SAT Math : SAT Mathematics

Study concepts, example questions & explanations for SAT Math

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Example Questions

Example Question #1 : How To Find The Square Of An Integer

The square root of 5184 is:

Possible Answers:

71

74

70

72

73

Correct answer:

72

Explanation:

The easiest way to narrow down a square root from a list is to look at the last number on the squared number – in this case 4 – and compare it to the last number of the answer. 

70 * 70 will equal XXX0

71 * 71 will equal XXX1

72 * 72  will equal XXX4

73 * 73 will equal XXX9

74 * 74  will equal XXX(1)6

Therefore 72 is the answer.  Check by multiplying it out.

Example Question #1 : How To Find The Square Of An Integer

If 5^{x}+5^{x}+5^{x}+5^{x}+5^{x}=5^{10}, what is the value of x?

Possible Answers:

10

5

1

2

9

Correct answer:

9

Explanation:

5(5^{x})=5^{10}

5^{1}(5^{x})=5^{10}

5^{x+1}=5^{10}

x=9

Example Question #3 : How To Find The Square Of An Integer

If x and y are integers and xy + y2 is even, which of the following statements must be true?

I. 3y is odd

II. y/2 is an integer

III. xy is even

Possible Answers:

I & II 

I, II, & III

I only

II only

Correct answer:

Explanation:

In order for the original statement to be true, the  and  terms must be either both odd or both even. Looking at each of the statements individually,

I. States that  is odd, but only odd values multiplied by 3 are odd. If  was an even number, the result would be even. But can be either odd or even, depending on what equals. Thus this statement COULD be true but does not HAVE to be true.

II. States that  is an integer, and since only even numbers are cleanly divided by 2 (odd values result in a fraction) this ensures that  is even. However, can also be odd, so this is a statement that COULD be true but does not HAVE to be true.

III. For exponents, only the base value determines whether it is even or odd - it does not indicate the value of y at all. Only even numbers raised to any power are even, thus, this ensures that  is even. But can be odd as well, so this statement COULD be true but does not HAVE to be true.

An example of two integers that will work violate conditions II and III is and .

, and even number.

is not an integer.

is not even.

Furthermore, any combination of 2 even integers will make the original statement true, and violate the Statement I.

Example Question #1 : How To Find The Square Of An Integer

How many integers from 20 to 80, inclusive, are NOT the square of another integer?

Possible Answers:

Correct answer:

Explanation:

First list all the integers between 20 and 80 that are squares of another integer:

52 = 25

62 = 36

72 = 49

82 = 64

In total, there are 61 integers from 20 to 80, inclusive. 61 – 4 = 57

Example Question #1044 : Sat Mathematics

Consider the inequality:

Which of the following could be a value of ?

Possible Answers:

There is no possible value for x

x=1

x=-\frac{3}{4}

x=-\frac{4}{3}

x=-1

Correct answer:

x=-\frac{3}{4}

Explanation:

Notice how x^4 is the greatest value. This often means that x is negative as (-1)^n=-1 when \dpi{100} n is odd and (-1)^n=1 when \dpi{100} n is even.

Let us examine the first choice, x=-\frac{3}{4}

x^5=-\frac{3^5}{4^5}=-\frac{243}{1024}> -\frac{3}{4}

This can only be true of a negative value that lies between zero and one.

Example Question #5 : How To Find The Square Of An Integer

Solve each problem and decide which is the best of the choices given.

Solve for .

Possible Answers:

Correct answer:

Explanation:

To solve for  you have to get all the 's on one side and all the numbers on the other side.

Combine like terms, and the result is 

.

Divide by  on both sides to get 

.

Finally take the square root of both sides to get .

Example Question #2 : How To Find The Square Of An Integer

Give the positive solution of the question.

Possible Answers:

Correct answer:

Explanation:

This question is testing one's ability to analyze a function algebraically and recognize different but equivalent forms. Identifying properties of functions through analyzing equivalent forms is critical to this concept. Such properties that can be found through analyzing the different forms of a function include finding roots (zeros), extreme values, symmetry, and intercepts.

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Recognize the general form of the function.

This is known as the difference of squares.

Step 2: Identify what is known.

Step 3: Substitute the known values into the difference of perfect squares found in step 1.

Step 4: Answer the question.

To find the positive solution set each binomial equal to zero and solve for x.

    

Therefore the positive solution is four.

 

Example Question #217 : New Sat

If the following are true, solve for .

 

Possible Answers:

Correct answer:

Explanation:

Given the two equations, substitute the numerical value of  into the second equation to solve for 

Substituting the numerical value for  into the equation with  is as follows.

From here, distribute the three.

Now square both side of the equation.

Remember to square both terms within the parentheses. Also, recall that squaring a square root sign cancels them out.

To solve for  divide both sides by six.

Example Question #1 : Fractions And Percentage

Write as a fraction: 22%

Possible Answers:

4/9

4/7

11/50

2/3

11/100

Correct answer:

11/50

Explanation:

22% = 22/100

Divide everything by 2:

22/100 = 11/50

11 is a prime number, so this is as reduced as this fraction can get.

Example Question #1 : Percentage

When y is decreased by ten percent, the result is equal to fifteen percent of x. Assuming both x and y are nonzero, what is the ratio of x to y?

Possible Answers:

3

18

1/3

1/6

6

Correct answer:

6

Explanation:

The problem states that decreasing y by ten percent gives us the same thing as taking fifteen percent of x. We need to find an expression for decreasing y by ten percent, and an expression for fifteen percent of x, and then set these two things equal.

If we were to decrease y by ten percent, we would be left with ninety percent of y (because the percentages must add to one hundred percent). We could write ninety percent of y as 0.90y = (90/100)y = (9/10)y. Remember, when converting from a percent to a decimal, we need to move the decimal two places to the left.

Similarly, we can write 15% of x as 0.15x = (15/100)x = (3/20)x.

Now, we set these two expressions equal to one another.

(9/10)y = (3/20)x

Multiply both sides by 20 to eliminate fractions.

18y = 3x

The question asks us to find the ratio of x to y, which is equal to x/y. Thus, we must rearrange the equation above until we have x/y by itself on one side.

18y = 3x

Divide both sides by 3.

6y = x

Divide both sides by y.

6 = x/y

Thus, the ratio of x to y is 6.

The answer is 6.

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