SSAT Middle Level Math : Plane Geometry

Study concepts, example questions & explanations for SSAT Middle Level Math

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Example Questions

Example Question #4 : How To Find The Area Of A Rectangle

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The rectangle above is \displaystyle 5 inches long and \displaystyle 10 inches wide. What is the area of the rectangle?

Note: Figure not drawn to scale.

Possible Answers:

\displaystyle 15\: in

\displaystyle 30\: in

\displaystyle 50\: in^{2}

\displaystyle 30\: in^{2}

\displaystyle 50\: in

Correct answer:

\displaystyle 50\: in^{2}

Explanation:

The area of the rectangle is \displaystyle 50\: in^{2}. In order to find the area of a rectangle, multiply the length (5 inches) by the width (10 inches). The answer is in units2 because the area, by definition, is the number of square units that cover the inside of a figure.

Example Question #2 : How To Find The Volume Of A Figure

Swimming_pool

The above depicts a rectangular swimming pool for an apartment. The pool is two meters deep everywhere. What is the volume of the pool in cubic meters?

Possible Answers:

\displaystyle 720 \textrm{ m}^{3}

\displaystyle 1,440\textrm{ m}^{3}

\displaystyle 820\textrm{ m}^{3}

\displaystyle 876\textrm{ m}^{3}

The correct answer is not among the other choices.

Correct answer:

\displaystyle 720 \textrm{ m}^{3}

Explanation:

The pool can be seen as a rectangular prism with dimensions 24 meters by 15 meters by 2 meters; its volume is the product of these dimensions, or

\displaystyle 24 \times 15 \times 2 = 720 cubic meters.

Example Question #211 : Problem Solving

Rectangles

Note: Figure NOT drawn to scale.

What percent of the above figure is white?

Possible Answers:

\displaystyle 22 \frac{1}{2} \%

\displaystyle 25 \%

\displaystyle 18 \frac{3}{4} \%

\displaystyle 17 \frac{1}{2} \%

\displaystyle 20 \%

Correct answer:

\displaystyle 18 \frac{3}{4} \%

Explanation:

The large rectangle has length 80 and width 40, and, consequently, area

\displaystyle 80 \times 40 = 3,200.

The white region is a rectangle with length 30 and width 20, and, consequently, area 

\displaystyle 30 \times 20 = 600.

The white region is 

\displaystyle \frac{600}{3,200} \times 100 = 18 \frac{3}{4} \%

of the large rectangle.

Example Question #1 : Rectangles

What is the area of a rectangle with length \displaystyle 14\ cm and width \displaystyle 12\ cm?

Possible Answers:

\displaystyle 158\;cm^{2}

\displaystyle 148\; cm^{2}

\displaystyle 198\;cm^{2}

\displaystyle 144\; cm^{2}

\displaystyle 168\;cm^{2}

Correct answer:

\displaystyle 168\;cm^{2}

Explanation:

The formula for the area, \displaystyle A, of a rectangle when we are given its length, \displaystyle L, and width, \displaystyle W, is \displaystyle A = L * W.

To calculate this area, just multiply the two terms.

\displaystyle A = 14\ cm * 12\ cm = 168\; cm^{2}

Example Question #161 : Geometry

Order the following from least area to greatest area:

Figure A: A rectangle with length 10 inches and width 14 inches.

Figure B: A square with side length 1 foot.

Figure C: A triangle with base 16 inches and height 20 inches.

Possible Answers:

\displaystyle A, C, B

\displaystyle B, C, A

\displaystyle A, B, C

\displaystyle B, A, C

\displaystyle C,A, B

Correct answer:

\displaystyle A, B, C

Explanation:

Figure A has area \displaystyle 10 \times 14 = 140 square inches.

Figure B has area \displaystyle 12 \times 12 = 144 square inches, 1 foot being equal to 12 inches.

Figure C has area \displaystyle \frac{1}{2} \times 16 \times 20 = 160 square inches.

The figures, arranged from least area to greatest, are A, B, C.

Example Question #2 : How To Find The Area Of A Rectangle

Prism

Give the surface area of the above box in square inches.

Possible Answers:

\displaystyle 672 \textrm{ in}^{2}

\displaystyle 3,168 \textrm{ in}^{2}

\displaystyle 816 \textrm{ in}^{2}

\displaystyle 1,056\textrm{ in}^{2}

\displaystyle 1,344 \textrm{ in}^{2}

Correct answer:

\displaystyle 1,344 \textrm{ in}^{2}

Explanation:

Use the surface area formula, substituting \displaystyle L = 22, W = H = 12 :

\displaystyle A = 2LW + 2LH + 2WH

\displaystyle A = 2 \cdot 22 \cdot 12 + 2 \cdot 22 \cdot 12 + 2\cdot 12\cdot 12

\displaystyle A = 528 + 528 + 288

\displaystyle A =1,344 square inches

Example Question #162 : Geometry

The area of the following rectangle is \displaystyle 48\: cm^2. Solve for \displaystyle x.

Isee_mid_question_4

 

Possible Answers:

\displaystyle x=16

\displaystyle x=4

\displaystyle x=12

\displaystyle x=8

Correct answer:

\displaystyle x=4

Explanation:

The area of a rectangle can be found by multiplying the length by the width.

\displaystyle A=l\times w

\displaystyle 48=3x\times x=3x^2

\displaystyle 48=3x^2

\displaystyle \frac{48}{3}=\frac{3x^2}{3}

\displaystyle 16=x^2

\displaystyle \sqrt{16}=\sqrt{x^2}

\displaystyle 4=x

Example Question #163 : Geometry

Rectangle

Give the area of the above rectangle in square feet.

Possible Answers:

\displaystyle 216 \textrm{ ft}^{2}

\displaystyle 66 \textrm{ ft}^{2}

\displaystyle 33 \textrm{ ft}^{2}

\displaystyle 576 \textrm{ ft}^{2}

\displaystyle 532\textrm{ ft}^{2}

Correct answer:

\displaystyle 216 \textrm{ ft}^{2}

Explanation:

Since 1 yard = 3 feet, multiply each dimension by 3 to convert from yards to feet:

\displaystyle 8 \textrm{ yd} \times 3 \textrm{ ft/yd} = 24 \textrm{ ft}

\displaystyle 3 \textrm{ yd} \times 3 \textrm{ ft/yd} = 9 \textrm{ ft}

Use the area formula, substituting \displaystyle L = 24, W = 9:

\displaystyle A = LW

\displaystyle A = 24 \times 9 = 216 square feet

Example Question #1 : Rectangles

The ratio of the perimeter of one square to that of another square is \displaystyle 7:4. What is the ratio of the area of the first square to that of the second square?

Possible Answers:

\displaystyle 7:8

\displaystyle 49:16

\displaystyle 7:2

\displaystyle 7:4

\displaystyle 49:4

Correct answer:

\displaystyle 49:16

Explanation:

For the sake of simplicity, we will assume that the second square has sidelength 1; Then its perimeter is \displaystyle 4 \times 1 = 4, and its area is \displaystyle 1^{2} = 1.

The perimeter of the first square is \displaystyle \frac{7}{4} \times 4 = 7 , and its sidelength is \displaystyle 7 \div 4 = \frac{7}{4}. The area of this square is therefore \displaystyle \left (\frac{7}{4} \right )^{2} =\frac{49}{16}.

The ratio of the areas is therefore \displaystyle \frac{49}{16} : 1 = 49:16.

Example Question #94 : Plane Geometry

The following question is about the Jones family wanting to buy square foot tiles for their rectangular basement. Their basement perimeter is 74 feet, with one of the sides being 15 feet long. 

How many square foot titles are the Jones family needing to purchase in order to tile their basement?

Possible Answers:

\displaystyle 68

\displaystyle 1320

\displaystyle 330

\displaystyle 72

\displaystyle 74

Correct answer:

\displaystyle 330

Explanation:

From the given information we know that the perimeter of the rectangular basement is 74 feet. We also know that one side of the rectangular basement is 15 feet. This means that the opposite side is also 15 feet long because the equivalent opposite sides rule of rectangles. In order to find the lengths of our other two sides of the rectangle, we need to subtract our two 15 feet sides from the perimeters 74 feet.

\displaystyle 74-30=44\ feet.

We know that the last two sides have to add up to 44 feet. Since the rules of rectangles say opposite sides are equivalent, we must take 44 feet and divide by the 2 sides. So 44 divided by 2 is 22 feet, meaning each side must be 22 feet. After adding up all the sides we can confirm that our perimeter is 74 feet. 

Now we know all the sides of the rectangle, we are able to move to the next step, finding the area. We must find the area, because the tiles are square feet. So in order to find the area we must take the length of the rectangle and multiply it to the width. 

\displaystyle 22\times 15= 330 ft^{2}

Knowing the area of the rectangular basement we also know how many tile are needed to fill the basement for the Jones family. It is exactly 330 square feet tile needed.

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