All SSAT Upper Level Math Resources
Example Questions
Example Question #271 : Ssat Upper Level Quantitative (Math)
If you have a circular yard and need to put up a fence around the outside, you would use the formula to figure out the amount of fence you need.
True
False
False
To figure out the amount of the fence around a circular yard, you need to find the circumference of the yard. The equation for the circumference of a cirle is and not .
Example Question #272 : Ssat Upper Level Quantitative (Math)
Find the circumference of a circle with a diameter of 12.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the diameter is 12, meaning we can plug our numbers into the second equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #273 : Ssat Upper Level Quantitative (Math)
Find the circumference of a circle with a diameter of 6.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the diameter is 6, meaning we can plug our numbers into the second equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #51 : Geometry
Find the circumference of a circle with a diameter of 2.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the diameter is 2, meaning we can plug our numbers into the second equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #52 : Geometry
Find the circumference of a circle with a radius of 12.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the radius is 12, meaning we can plug our numbers into the first equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #53 : Geometry
Find the circumference of a circle with a radius of 13.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the radius is 13, meaning we can plug our numbers into the first equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #54 : Geometry
Find the circumference of a circle with a radius of 27.
There are two possible formulas for finding the circumference of a circle. They are as follows:
And:
Where C is circumference, r is radius, and d is diameter.
For this problem, we are given the radius is 27, meaning we can plug our numbers into the first equation. Since pi is an irrational constant, it is okay to leave the answer in terms of pi.
Example Question #2 : How To Find The Equation Of A Line
Given the graph of the line below, find the equation of the line.
To solve this question, you could use two points such as (1.2,0) and (0,-4) to calculate the slope which is 10/3 and then read the y-intercept off the graph, which is -4.
Example Question #2 : Coordinate Geometry
Which line passes through the points (0, 6) and (4, 0)?
y = 2/3x –6
y = 2/3 + 5
y = 1/5x + 3
y = –3/2 – 3
y = –3/2x + 6
y = –3/2x + 6
P1 (0, 6) and P2 (4, 0)
First, calculate the slope: m = rise ÷ run = (y2 – y1)/(x2 – x1), so m = –3/2
Second, plug the slope and one point into the slope-intercept formula:
y = mx + b, so 0 = –3/2(4) + b and b = 6
Thus, y = –3/2x + 6
Example Question #3 : Coordinate Geometry
What line goes through the points (1, 3) and (3, 6)?
–3x + 2y = 3
2x – 3y = 5
4x – 5y = 4
–2x + 2y = 3
3x + 5y = 2
–3x + 2y = 3
If P1(1, 3) and P2(3, 6), then calculate the slope by m = rise/run = (y2 – y1)/(x2 – x1) = 3/2
Use the slope and one point to calculate the intercept using y = mx + b
Then convert the slope-intercept form into standard form.
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