All SAT Math Resources
Example Questions
Example Question #2811 : Sat Mathematics
If , what is the smallest possible value of ?
4
6
8
12
10
6
This equation describes a parabola whose vertex is located at the point (4, 6). No matter how large or small the value of t gets, the smallest that f(t) can ever be is 6 because the parabola is concave up. To prove this to yourself you can plug in different values of t and see if you ever get anything smaller than 6.
Example Question #2812 : Sat Mathematics
If , then ?
To find when , we substitute for in .
Thus, .
We expand to .
We can combine like terms to get .
We add 3 to this result to get our final answer.
Example Question #2813 : Sat Mathematics
Let and be functions such that , and . Which of the following is equal to ?
If and are defined as inverse functions, then . Thus, according to the definition of inverse functions, and given in the problem must be inverse functions.
If we want to find the inverse of a function, the most straighforward method is usually replacing with , swapping and , and then solving for .
We want to find the inverse of . First, we will replace with .
Next, we will swap and .
Lastly, we will solve for . The equation that we obtain in terms of will be in the inverse of , which equals .
We can treat as a proportion, . This allows us to cross multiply and set the results equal to one another.
We want to get y by itself, so let's divide both sides by x.
Next, we will add 3 to both sides.
To combine the right side, we will need to rewrite 3 so that it has a denominator of .
The answer is .
Example Question #105 : Algebraic Functions
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Example Question #2814 : Sat Mathematics
Let the function f be defined by f(x)=x-t. If f(12)=4, what is the value of f(0.5*t)?
First we substitute in 12 for x and set the equation up as 12-t=4. We then get t=8, and substitute that for t and get f(0.5*8), giving us f(4). Plugging 4 in for x, and using t=8 that we found before, gives us:
f(4) = 4 - 8 = -4
Example Question #2815 : Sat Mathematics
What is the value of the function f(x) = 6x2 + 16x – 6 when x = –3?
96
–108
–12
0
0
There are two ways to do this problem. The first way just involves plugging in –3 for x and solving 6〖(–3)〗2 + 16(–3) – 6, which equals 54 – 48 – 6 = 0. The second way involves factoring the polynomial to (6x – 2)(x + 3) and then plugging in –3 for x. The second way quickly shows that the answer is 0 due to multiplying by (–3 + 3).
Example Question #2816 : Sat Mathematics
Given the functions f(x) = 2x + 4 and g(x) = 3x – 6, what is f(g(x)) when x = 6?
16
144
12
28
192
28
We need to work from the inside to the outside, so g(6) = 3(6) – 6 = 12.
Then f(g(6)) = 2(12) + 4 = 28.
Example Question #71 : How To Find F(X)
A function f(x) = –1 for all values of x. Another function g(x) = 3x for all values of x. What is g(f(x)) when x = 4?
–3
–12
12
–1
3
–3
We work from the inside out, so we start with the function f(x). f(4) = –1. Then we plug that value into g(x), so g(f(x)) = 3 * (–1) = –3.
Example Question #14 : How To Find F(X)
What is f(–3) if f(x) = x2 + 5?
15
–14
–4
14
4
14
f(–3) = (–3)2 + 5 = 9 + 5 = 14
Example Question #21 : Algebraic Functions
For all values of x, f(x) = 7x2 – 3, and for all values of y, g(y) = 2y + 9. What is g(f(x))?
14x2 + 3
7y2 – 3
2x + 9
14y2 + 3
14x2 – 3
14x2 + 3
The inner function f(x) is like our y-value that we plug into g(y).
g(f(x)) = 2(7x2 – 3) + 9 = 14x2 – 6 + 9 = 14x2 + 3.