PSAT Math : Algebraic Functions

Study concepts, example questions & explanations for PSAT Math

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Example Questions

Example Question #336 : Algebra

If  is an odd integer, and  is an even integer, which of the following must be even?

Possible Answers:

Correct answer:

Explanation:

Solve this problem using picked numbers. Choose an odd number to represent  and an even number to represent . In this case, we have chosen 3 to represent  and 2 to represent .

Substitute into each equation to find the correct answer:

This number is even, and likely the answer we are looking for. Just in case, quickly check the other answers to make sure no others come out even.

This expression gives an odd answer and must be incorrect.

This expression gives an odd answer and must be incorrect.

This expression gives an odd answer and must be incorrect.

This expression gives an odd answer and must be incorrect.

 

Only the first answer is even. The answer is .

Example Question #72 : Algebraic Functions

If  

What is ?

Possible Answers:

Correct answer:

Explanation:

To find f(4), input a 4 in every place you see an x in the equation. That gives you

When you simplify this expression, you get 

When you add together each part, you get

Example Question #16 : Algebraic Functions

What is the value of the function f(x) = 6x+ 16x – 6 when x = –3?

Possible Answers:

–12

96

–108

0

Correct answer:

0

Explanation:

There are two ways to do this problem. The first way just involves plugging in –3 for x and solving 6〖(–3)〗+ 16(–3) – 6, which equals 54 – 48 – 6 = 0. The second way involves factoring the polynomial to (6x – 2)(x + 3) and then plugging in –3 for x. The second way quickly shows that the answer is 0 due to multiplying by (–3 + 3).

Example Question #17 : Algebraic Functions

Given the functions f(x) = 2x + 4 and g(x) = 3x – 6, what is f(g(x)) when = 6?

Possible Answers:

12

144

16

28

192

Correct answer:

28

Explanation:

We need to work from the inside to the outside, so g(6) = 3(6) – 6 = 12.

Then f(g(6)) = 2(12) + 4 = 28.

Example Question #71 : Algebraic Functions

A function f(x) = –1 for all values of x. Another function g(x) = 3x for all values of x. What is g(f(x)) when x = 4?

Possible Answers:

–3

3

–12

12

–1

Correct answer:

–3

Explanation:

We work from the inside out, so we start with the function f(x). f(4) = –1. Then we plug that value into g(x), so g(f(x)) = 3 * (–1) = –3.

Example Question #19 : Algebraic Functions

What is f(–3) if f(x) = x2 + 5?

Possible Answers:

15

14

–4

4

–14

Correct answer:

14

Explanation:

f(–3) = (–3)2 + 5 = 9 + 5 = 14

Example Question #21 : Algebraic Functions

For all values of x, f(x) = 7x2 – 3, and for all values of y, g(y) = 2y + 9. What is g(f(x))?

Possible Answers:

14y2 + 3

14x2 + 3

14x2 – 3

2x + 9

7y2 – 3

Correct answer:

14x2 + 3

Explanation:

The inner function f(x) is like our y-value that we plug into g(y).

g(f(x)) = 2(7x2 – 3) + 9 = 14x2 – 6 + 9 = 14x2 + 3.

Example Question #35 : Algebraic Functions

Find

Possible Answers:

Correct answer:

Explanation:

Simply plug 6 into the equation and don't forget the absolute value at the end.

absolute value = 67

Example Question #72 : Algebraic Functions

An outpost has the supplies to last 2 people for 14 days. How many days will the supplies last for 7 people?

Possible Answers:

\dpi{100} \small 9

\dpi{100} \small 10

\dpi{100} \small 7

\dpi{100} \small 5

\dpi{100} \small 4

Correct answer:

\dpi{100} \small 4

Explanation:

Supplies are used at the rate of \dpi{100} \small \frac{Supplies}{Days\times People}.

Since the total amount of supplies is the same in either case, \dpi{100} \small \frac{1}{14\times 2}=\frac{1}{7\times \ (\&hash;\ of\ days)}.

Solve for days to find that the supplies will last for 4 days.

Example Question #73 : Algebraic Functions

Worker \dpi{100} \small A can make a trinket in 4 hours, Worker \dpi{100} \small B can make a trinket in 2 hours. When they work together, how long will it take them to make a trinket?

Possible Answers:

\dpi{100} \small 3\ hours

\dpi{100} \small \ 1 \frac{1}{2}\ hours

\dpi{100} \small \frac{1}{2}\ hour

\dpi{100} \small 6\ hours

\dpi{100} \small \ 1 \frac{1}{3}\ hours

Correct answer:

\dpi{100} \small \ 1 \frac{1}{3}\ hours

Explanation:

The rates are what needs to be added. Rate \dpi{100} \small A is \dpi{100} \small \frac{1}{4}, or one trinket every 4 hours. Rate \dpi{100} \small B is \dpi{100} \small \frac{1}{2}, one per two hours.

\dpi{100} \small \frac{1}{4}+ \frac{1}{2}=\frac{3}{4}, their combined rate in trinkets per hour.

Now invert the equation to get back to hours per trinket, which is what the question asks for: \dpi{100} \small \frac{4}{3}\ or \ 1 \frac{1}{3}

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