All SAT Math Resources
Example Questions
Example Question #2071 : Sat Mathematics
Find the solution to the system of equations.
We can solve either by substitution or by elimination. We will solve by elimination.
Line up both equations so the variables are in the same order.
Because we have a negative and a positive , if we were to add these two equations straight up and down, the values would cancel out.
Solve for .
Plug back in to one of the original equations to solve for .
The final answer will be . We can check this answer by plugging it back into either of the original equations.
Example Question #2072 : Sat Mathematics
Given:
How many solutions will there be for the system of equations?
Use the substitution method to solve the system of equations. There are two ways to do this - either substitute the first equation into the second, or the second equation into the first. Since the second equation is already solved for one variable, we will choose the latter.
Now factor the equation:
or
For this particular question, you could stop right here, as you can only need to know the number of solutions not the ordered pair of the solutions. Here there are two solutions. The ordered pairs would be:
and
Example Question #2073 : Sat Mathematics
Find the value of .
Subtracting the second equation from the first, we acquire .
Adding this equation to the third equation, we get .
Therefore, .
Example Question #2074 : Sat Mathematics
What is ?
Solve for by merging the equations so that gets factored out. To do so, multiply the lower equation by (so that at the top is subtracted by )
Example Question #299 : Equations / Inequalities
The total number of chocolate milkshakes, vanilla milkshakes, and strawberry milkshakes sold at a milkshake stand is 179. Vanilla milkshakes cost $1.30, while chocolate and strawberry milkshakes each cost $1.45. If the total milkshake profits totaled $246.05, and there were 27 more chocolate milkshakes sold than strawberry, then how many strawberry milkshakes were sold?
If the total milkshake profits were $246.05, and vanilla milkshakes cost $1.30 while chocolate and strawberry milkshakes cost $1.45, we can set up the equation
,
where a represents the number of vanilla milkshakes sold and b represents the number of chocolate and strawberry milkshakes sold. We also know that 179 total milkshakes were sold, so we can set up the equation
.
If we solve for b,
and substitute that value into our first equation
we can solve for a and then b, and we get
This means that 90 vanilla milkshakes were sold and 89 chocolate and strawberry milkshakes were sold. If there were 27 more chocolate milkshakes sold than strawberry, we can set up the equation where s represents the number of strawberry milkshakes sold, and s+27 represents the number of chocolate milkshakes sold. We can now solve for s.
Therefore, 31 strawberry milkshakes were sold.
Example Question #82 : Systems Of Equations
The product of two positive numbers is 77. One number is 3 less than twice the value of the other number. What is the sum of the two numbers?
In order to find the solution, you must set up a system of equations. We know that the product of two numbers, say x and y, is equal to 77.
Therefore, your first equation is
.
Next, we know that one number is 3 less than twice the value of the other number, or that
.
Once we have our two equations, we can use substitution in order to eliminate a variable and solve for the remaining variable.
We know that,
,
so instead of
we can say that (2y - 3) times y equals 77, or
.
To solve for y we need to factor.
becomes
.
Because y must be positive, we know that y must equal 7. Substituting 7 for y into our original equation (xy = 77), we learn that x equals 11.
Therefore and and the sum of our two numbers equals 18.
Example Question #83 : How To Find The Solution For A System Of Equations
Give the area of the triangle on the coordinate plane that is bounded by the lines of the equations , , and .
It is necessary to find the vertices of the triangle,each of which is the intersection of two lines.
The lines of the equations and can be immediately seen to intersect at .
The intersection of the lines of equations and can be found by substituting 1 for in the second equation and evaluating :
Their point of intersection is at .
Similarly, the intersection of the lines of equations and can be found by substituting for in the second equation and solving for :
Their point of intersection is at .
The lines in question are graphed below, and the triangle they bound is shaded:
The triangle is right, so its area is half the product of the lengths of its legs, which here are its vertical and horizontal sides. The length of its horizontal leg is the difference of the -coordinates of its endpoints:
The length of its vertical leg is the difference of the -coordinates of its endpoints:
Half the product of these is the area:
Example Question #2075 : Sat Mathematics
is a solution to the system of equations. What is the value of ?
Substitution
Solve the second equation for x:
Substitute this expression for x in the first equation:
Solve for y:
Substitute this value for y in any equation and solve for x.
Example Question #1 : Quadratic Equations
Solve: x2+6x+9=0
-3
9
12
6
3
-3
Given a quadratic equation equal to zero you can factor the equation and set each factor equal to zero. To factor you have to find two numbers that multiply to make 9 and add to make 6. The number is 3. So the factored form of the problem is (x+3)(x+3)=0. This statement is true only when x+3=0. Solving for x gives x=-3. Since this problem is multiple choice, you could also plug the given answers into the equation to see which one works.
Example Question #1 : How To Factor The Quadratic Equation
64x2 + 24x - 10 = 0
Solve for x
64x2 + 24x - 10 = 0
Factor the equation:
(8x + 5)(8x – 2) = 0
Set each side equal to zero
(8x + 5) = 0
x = -5/8
(8x – 2) = 0
x = 2/8 = 1/4