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SAT Math : How to find f(x)

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Example Questions

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Example Question #281 : Algebra

If f(x) = 4x + 2(x+1) , then f(8x) =?

Possible Answers:

48x + 2

32x + 1

16x + 4

48x + 8

Correct answer:

48x + 2

Explanation:

f(x) = 4x + 2(x+1) ,

f(8x) = 4(8x) + 2(8x+1) = 32x + 16x + 2 = 48x + 2

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Example Question #162 : How To Find F(X)

Define two functions as follows:

f(x) = 4x- 17

$g(x) = \frac{1}{2}x+ 13$

Evaluate $(g \circ f ) (10)$ .

Possible Answers:

$-12 \frac{1}{2}$

$24 \frac{1}{2}$

$\textup{None of the other choices gives the correct response}$

$2 \frac{3}{4}$

Correct answer:

$24 \frac{1}{2}$

Explanation:

By definition, $(g \circ f ) (10) = g [f(10)]$ .

First, evaluate f(10) by setting x = 10 in the definition of f(x) :

f(x) = 4x- 17

$f(10) = 4 \cdot 10 - 17= 40 - 17 = 23$

$(g \circ f ) (10) = g [f(10)] = g(23)$ , so evaluate g(23) similarly:

$g(x) = \frac{1}{2}x+ 13$

$g(23 ) = \frac{1}{2} \cdot 23 + 13 = 11 \frac{1}{2} + 13 = 24 \frac{1}{2}$

$(g \circ f ) (10) = 24 \frac{1}{2}$

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Example Question #161 : How To Find F(X)

Define $f(x) = \sqrt{2x+ 3}$ , restricting the domain of the function to the interval [11, 39 ] .

Give the range of the function.

Possible Answers:

[-9, 9 ]

$(-\infty, \infty )$

None of these

$[-9, -5 ] \cup [5, 9 ]$

[5, 9 ]

Correct answer:

[5, 9 ]

Explanation:

If $11 \le x \le 39$ , then, by way of the properties of inequality, we can multiply all expressions by 2:

$2 \cdot 11 \le 2 \cdot x \le 2 \cdot 39$

$22 \le 2 x \le 78$

then add 3 to all expressions:

$22+ 3 \le 2 x+ 3 \le 78 + 3$

$25 \le 2 x+ 3 \le 81$

Taking the square root of all expressions, we get

$\sqrt{25 }\le \sqrt{2 x+ 3} \le \sqrt{81}$

$5 \le \sqrt{2 x+ 3} \le 9$

$5 \le f(x) \le 9$ .

The correct range is [5, 9 ] .

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Example Question #164 : How To Find F(X)

Define two functions as follows:

f(x) = 4x- 17

$g(x) = \frac{1}{2}x+ 13$

Evaluate:

$(f \circ g ) (10)$

Possible Answers:

$-12 \frac{1}{2}$

$2 \frac{3}{4}$

None of these

$24 \frac{1}{2}$

Correct answer:

Explanation:

By definition, $(f \circ g ) (10) = f [g(10)]$ .

First, evaluate g(10) by setting x = 10 in the definition of g(x) :

$g(x) = \frac{1}{2}x+ 13$

$g(10) = \frac{1}{2} \cdot 10 + 13 = 5 + 13 = 18$

$(f \circ g ) (10) = f [g(10)] = f(18)$ , so evaluate f(18) similarly:

f(x) = 4x- 17

$f(18) = 4 \cdot 18 - 17= 72 - 17 = 55$

$(f \circ g ) (10) = 55$

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Example Question #31 : How To Find F(X)

The function is defined as f(x) = 3x^2 + 6x + 27 . What is f(-1) ?

Possible Answers:

-36

Correct answer:

Explanation:

Substitute -1 for in the given function.

$f(-1)=3(-1)^{2}+6(-1)+27$

f(-1)=3(1)-6+27

f(-1)=3-6+27

f(-1)=24

If you didn’t remember the negative sign, you will have calculated 36. If you remembered the negative sign at the very last step, you will have calculated -36; however, if you did not remember that (-1)^2 is 1, then you will have calculated 18.

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Example Question #441 : Algebra

If the function h(x) is created by shifting f(x) up four units and then reflecting it across the x-axis, which of the following represents h(x) in terms of f(x) ?

Possible Answers:

f(x)+4

f(x-4)

-f(x+4)

f(x+4)

-f(x)-4

Correct answer:

-f(x)-4

Explanation:

We can take each of the listed transformations of f(x) one at a time. If f(x) is to be shifted up by four units, increase every value of f(x) by 4.

$f(x)_{\textup{shifted up by 4}}=f(x)+4$

Next, take this equation and reflect it across the x-axis. If we reflect a function across the x-axis, then all of its values will be multiplied by negative one. So, h(x) can be written in the following way:

h(x)=-(f(x)+4)

Lastly, distribute the negative sign to arrive at the final answer.

h(x)=-f(x)-4

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SAT Math : How to find f(x)

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #281 : Algebra

Example Question #162 : How To Find F(X)

Example Question #161 : How To Find F(X)

Example Question #164 : How To Find F(X)

Example Question #31 : How To Find F(X)

Example Question #441 : Algebra

All SAT Math Resources

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