All SSAT Upper Level Math Resources
Example Questions
Example Question #31 : Algebra
Given: are distinct integers such that:
Which of the following could be the least of the three?
or only
, , or
or only
or only
only
or only
, which means that must be positive.
If is nonnegative, then . If is negative, then it follows that . Either way, . Therefore, cannot be the least.
We now show that we cannot eliminate or as the least.
For example, if , then is the least; we test both statements:
, which is true.
, which is also true.
If , then is the least; we test both statements:
, which is true.
, which is also true.
Therefore, the correct response is or only.
Example Question #33 : Algebra
, , and are distinct integers. and . Which of the following could be the greatest of the three?
only
only
, , or
only
None of the other responses is correct.
only
, so must be positive. Therefore, since , equivalently, , so must be positive, and
If is negative or zero, it is the least of the three. If is positive, then the statement becomes
,
and is still the least of the three. Therefore, must be the greatest of the three.
Example Question #31 : Algebra
Give the solution set:
If , then either or . Solve separately:
or
The solution set, in interval notation, is .
Example Question #11 : How To Find Absolute Value
Define an operation on the real numbers as follows:
If , then
If , then
If , then
If , , and
then which of the following is a true statement?
Since , evaluate
, setting :
Since , then select the pattern
Since , evaluate
, setting :
, so the correct choice is that .
Example Question #36 : Algebra
Given: are distinct integers such that:
Which of the following could be the least of the three?
only
, , or
only
or only
only
only
, which means that must be positive.
If is nonnegative, then . If is negative, then it follows that . Either way, . Therefore, cannot be the least.
Now examine the statemtn . If , then - but we are given that and are distinct. Therefore, is nonzero, , and
and
.
cannot be the least either.
Example Question #12 : How To Find Absolute Value
, , and are distinct integers. and . Which of the following could be the least of the three?
None of the other responses is correct.
or only
or only
, , or
or only
None of the other responses is correct.
, so must be positive. Therefore, since , it follows that , so must be positive, and
If is negative or zero, it is the least of the three. If is positive, then the statement becomes
,
and is still the least of the three. Therefore, must be the least of the three, and the correct choice is "None of the other responses is correct."
Example Question #12 : How To Find Absolute Value
Give the solution set:
When dealing with absolute value bars, it is important to understand that whatever is inside of the absolute value bars can be negative or positive. This means that an inequality can be made.
In this particular case if , then, equivalently,
From here, isolate the variable by adding seven to each side.
In interval notation, this is .
Example Question #13 : How To Find Absolute Value
Solve the following expression for when .
First you plug in for and squre it.
This gives the expression which is equal to .
Since the equation is within the absolute value lines, you must make it the absolute value which is the amount of places the number is from zero.
This makes your answer .
Example Question #13 : How To Find Absolute Value
and
and
and
and
and
The absolute value of a number is its distance from zero. Absolute value is represented with or absolute value bars . To solve this absolute value equation remove the absolute value bars and set the equation equal to positive and negative eleven.
and are the two values of which make this statement true.
and
Remember, because Absolute Value measures the distance from zero, the absolute value of a number whether negative or positive is always non-negative.
Example Question #14 : How To Find Absolute Value
There is no solution.
Absolute value measures distance from that number to the point of origin or zero.
However, there is a negative sign outside the Absolute value bars, which indicates the multiplication by
becomes
Therefore is the correct solution.