SAT Math : Solid Geometry

Study concepts, example questions & explanations for SAT Math

varsity tutors app store varsity tutors android store varsity tutors ibooks store

Example Questions

Example Question #1 : How To Find The Volume Of A Cylinder

What is the volume of a right cylinder with a circumference of 25π in and a height of 41.3 in?

Possible Answers:

3831.34π in3

4813.33π in3

25812.5π in3

6453.125π in3

1032.5π in3

Correct answer:

6453.125π in3

Explanation:

The formula for the volume of a right cylinder is: V = A * h, where A is the area of the base, or πr2.  Therefore, the total formula for the volume of the cylinder is: V = πr2h.

 First, we must solve for r by using the formula for a circumference (c = 2πr): 25π = 2πr; r = 12.5.

Based on this, we know that the volume of our cylinder must be: π*12.52*41.3 = 6453.125π in3

Example Question #121 : Solid Geometry

An 8-inch cube has a cylinder drilled out of it. The cylinder has a radius of 2.5 inches. To the nearest hundredth, approximately what is the remaining volume of the cube?

Possible Answers:

462 in3

157.08 in3

391.33 in3

203.34 in3

354.92 in3

Correct answer:

354.92 in3

Explanation:

We must calculate our two volumes and subtract them. The volume of the cube is very simple: 8 * 8 * 8, or 512 in3.

The volume of the cylinder is calculated by multiplying the area of its base by its height. The height of the cylinder is 8 inches (the height of the cube through which it is being drilled). Therefore, its volume is πr2h = π * 2.5* 8 = 50π in3

The volume remaining in the cube after the drilling is: 512 – 50π, or approximately 512 – 157.0795 = 354.9205, or 354.92 in3.

Example Question #1 : How To Find The Volume Of A Cylinder

An 12-inch cube of wood has a cylinder drilled out of it. The cylinder has a radius of 3.75 inches. If the density of the wood is 4 g/in3, what is the mass of the remaining wood after the cylinder is drilled out?

Possible Answers:

4791.43 g

4921.4 g

2594.11 g

3813.3 g

3193.33 g

Correct answer:

4791.43 g

Explanation:

We must calculate our two volumes and subtract them. Following this, we will multiply by the density.

The volume of the cube is very simple: 12 * 12 * 12, or 1728 in3.

The volume of the cylinder is calculated by multiplying the area of its base by its height. The height of the cylinder is 8 inches (the height of the cube through which it is being drilled). Therefore, its volume is πr2h = π * 3.75* 12 = 168.75π in3.

The volume remaining in the cube after the drilling is: 1728 – 168.75π, or approximately 1728 – 530.1433125 = 1197.8566875 in3. Now, multiply this by 4 to get the mass: (approx.) 4791.43 g.

Example Question #1 : How To Find The Volume Of A Cylinder

A hollow prism has a base 5 in x 6 in and a height of 10 in. A closed, cylindrical can is placed in the prism. The remainder of the prism is then filled with gel around the cylinder. The thickness of the can is negligible. Its diameter is 4 in and its height is half that of the prism. What is the approximate volume of gel needed to fill the prism?

Possible Answers:

187.73 in3

203.44 in3

237.17 in3

249.73 in3

103.33 in3

Correct answer:

237.17 in3

Explanation:

The general form of our problem is:

Gel volume = Prism volume – Can volume

The prism volume is simple: 5 * 6 * 10 = 300 in3

The volume of the can is found by multiplying the area of the circular base by the height of the can. The height is half the prism height, or 10/2 = 5 in. The area of the base is equal to πr2. Note that the prompt has given the diameter. Therefore, the radius is 2, not 4. The base's area is: 22π = 4π. The total volume is therefore: 4π * 5 = 20π in3.

The gel volume is therefore: 300 – 20π or (approx.) 237.17 in3.

Example Question #2 : How To Find The Volume Of A Cylinder

A hollow prism has a base 12 in x 13 in and a height of 42 in. A closed, cylindrical can is placed in the prism. The remainder of the prism is then filled with gel, surrounding the can. The thickness of the can is negligible. Its diameter is 9 in and its height is one-fourth that of the prism. The can has a mass of 1.5 g per in3, and the gel has a mass of 2.2 g per in3. What is the approximate overall mass of the contents of the prism?

Possible Answers:

139.44 g

973.44 g

11.48 kg

13.95 kg

15.22 kg

Correct answer:

13.95 kg

Explanation:

We must find both the can volume and the gel volume. The formula for the gel volume is:

Gel volume = Prism volume – Can volume

The prism volume is simple: 12 * 13 * 42 = 6552 in3

The volume of the can is found by multiplying the area of the circular base by the height of the can. The height is one-fourth the prism height, or 42/4 = 10.5 in. The area of the base is equal to πr2. Note that the prompt has given the diameter. Therefore, the radius is 4.5, not 9. The base's area is: 4.52π = 20.25π. The total volume is therefore: 20.25π * 10.5 = 212.625π in3.

The gel volume is therefore: 6552 – 212.625π or (approx.) 5884.02 in3.

The approximate volume for the can is: 667.98 in3

From this, we can calculate the approximate mass of the contents:

Gel Mass = Gel Volume * 2.2 = 5884.02 * 2.2 = 12944.844 g

Can Mass = Can Volume * 1.5 = 667.98 * 1.5 = 1001.97 g

The total mass is therefore 12944.844 + 1001.97 = 13946.814 g, or approximately 13.95 kg.

Example Question #11 : How To Find The Volume Of A Cylinder

A vase needs to be filled with water.  If the vase is a cylinder that is \dpi{100} \small 12{}'' tall with a \dpi{100} \small 2{}'' radius, how much water is needed to fill the vase?

Possible Answers:

\dpi{100} \small 48\pi

\dpi{100} \small 12\pi

\dpi{100} \small 96\pi

\dpi{100} \small 64\pi

\dpi{100} \small 24\pi

Correct answer:

\dpi{100} \small 48\pi

Explanation:

Cylinder

\dpi{100} \small V = \pi r^{2}h

\dpi{100} \small V = \pi (2)^{2}\times 12

\dpi{100} \small V = 4\times 12\pi

\dpi{100} \small V = 48\pi

Example Question #21 : Cylinders

A cylinder has a base diameter of 12 in and is 2 in tall. What is the volume?

Possible Answers:

Correct answer:

Explanation:

The volume of a cylinder is

The diameter is given, so make sure to divide it in half.

The units are inches cubed in this example

Example Question #21 : Cylinders

What is the volume of a cylinder with a radius of 4 and a height of 5?

Possible Answers:

72\pi

60\pi

54\pi

80\pi

40\pi

Correct answer:

80\pi

Explanation:

volume = \pi r^{2}h = \pi \cdot 4^{2} \cdot 5 = 80\pi

Example Question #12 : How To Find The Volume Of A Cylinder

Claire's cylindrical water bottle is 9 inches tall and has a diameter of 6 inches. How many cubic inches of water will her bottle hold?

Possible Answers:

Correct answer:

Explanation:

The volume is the area of the base times the height. The area of the base is , and the radius here is 3.  

Example Question #13 : Cylinders

What is the volume of a circular cylinder whose height is 8 cm and has a diameter of 4 cm?

Possible Answers:

Correct answer:

Explanation:

The volume of a circular cylinder is given by  V = \pi r^{2}h where  is the radius and  is the height.  The diameter is given as 4 cm, so the radius would be 2 cm as the diameter is twice the radius.

Learning Tools by Varsity Tutors