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Example Questions
Example Question #1 : How To Find The Volume Of A Cylinder
What is the volume of a right cylinder with a circumference of 25π in and a height of 41.3 in?
3831.34π in3
4813.33π in3
25812.5π in3
6453.125π in3
1032.5π in3
6453.125π in3
The formula for the volume of a right cylinder is: V = A * h, where A is the area of the base, or πr2. Therefore, the total formula for the volume of the cylinder is: V = πr2h.
First, we must solve for r by using the formula for a circumference (c = 2πr): 25π = 2πr; r = 12.5.
Based on this, we know that the volume of our cylinder must be: π*12.52*41.3 = 6453.125π in3
Example Question #121 : Solid Geometry
An 8-inch cube has a cylinder drilled out of it. The cylinder has a radius of 2.5 inches. To the nearest hundredth, approximately what is the remaining volume of the cube?
462 in3
157.08 in3
391.33 in3
203.34 in3
354.92 in3
354.92 in3
We must calculate our two volumes and subtract them. The volume of the cube is very simple: 8 * 8 * 8, or 512 in3.
The volume of the cylinder is calculated by multiplying the area of its base by its height. The height of the cylinder is 8 inches (the height of the cube through which it is being drilled). Therefore, its volume is πr2h = π * 2.52 * 8 = 50π in3
The volume remaining in the cube after the drilling is: 512 – 50π, or approximately 512 – 157.0795 = 354.9205, or 354.92 in3.
Example Question #1 : How To Find The Volume Of A Cylinder
An 12-inch cube of wood has a cylinder drilled out of it. The cylinder has a radius of 3.75 inches. If the density of the wood is 4 g/in3, what is the mass of the remaining wood after the cylinder is drilled out?
4791.43 g
4921.4 g
2594.11 g
3813.3 g
3193.33 g
4791.43 g
We must calculate our two volumes and subtract them. Following this, we will multiply by the density.
The volume of the cube is very simple: 12 * 12 * 12, or 1728 in3.
The volume of the cylinder is calculated by multiplying the area of its base by its height. The height of the cylinder is 8 inches (the height of the cube through which it is being drilled). Therefore, its volume is πr2h = π * 3.752 * 12 = 168.75π in3.
The volume remaining in the cube after the drilling is: 1728 – 168.75π, or approximately 1728 – 530.1433125 = 1197.8566875 in3. Now, multiply this by 4 to get the mass: (approx.) 4791.43 g.
Example Question #1 : How To Find The Volume Of A Cylinder
A hollow prism has a base 5 in x 6 in and a height of 10 in. A closed, cylindrical can is placed in the prism. The remainder of the prism is then filled with gel around the cylinder. The thickness of the can is negligible. Its diameter is 4 in and its height is half that of the prism. What is the approximate volume of gel needed to fill the prism?
187.73 in3
203.44 in3
237.17 in3
249.73 in3
103.33 in3
237.17 in3
The general form of our problem is:
Gel volume = Prism volume – Can volume
The prism volume is simple: 5 * 6 * 10 = 300 in3
The volume of the can is found by multiplying the area of the circular base by the height of the can. The height is half the prism height, or 10/2 = 5 in. The area of the base is equal to πr2. Note that the prompt has given the diameter. Therefore, the radius is 2, not 4. The base's area is: 22π = 4π. The total volume is therefore: 4π * 5 = 20π in3.
The gel volume is therefore: 300 – 20π or (approx.) 237.17 in3.
Example Question #2 : How To Find The Volume Of A Cylinder
A hollow prism has a base 12 in x 13 in and a height of 42 in. A closed, cylindrical can is placed in the prism. The remainder of the prism is then filled with gel, surrounding the can. The thickness of the can is negligible. Its diameter is 9 in and its height is one-fourth that of the prism. The can has a mass of 1.5 g per in3, and the gel has a mass of 2.2 g per in3. What is the approximate overall mass of the contents of the prism?
139.44 g
973.44 g
11.48 kg
13.95 kg
15.22 kg
13.95 kg
We must find both the can volume and the gel volume. The formula for the gel volume is:
Gel volume = Prism volume – Can volume
The prism volume is simple: 12 * 13 * 42 = 6552 in3
The volume of the can is found by multiplying the area of the circular base by the height of the can. The height is one-fourth the prism height, or 42/4 = 10.5 in. The area of the base is equal to πr2. Note that the prompt has given the diameter. Therefore, the radius is 4.5, not 9. The base's area is: 4.52π = 20.25π. The total volume is therefore: 20.25π * 10.5 = 212.625π in3.
The gel volume is therefore: 6552 – 212.625π or (approx.) 5884.02 in3.
The approximate volume for the can is: 667.98 in3
From this, we can calculate the approximate mass of the contents:
Gel Mass = Gel Volume * 2.2 = 5884.02 * 2.2 = 12944.844 g
Can Mass = Can Volume * 1.5 = 667.98 * 1.5 = 1001.97 g
The total mass is therefore 12944.844 + 1001.97 = 13946.814 g, or approximately 13.95 kg.
Example Question #11 : How To Find The Volume Of A Cylinder
A vase needs to be filled with water. If the vase is a cylinder that is tall with a radius, how much water is needed to fill the vase?
Cylinder
Example Question #21 : Cylinders
A cylinder has a base diameter of 12 in and is 2 in tall. What is the volume?
The volume of a cylinder is
The diameter is given, so make sure to divide it in half.
The units are inches cubed in this example
Example Question #21 : Cylinders
What is the volume of a cylinder with a radius of 4 and a height of 5?
Example Question #12 : How To Find The Volume Of A Cylinder
Claire's cylindrical water bottle is 9 inches tall and has a diameter of 6 inches. How many cubic inches of water will her bottle hold?
The volume is the area of the base times the height. The area of the base is , and the radius here is 3.
Example Question #13 : Cylinders
What is the volume of a circular cylinder whose height is 8 cm and has a diameter of 4 cm?
The volume of a circular cylinder is given by where is the radius and is the height. The diameter is given as 4 cm, so the radius would be 2 cm as the diameter is twice the radius.
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