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SSAT Elementary Level Math : Plane Geometry

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #611 : Plane Geometry

Why is this shape a triangle?

Screen shot 2015 07 21 at 2.50.59 pm

Possible Answers:

Because it is smaller than a square

Because the sides do not connect

Because it has sides

Because its color is blue

Because it has sides

Correct answer:

Because it has sides

Explanation:

A triangle has sides.

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Example Question #612 : Plane Geometry

Find the area of a triangle with base 4 and height 7.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a triangle. Thus,

$A=\frac{1}{2}Bh=\frac{1}{2}*4*7=\frac{1}{2}*28=14$

To remember this formula, simply realize that two triangles added together would leave you with a rectangle, so a triangle's area must be half the area of a rectangle.

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Example Question #24 : How To Find The Area Of A Triangle

Find the area of the triangle shown below:

Screen shot 2015 11 03 at 3.24.38 pm

Possible Answers:

Correct answer:

Explanation:

The area of a triangle can be expressed by the formula

$\frac{b\times h}{2}$ ,

or base times height divided by 2.

$\frac{4\times12}{2}=24$ .

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Example Question #25 : How To Find The Area Of A Triangle

Use the following to answer the question.

Triangle3

Find the area of the triangle if the height is twice the length of the base.

Possible Answers:

$27\text{cm}$

$25\text{cm}$

$50\text{cm}^2$

$25\text{cm}^2$

$27\text{cm}^2$

Correct answer:

$25\text{cm}^2$

Explanation:

To find the area of a triangle, we use the following formula:

$\text{area of triangle} = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

So, using the triangle

Triangle3

we can see that the base is 5cm. The problem also stated that the height is twice (or two times) the length of the base. So, the height is 10cm ( 2x5cm ). Knowing this, we can substitute into the formula. We get

$\text{area of triangle} = \frac{1}{2} \cdot 5\text{cm} \cdot 10\text{cm}$

$\text{area of triangle} = \frac{1}{2} \cdot 50\text{cm}^2$

$\text{area of triangle} = 25\text{cm}^2$

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Example Question #614 : Geometry

Find the area of a triangle.

What is the area of a triangle with a base of 10cm and a height of 5cm?

Possible Answers:

25cm

$25cm^{2}$

$7.5cm^{2}$

15cm

$50cm^{2}$

Correct answer:

$25cm^{2}$

Explanation:

First you must understand that the area of a triangle is $\frac{1}{2}$ base times height.

$\frac{1}{2}\times10cm=5cm$

$5cm\times5cm=25cm^{2}$

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Example Question #615 : Geometry

Find the area of the triangle.

What is the area of the triangle with a base of 4cm and a height of 14cm.

Possible Answers:

56cm

28cm

$56cm^{2}$

$18cm^{2}$

$28cm^{2}$

Correct answer:

$28cm^{2}$

Explanation:

First you must understand that area of a triangle is $\frac{1}{2}$ base times height.

$\frac{1}{2}$ $\times4=2cm$

$2cm\times14cm=28cm^{2}$

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Example Question #613 : Geometry

Find the area of a triangle with a base of 8in and a height of 12in.

Possible Answers:

$96\text{in}^2$

$20\text{in}^2$

$32\text{in}^2$

$48\text{in}^2$

$58\text{in}^2$

Correct answer:

$48\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$\text{area of triangle} = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 8in. We also know the height of the triangle is 12in.

Knowing this, we can substitute into the formula. We get

$\text{area of triangle} = \frac{1}{2} \cdot 8\text{in} \cdot 12\text{in}$

$\text{area of triangle} = 4\text{in} \cdot 12\text{in}$

$\text{area of triangle} = 48\text{in}^2$

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Example Question #614 : Geometry

Find the area of a triangle with a base of 6in and a height that is three times the base.

Possible Answers:

$68\text{in}^2$

$108\text{in}^2$

$54\text{in}^2$

$18\text{in}^2$

$9\text{in}^2$

Correct answer:

$54\text{in}^2$

Explanation:

To find the area of a triangle, we will use the following formula:

$A = \frac{1}{2} \cdot b \cdot h$

where b is the base and h is the height of the triangle.

Now, we know the base of the triangle is 6in. We also know the height of the triangle is three times the base. Therefore, the height is 18in.

Now, we can substitute. We get

$A = \frac{1}{2} \cdot 6\text{in} \cdot 18\text{in}$

$A = 3\text{in} \cdot 18\text{in}$

$A = 54\text{in}^2$

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Example Question #61 : Reason With Shapes And Their Attributes

What two shapes can you find in this shape?

Screen shot 2015 07 24 at 11.12.33 am

Possible Answers:

A square and a square

A rectangle and a triangle

A triangle and a triangle

A triangle and a square

Correct answer:

A triangle and a triangle

Explanation:

Screen shot 2015 07 24 at 11.15.16 am

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Example Question #1 : How To Find The Perimeter Of A Triangle

If one side of an equilateral triangle is 6, what is the perimeter of the triangle?

Possible Answers:

Correct answer:

Explanation:

To find the perimeter of any triangle you will need to add up all the sides. For this triangle, you will add 6 + 6 + 6 = 18 since an equilateral triangle has 3 congruent sides.

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All SSAT Elementary Level Math Resources

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SSAT Elementary Level Math : Plane Geometry

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #611 : Plane Geometry

Example Question #612 : Plane Geometry

Example Question #24 : How To Find The Area Of A Triangle

Example Question #25 : How To Find The Area Of A Triangle

Example Question #614 : Geometry

Example Question #615 : Geometry

Example Question #613 : Geometry

Example Question #614 : Geometry

Example Question #61 : Reason With Shapes And Their Attributes

Example Question #1 : How To Find The Perimeter Of A Triangle

All SSAT Elementary Level Math Resources

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