SAT Math : Rhombuses
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Example Question #11 : How To Find The Area Of A Rhombus
A rhombus has a side length of 5. Which of the following is NOT a possible value for its area?
25
24
30
10
15
30
The area of a rhombus will vary as the angles made by its sides change. The "flatter" the rhombus is (with two very small angles and two very large angles, say 2, 178, 2, and 178 degrees), the smaller the area is. There is, of course, a lower bound of zero for the area, but the area can get arbitrarily small. This implies that the correct answer would be the largest choice. In fact, the largest area of a rhombus occurs when all four angles are equal, i.e. when the rhombus is a square. The area of a square of side length 5 is 25, so any value bigger than 25 is impossible to acheive.
Example Question #1 : Quadrilaterals
If the area of a rhombus is 24 and one diagonal length is 6, find the perimeter of the rhombus.
24
12
8
16
20
20
The area of a rhombus is found by
A = 1/2(d1)(d2)
where d1 and d2 are the lengths of the diagonals. Substituting for the given values yields
24 = 1/2(d1)(6)
24 = 3(d1)
8 = d1
Now, use the facts that diagonals are perpendicular in a rhombus, diagonals bisect each other in a rhombus, and the Pythagorean Theorem to determine that the two diagonals form 4 right triangles with leg lengths of 3 and 4. Since 32 + 42 = 52, each side length is 5, so the perimeter is 5(4) = 20.
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