Solution 1:

We can divide the rectangle width and height by the square side length and multiply the results:

rectangle width square length =

rectangle heightsquare length =

Solution 2:

As the results of the division of rectangle width and height by the square length are integers and do not have a residual, we can say that the squares can be perfectly fitted in the rectangle. Now in order to find the number of squares we can divide the rectangle area by the square area:

Rectangle area = square inches

Square area = square inches

So we can get:

The area of a rectangle is given by multiplying the width times the height. That means:

where:

width and  height.

We know that: . Substitube the  in the area formula:

Now we should solve the equation for :

The equation has two answers, one positive  and one negative . As the length is always positive, the correct answer is inches.

A rectangle has two congruent diagonals. A diagonal of a rectangle divides it into two identical right triangles. The diagonal of the rectangle is the hypotenuse of these triangles. We can use the Pythagorean Theorem to find the length of the diagonal if we know the width and height of the rectangle.

where:

  is the width of the rectangle
is the height of the rectangle

First, we find the height of the rectangle:

So we can write:

inches

As a rectangle has two diagonals with the same length, the sum of the diagonals is inches.

First we need to find the height of the rectangle. Since the width and the diagonal lengths are known, we can use the Pythagorean Theorem to find the height of the rectangle:

So we have:

So we can get:

Let  be the length of the rectangle. Then its width is 60% of this, or . The perimeter is the sum of the lengths of its sides, or

; we set this equal to 800 inches and solve for :

The width is therefore

.

The product of the length and width is the area:

 square inches.

The area of a rectangle is the product of the length and its height, Rectangle A has area  square inches; Rectangle B has area  square inches.

The area of Rectangle C is the mean of these areas, or 

 square inches, so its height is this area divided by its length:

 inches.

Let  be the length in feet. Then the width of the rectangle in feet is four-sevenths of this, or . The area is equal to the product of the length and the width, so set up this equation and solve for :

Since this is the length in feet, we multiply this by 12 to get the length in inches:

The area of a rectangle is the product of the length and its height.

Rectangle A has area  square inches, and Rectangle B has an area of  square inches, so the sum of their areas is  square inches. This is the area of Rectangle C; divide it by height  inches to get a length of

 inches. This answer is not among the given choices.

Let  be the length of the rectangle. Then its width is three-fourths of this, or . The perimeter is the sum of the lengths of its sides, or

.

Set this equal to 490 centimeters and solve for :

The length of the rectangle is 140 centimeters; the width is three-fourths of this, or 

 centimeters.

The area is the product of the length and the width:

 square centimeters.

We begin this problem by finding the difference of two areas: the larger rectangle bounded by the outer edge of the border and the smaller rectangle that is the court itself.

The larger rectangle is  square feet , and the court is  square feet .

The difference, , repesents the area of the border.

Now we divide this by , which is just a bit over . But since we can't leave  square feet unpainted, we have to round up to  cans of paint.