The Period Of The Tangent

Which of the following represents a tangent function that has a period half that of one with a period of $16\pi$ ?

Possible Answers:

f(x) = 8tan(x)

$f(x)=\frac{1}{2}tan(16x)$

f(x) = 8tan(x)+8

f(x) = 14tan(8x)-12

f(x)=tan^8(x)

Correct answer:

f(x) = 14tan(8x)-12

Explanation:

The standard period of a tangent function is $\pi$ radians. In other words, it completes its entire cycle of values in that many radians. To alter the period of the function, you need to alter the value of the parameter of the trigonometric function. You multiply the parameter by the number of periods that would complete in $\pi$ radians. With a period of $16\pi$ , you are multiplying your parameter by . Now, half of this would be a period of $8\pi$ . Thus, you will have a function of the form:

f(x) =a*tan(8x)+b

Since and do not alter the period, these can be anything.

Therefore, among your options, f(x) = 14tan(8x)-12 is correct.

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Example Question #2 : How To Find The Period Of The Tangent

What is the period of the following tangent function?

f(x)=3tan(5x)+4

Possible Answers:

$\frac{2\pi}{5}$

$\frac{\pi}{5}$

$3\pi$

$\frac{\pi}{4}$

Correct answer:

$\frac{\pi}{5}$

Explanation:

The period of the tangent function defined in its standard form f(x)=tan(x) has a period of $\pi$ . When you multiply the argument of the trigonometric function by a constant, you shorten its period of repetition. (Think of it like this: You pass through more iterations for each value that you use.) If you have f(x)=tan(5x) , this has one fifth of the period of the standard tangent function. In the equation given, none of the other details matter regarding the period. They alter other aspects of the equation (its "width," its location, etc.). The period is altered only by the parameter. Thus, the period of this function is $\frac{1}{5}$ of $\pi$ , or $\frac{\pi}{5}$ .

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Example Question #2 : How To Find The Period Of The Tangent

What is the period of the following trigonometric equation:
$h(t) = 4\tan(-3t)$

Possible Answers:

$\frac{\pi}{2}$

$-\frac{\pi}{3}$

$2\pi$

$4\pi$

$\frac{\pi}{3}$

Correct answer:

$\frac{\pi}{3}$

Explanation:

For tangent and cotangent the period is given by the formula:

$\omega = \frac{\pi}{\left | b\right |}$ where comes from $h(t)= a\tan(bt)$ .

Thus we see from our equation b=-3 and so
$\omega = \frac{\pi}{\left | -3\right |}=\frac{\pi}{3}$ .

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Example Question #3 : How To Find The Period Of The Tangent

What is the period of the trigonometric function given by:
$h(t) = -4\tan(-3t)$ ?

Possible Answers:

$\frac{\pi}{4}$

$-\frac{\pi}{3}$

$\frac{2\pi}{3}$

$\frac{\pi}{3}$

$-\frac{2\pi}{3}$

Correct answer:

$\frac{\pi}{3}$

Explanation:

To find the period of a tangent funciton use the following formula:

$\omega = \frac{\pi}{\left | b\right |}$ where comes from $f(t) = a\tan(bt)$ .

thus we get that b = -3 so $\omega = \frac{\pi}{\left|3\right|} = \frac{\pi}{3}$

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Example Question #1 : How To Find The Period Of The Tangent

What is the period of the following trigonometric function:

$m(t) = -3\cot(-2t)$

Possible Answers:

$\omega = \frac{\pi}{3}$

$\omega = -\frac{\pi}{2}$

$\omega = -\pi$

$\omega = \frac{\pi}{2}$

$\omega = \pi$

Correct answer:

$\omega = \frac{\pi}{2}$

Explanation:

To find the period of a tangent or cotangent function use the following formula:

$\omega = \frac{\pi}{\left| b\right|}$

from the general tirogonometric formula:

$m(t) = a\cot(bt)$

Since we have,

$m(t) = -3\cot(-2t)$

we have

|b|=|-2|=2 .

Thus we get that

$\omega = \frac{\pi}{2}$

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ACT Math : How to find the period of the tangent

Study concepts, example questions & explanations for ACT Math

All ACT Math Resources

Example Questions

Example Question #1 : How To Find The Period Of The Tangent

Example Question #1 : How To Find The Period Of The Tangent

Example Question #2 : How To Find The Period Of The Tangent

Example Question #2 : How To Find The Period Of The Tangent

Example Question #3 : How To Find The Period Of The Tangent

Example Question #1 : How To Find The Period Of The Tangent

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