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SSAT Middle Level Math : Plane Geometry

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Example Questions

Example Question #261 : Plane Geometry

Find the perimeter of the trapezoid:
Question_12

Possible Answers:

$\small 23.5$

$\small 21$

$\small 26$

$\small 40$

Correct answer:

$\small 21$

Explanation:

The perimeter of any shape is equal to the sum of the lengths of its sides:

$\small P=4+6+3+8=21$

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Example Question #203 : Geometry

Trapezoid

Find the perimeter of the given trapezoid if $l=9, h=7, b_{1}=8, b_{2}=10$

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter, we must find the sum of the outer edges:

Trapezoid_labeled

9+8+ 9+10=36

Notice that we didn't use height in our calculation.

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Example Question #201 : Geometry

Trapezoid

Find the perimeter of the given trapezoid if $l=6, h=4, b_{1}=2, b_{2}=5$

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter, find the sum of the outer edges:

Trapezoid_labeled

6+2+6+5=19

Notice that we didn't use height in our calculation.

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Example Question #123 : Quadrilaterals

Trapezoid

The above diagram depicts a rectangle RECT with isosceles triangle $\Delta ECM$ . is the midpoint of $\overline{CT}$ . What is the ratio of the area of the orange trapezoid to that of the white triangle?

Possible Answers:

4:1

9:2

3:1

7:2

More information is needed to answer this question.

Correct answer:

3:1

Explanation:

We can simplify this problem by supposing that the length of one leg of a triangle is 2. Then the other leg is 2, and the area of the triangle is

$A = \frac {1}{2} \cdot 2 \cdot 2 = 2$

Since is the midpoint of $\overline{CT}$ , MT = 2 . Also, since opposite sides of a rectangle are congruent,

RE = CT = CM + MT = 2 + 2 = 4 .

This makes the trapezoid one with height 2 and bases 2 and 4, so

$A = \frac {1}{2} \cdot (2 + 4) \cdot 2 = 6$

The ratio of the area of the trapezoid to that of the triangle is 6 to 2, which simplifies to 3 to 1.

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Example Question #124 : Quadrilaterals

Find the area of the trapezoid above.

Note: Image not drawn to scale.

Possible Answers:

$120\: cm^{2}$

$120\: cm$

$200\: cm^{2}$

$80\: cm$

$160\: cm$

Correct answer:

$120\: cm^{2}$

Explanation:

The area of a trapezoid is equal to the average of the length of the two bases multiplied by the height.

The formula to find the area of a trapezoid is: $\left (\frac{base_{1} + base_{2}}{2}\right )* height$

In this problem, the lengths of the bases are $10\: cm$ and $20\: cm.$ Their average is $15\: cm$ . The height of the trapezoid is $8\: cm.$

$15\: cm\ast 8\: cm=120\: cm$

Remember: the answer to the problem should have units in cm² .

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Example Question #125 : Quadrilaterals

Find the area of a trapezoid with a height of $5\:cm$ and base lengths of $4\:cm$ and $8\:cm$ , respectively.

Possible Answers:

$15\:cm^{2}$

$30\:cm^{2}$

$17\:cm$

$10\:cm^{2}$

$22\:cm^{2}$

Correct answer:

$30\:cm^{2}$

Explanation:

The area of a trapezoid is equal to the average of its two bases ( $b_{1}$ and $b_{2}$ ) multiplied by its height . Therefore:

$A=\frac{1}{2}(b_{1}+b_{2})h$

$A=\frac{1}{2}(4\:cm+8\:cm)5\:cm$

$A=\(6\:cm)5\:cm$

$A=30\:cm^{2}$

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Example Question #2 : How To Find The Area Of A Trapezoid

Find the area of a trapezoid with a height of $8\:cm$ and base lengths of $10\:cm$ and $12\:cm$ , respectively.

Possible Answers:

$88\:cm^{2}$

$30\:cm^{2}$

$88\:cm$

$52\:cm^{2}$

$30\:cm$

Correct answer:

$88\:cm^{2}$

Explanation:

The area of a trapezoid is equal to the average of its two bases ( $b_{1}$ and $b_{2}$ ) multiplied by its height . Therefore:

$A=\frac{1}{2}(b_{1}+b_{2})h$

$A=\frac{1}{2}(10\:cm+12\:cm)8\:cm$

$A=\(11\:cm)8\:cm$

$A=88\:cm^{2}$

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Example Question #1 : How To Find The Area Of A Trapezoid

Trapezoid

What is the area of the above trapezoid?

Possible Answers:

$142.04\textrm{ m}^{2}$

$96.48\textrm{ m}^{2}$

$218.36\textrm{ m}^{2}$

$76.32\textrm{ m}^{2}$

$109.18\textrm{ m}^{2}$

Correct answer:

$109.18\textrm{ m}^{2}$

Explanation:

To find the area of a trapezoid, multiply one half (or 0.5, since we are working with decimals) by the sum of the lengths of its bases (the parallel sides) by its height (the perpendicular distance between the bases). This quantity is

$A = 0.5 \cdot (7.2 + 13.4) \cdot 10.6 =0.5 \cdot 20.6 \cdot 10.6 = 109.18\textrm{ m}^{2}$

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Example Question #2 : How To Find The Area Of A Trapezoid

Find the area of the trapezoid:

Question_7

Possible Answers:

Correct answer:

Explanation:

The area of a trapezoid can be determined using the equation $A=\frac{1}{2}(b_1+b_2)h$ .

$A=\frac{1}{2}(6+8)(4)$

$A=\frac{1}{2}(14)(4)$

A=(7)(4)=28

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Example Question #1 : How To Find The Area Of A Trapezoid

Trapezoid

What is the area of the trapezoid?

Possible Answers:

$135\textrm{ m}^{2}$

$198\textrm{ m}^{2}$

$63\textrm{ m}^{2}$

$105\textrm{ m}^{2}$

$99\textrm{ m}^{2}$

Correct answer:

$99\textrm{ m}^{2}$

Explanation:

To find the area of a trapezoid, multiply the sum of the bases (the parallel sides) by the height (the perpendicular distance between the bases), and then divide by 2.

$A = \frac{1}{2} \cdot (7 + 15) \cdot 9 = \frac{1}{2} \cdot 22 \cdot 9 = 99 \textrm{ m}^2$

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SSAT Middle Level Math : Plane Geometry

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #261 : Plane Geometry

Example Question #203 : Geometry

Example Question #201 : Geometry

Example Question #123 : Quadrilaterals

Example Question #124 : Quadrilaterals

Example Question #125 : Quadrilaterals

Example Question #2 : How To Find The Area Of A Trapezoid

Example Question #1 : How To Find The Area Of A Trapezoid

Example Question #2 : How To Find The Area Of A Trapezoid

Example Question #1 : How To Find The Area Of A Trapezoid

All SSAT Middle Level Math Resources

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