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SSAT Middle Level Math : Geometry

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Example Questions

Example Question #223 : Ssat Middle Level Quantitative (Math)

Dr. Robinson recently put a rectangular fence around his backyard. The fence has a width of $\small 15$ yards and a length of $\small 8$ yards. If Dr. Robinson paid $\small \small \$ 12.50$ for every yard of fence, how much did the fence cost?

Possible Answers:

$\small \$525$

$\small \$375$

$\small \$575$

$\small \$625$

Correct answer:

$\small \$575$

Explanation:

To find the cost of the fence, apply the formula $\small P=2(width)+2(length)$ in order to first find the length of the perimeter of the fence.

Then multiply the perimeter by $\small \$12.50$ .

Thus, the solution is:

$\small P=2(15)+2(8)$
$\small P=30+16$
$\small P=46$

$\small 46\times12.5=575$

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Example Question #224 : Ssat Middle Level Quantitative (Math)

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The rectangle shown above has a width of $\small 14$ and a length of $\small 4$ . Find the area and perimeter of the rectangle.

Possible Answers:

$\small \small A=43 units^2, P=26$

$\small \small A=36 units^2, P=36$

$\small \small A=56 units^2, P=36$

$\small \small A=50 units^2, P=34$

Correct answer:

$\small \small A=56 units^2, P=36$

Explanation:

To solve this problem apply the formulas: $\small Area=width\times length$ & $\small Perimeter=2(w)+2(l)$

Thus, the solution is:

$\small A=14\times4=56$
$\small P=2(14)+2(4)=28+8=36$

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Example Question #1 : Plane Geometry

A right triangle has legs 90 centimeters and 16 centimeters, What is its area?

Possible Answers:

$720 \; \textrm{cm}^{2}$

$256 \; \textrm{cm}^{2}$

$1,440 \; \textrm{cm}^{2}$

$405\; \textrm{cm}^{2}$

$4,050 \; \textrm{cm}^{2}$

Correct answer:

$720 \; \textrm{cm}^{2}$

Explanation:

The legs of a right triangle are its base and height, so use the area formula for a triangle with these dimension. Setting b=16,h=90 :

$A = \frac{1}{2} bh = \frac{1}{2} \cdot 16 \cdot 90= 720$

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Example Question #2 : Plane Geometry

A triangle has base 18 inches and height 14 inches. What is its area?

Possible Answers:

$252 \; \textrm{in}^{2}$

$98 \; \textrm{in}^{2}$

$196 \; \textrm{in}^{2}$

$126 \; \textrm{in}^{2}$

$162 \; \textrm{in}^{2}$

Correct answer:

$126 \; \textrm{in}^{2}$

Explanation:

Use the area formula for a triangle, setting b=18,h=14 :

$A = \frac{1}{2} bh = \frac{1}{2} \cdot 18 \cdot14 = 126$

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Example Question #3 : Plane Geometry

Triangle

What is the area of the above triangle?

Possible Answers:

$168\textrm{ in}^{2}$

$112\textrm{ in}^{2}$

$56\textrm{ in}^{2}$

$300\textrm{ in}^{2}$

$84\textrm{ in}^{2}$

Correct answer:

$84\textrm{ in}^{2}$

Explanation:

The two legs of a right triangle can serve as its base and its height. The area of the triangle is half the product of the two:

$\frac{1}{2} \cdot 7 \cdot 24 = 84$

That is, the area is 84 square inches.

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Example Question #4 : Plane Geometry

Triangle

What is the area of the above triangle?

Possible Answers:

$3,000\textrm{ mm}^{2}$

$6,000\textrm{ mm}^{2}$

$300\textrm{ mm}^{2}$

$3,250\textrm{ mm}^{2}$

$325\textrm{ mm}^{2}$

Correct answer:

$3,000\textrm{ mm}^{2}$

Explanation:

The two legs of a right triangle can serve as its base and its height. The area of the triangle is half the product of the two:

$\frac{1}{2} \cdot 50 \cdot 120 = 3,000$

That is, the area is 3,000 square millimeters.

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Example Question #2 : Triangles

Triangle

Note: Figure NOT drawn to scale.

The above triangle has an area of 450 square centimers. $x = 20 \textrm{ cm}$ . What is ?

Possible Answers:

$y = 22.5 \textrm{ cm}$

$y = 30\textrm{ cm}$

$y = 37.5\textrm{ cm}$

$y = 45\textrm{ cm}$

$y = 60\textrm{ cm}$

Correct answer:

$y = 45\textrm{ cm}$

Explanation:

The area of a triangle is one half the product of its base and its height - in the above diagram, that means

$A = \frac{1}{2}xy$ .

Substitute A = 450, x = 20 , and solve for :

$\frac{1}{2} \cdot 20 \cdot y = 450$

$10 \cdot y = 450$

$10 \cdot y \div 10 = 450 \div 10$

$y = 45 \textrm{ cm}$

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Example Question #6 : How To Find The Area Of A Triangle

Find the area of the triangle.

Note: Figure not drawn to scale.

Possible Answers:

$48\: in^{2}$

$120\: in^{2}$

$24\: in^{2}$

$60\: in^{2}$

Correct answer:

$60\: in^{2}$

Explanation:

To find the area of a triangle, multiply the base of the triangle by the height and then divide by two.

10*12=120

120/2=60

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Example Question #5 : How To Find The Area Of A Triangle

Square

The quadrilateral in the above diagram is a square. What percent of it is white?

Possible Answers:

$14 \frac{1}{16} \%$

$28 \frac{1}{8} \%$

$20 \%$

$17 \frac{1}{2} \%$

$16 \frac{1}{4} \%$

Correct answer:

$14 \frac{1}{16} \%$

Explanation:

The area of the entire square is the square of the length of a side, or

$80 \times 80 = 6,400$ .

The area of the white right triangle is half the product of its legs, or

$\frac{1}{2} \times 30 \times 60 = 900$ .

Therefore, the area of that triangle is

$\frac{900 }{6,400} \times 100 = 14 \frac{1}{16} \%$

of that of the entire square.

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Example Question #7 : How To Find The Area Of A Triangle

Yard_2

Mr. Jones owns the isosceles-triangle-shaped parcel of land seen in the above diagram. He sells the parcel represented in red to his brother. What is the area of the land he retains?

Possible Answers:

$15,232\textrm{ m}^{2}$

$7,616\textrm{ m}^{2}$

$4,032\textrm{ m}^{2}$

$18,816\textrm{ m}^{2}$

$11,200\textrm{ m}^{2}$

Correct answer:

$7,616\textrm{ m}^{2}$

Explanation:

The area of a triangle is half the product of its base and its height, so Mr. Jones's parcel originally had area

$\frac{1}{2} \times 140 \times 160 = 11,200$ square meters.

The portion he sold his brother, represented by the red right triangle, has area

$\frac{1}{2} \times 56 \times 128 = 3,584$ square meters.

Therefore, the area of the parcel Mr. Jones retained is

11,200 -3,584= 7,616 square meters.

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SSAT Middle Level Math : Geometry

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #223 : Ssat Middle Level Quantitative (Math)

Example Question #224 : Ssat Middle Level Quantitative (Math)

Example Question #1 : Plane Geometry

Example Question #2 : Plane Geometry

Example Question #3 : Plane Geometry

Example Question #4 : Plane Geometry

Example Question #2 : Triangles

Example Question #6 : How To Find The Area Of A Triangle

Example Question #5 : How To Find The Area Of A Triangle

Example Question #7 : How To Find The Area Of A Triangle

All SSAT Middle Level Math Resources

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